NCERT Solutions For Class 12 Physics Chapter 4: Moving Charges and Magnetism

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Jasmine Grover

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NCERT Solutions for Class 12 Physics Chapter 4 Moving Charges and Magnetism are provided in this article. Moving charges generate an electric field. The rate of flow of electric charge is known as current. Magnetism is caused due to the current. Magnetic fields exert forces on the magnets and the moving charges.  

Class 12 Physics Chapter 4 along with Chapter 5 Magnetism and Matter belongs to Unit 3 which has a weightage of 17 marks with Unit 4 Electromagnetic Induction and Alternating Currents. Along with the elementary concepts, mathematical treatment of the magnetic field produced due to a current element (Biot Savart Law), ampere’s circuital law and the concept of solenoid and toroids are covered in the Class 12 NCERT Solutions for NCERT Solutions for Class 12 Physics Chapter 4. 

Download PDF: NCERT Solutions for Class 12 Physics Chapter 4


NCERT Solutions for Class 12 Physics Chapter 4

The NCERT solutions for class 12 physics chapter 4: Moving Charges and Magnetism are provided below. 

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS

NCERT SOLUTIONS


Class 12 Physics Chapter 4 – Important Concepts

  • The region in space where a Magnet has its magnetic effect is known as the Magnetic field of the Magnet.
F = q [E(r) + v × B(r)] = EElectric + Fmagnetic 
  • Magnetism is a property displayed by Magnets and produced by the moving charges. This results in the objects being attracted or pushed away.
The relation between a moving charge and magnetism is that Magnetism is caused due to the movement of charges.
  • Lorentz Force is the total force on a given charge c, moving with a velocity v, in the presence of electric field E and magnetic field B. (This force acts normal to v and the work done by it is zero)

F = q(v x B + E)

  • Magnetic Force on a Current-Carrying Conductor: Due to the motion of charges in a conductor, each charge experiences a force. When current is passed through a magnetic field, the magnetic field exerts a force on the wire in a perpendicular direction to the current and the magnetic field as well.

 \(F= I (I \times B ) or |F | = I |I||B| sin \theta \)


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CBSE CLASS XII Related Questions

  • 1.
    Consider a cylindrical conductor of length \( l \) and area of cross-section \( A \). Current \( I \) is maintained in the conductor and electrons drift with velocity \( \vec{v}_d \, (|\vec{v}_d| = \frac{eE}{m} \tau) \), where symbols have their usual meanings. Show that the conductivity of the material of the conductor is given by \[ \sigma = \frac{n e^2 \tau}{m}. \]


      • 2.
        Read the following paragraph and answer the questions that follow.
        In an experiment with convex lens of focal length f, the screen is fixed at a distance D from the object. A student slowly moves the lens away from the object towards the screen and finds that she is able to form sharp image of the object for two positions of the lens. The distance between these two positions of the lens is d.


          • 3.
            Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

              • \( (M_x - M_z)<M_y \)
              • \( (M_x - M_y)<M_z \)
              • \( M_x>(M_y + M_z) \)
              • \( M_x<(M_y + M_z) \)

            • 4.
              A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.


                • 5.
                  Write two advantages of reflecting telescope over refracting telescope.


                    • 6.
                      An electric field $\vec{E}$ is established across the ends of a cylindrical conductor of length L and area of cross-section A. Discuss how electrons attain an average velocity, independent of time. Hence, obtain a relation between current in the conductor and this ‘average velocity’ of electrons.

                        CBSE CLASS XII Previous Year Papers

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