NCERT Solutions For Class 12 Physics Chapter 4: Moving Charges and Magnetism

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NCERT Solutions for Class 12 Physics Chapter 4 Moving Charges and Magnetism are provided in this article. Moving charges generate an electric field. The rate of flow of electric charge is known as current. Magnetism is caused due to the current. Magnetic fields exert forces on the magnets and the moving charges.  

Class 12 Physics Chapter 4 along with Chapter 5 Magnetism and Matter belongs to Unit 3 which has a weightage of 17 marks with Unit 4 Electromagnetic Induction and Alternating Currents. Along with the elementary concepts, mathematical treatment of the magnetic field produced due to a current element (Biot Savart Law), ampere’s circuital law and the concept of solenoid and toroids are covered in the Class 12 NCERT Solutions for NCERT Solutions for Class 12 Physics Chapter 4. 

Download PDF: NCERT Solutions for Class 12 Physics Chapter 4


NCERT Solutions for Class 12 Physics Chapter 4

The NCERT solutions for class 12 physics chapter 4: Moving Charges and Magnetism are provided below. 

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS


Class 12 Physics Chapter 4 – Important Concepts

  • The region in space where a Magnet has its magnetic effect is known as the Magnetic field of the Magnet.
F = q [E(r) + v × B(r)] = EElectric + Fmagnetic 
  • Magnetism is a property displayed by Magnets and produced by the moving charges. This results in the objects being attracted or pushed away.
The relation between a moving charge and magnetism is that Magnetism is caused due to the movement of charges.
  • Lorentz Force is the total force on a given charge c, moving with a velocity v, in the presence of electric field E and magnetic field B. (This force acts normal to v and the work done by it is zero)

F = q(v x B + E)

  • Magnetic Force on a Current-Carrying Conductor: Due to the motion of charges in a conductor, each charge experiences a force. When current is passed through a magnetic field, the magnetic field exerts a force on the wire in a perpendicular direction to the current and the magnetic field as well.

 \(F= I (I \times B ) or |F | = I |I||B| sin \theta \)


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CBSE CLASS XII Related Questions

  • 1.
    Capacitors are manufactured with certain standard capacitances and working voltages. However, these standard values may not be the ones that are actually needed in a particular application. Two or more capacitors can be grouped in series or in parallel to achieve desired capacitance and voltage. When connected in series, the total capacitance decreases while the voltage rating increases, whereas in parallel connections, the total capacitance increases and maintains the same voltage rating. A capacitor stores energy in the electric field between its plates and stored energy is proportional to the square of the voltage and capacitance $U = \frac{1}{2}CV^2$, where symbols have their usual meanings.
    Two capacitors, one of $3 \ \mu$F and the other of $6 \ \mu$F, are connected in series in the circuit as shown in the figure, for a long time. }


      • 2.
        The resistance of a metal wire at \( 20^\circ \text{C} \) is \( 1.05 \, \Omega \) and at \( 100^\circ \text{C} \) is \( 1.38 \, \Omega \). Determine the temperature coefficient of resistivity of this metal.


          • 3.
            An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.


              • 4.
                Read the following paragraph and answer the questions that follow.
                A p-type or n-type semiconductor can be converted into a p-n junction by doping it with suitable impurity. The motion of majority charge carriers causes diffusion current across the junction while the barrier electric field causes motion of minority carriers for drift current. In case of unbiased diode, the diffusion and drift currents are equal. This equilibrium is disturbed by the biasing batteries. Diodes, therefore, allow currents in one direction. This property of diode is used in making rectifiers.


                  • 5.
                    Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

                      • \( (M_x - M_z)<M_y \)
                      • \( (M_x - M_y)<M_z \)
                      • \( M_x>(M_y + M_z) \)
                      • \( M_x<(M_y + M_z) \)

                    • 6.
                      Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.

                        CBSE CLASS XII Previous Year Papers

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