For the given circuit, at steady state, the Ampere Maxwell Law can be modified to:

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For the given circuit, at steady state, the Ampere Maxwell Law can be modified to

We know that Ampere Maxwell Law is given by,

∮→B.→dl=μ0(ic+id)=μ0(ic+ϵ0dϕEdt)

For the given circuit, at a steady state, the capacitor act as an open switch, therefore conduction current is zero.

Also, the electric field between the plates of the capacitor is constant at a steady state, which means the electric flux is constant. Therefore, the displacement current is also zero.

So, the Ampere Maxwell Law will be ∮→B.→dl=0.

Also check:

CBSE CLASS XII Related Questions

  • 1.
    A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

      • 5 V
      • 3.5 V
      • 2.5 V
      • Zero V

    • 2.
      Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

        • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
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        • Assertion (A) is true, but Reason (R) is false.
        • Both Assertion (A) and Reason (R) are false.

      • 3.
        Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

          • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
          • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
          • Assertion (A) is true, but Reason (R) is false.
          • Both Assertion (A) and Reason (R) are false.

        • 4.
          Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.


            • 5.
              Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

                • (i) and (iii) only
                • (iii) and (iv) only
                • (i), (iii) and (iv) only
                • All of them

              • 6.
                Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –

                  • \((P_1+P_2)\)
                  • \(\dfrac{P_1+P_2}{2}\)
                  • \(\dfrac{P_1P_2}{2(P_1+P_2)}\)
                  • \(\dfrac{P_1P_2}{4(P_1+P_2)}\)
                CBSE CLASS XII Previous Year Papers

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