Define gravitational flux in analogy to electric flux. How does gravitational flux differ from electric flux?

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Jasmine Grover

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Gravitational flux is a measure of the amount of gravitational field passing through a given area, just as electric flux is a measure of the amount of electric field passing through a given area. It is similar to electric flux in that it is a measure of the strength of the field at a point, and is calculated by taking the dot product of the field vector and the area vector.

However, gravitational flux differs from the electric flux in a few key ways.

  • Firstly, while electric fields can be both positive and negative, gravitational fields are always attractive, meaning that they are always directed towards the source of the field.
  • This means that the gravitational flux through a closed surface is always negative, while the electric flux can be either positive or negative.
  • Another key difference is that while electric fields are generated by charges, gravitational fields are generated by masses.
  • This means that the gravitational flux through a given area is dependent on the mass of the object generating the field, as well as the distance between the object and the area.

Gravitational Flux = \(\overrightarrow{g}.\overrightarrow{A}\)

Electric flux = \(\overrightarrow{E}.\overrightarrow{A}\)

Magnetic flux\(\overrightarrow{B}.\overrightarrow{A}\)

Both gravitational flux and electric flux have similar formulas. They are measures of the strength of a field passing through a given area. Gravitational flux is always negative and depends on the mass of the object generating the field. The electric flux can be positive or negative and depends on the charges generating the field.

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CBSE CLASS XII Related Questions

  • 1.
    The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

      • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
      • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
      • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
      • Zero

    • 2.
      Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

        • attract with a force \( \frac{F}{2} \)
        • repel with a force \( \frac{F}{2} \)
        • repel with a force \( F \)
        • attract with a force \( F \)

      • 3.
        A light copper ring is freely suspended by a light string. A bar magnet is held horizontally with its length along the axis of the ring. The magnet is moved towards the ring with its N pole facing the loop. What will happen to the ring and its position? Explain.


          • 4.
            Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.


              • 5.
                Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

                  • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
                  • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                  • Assertion (A) is true, but Reason (R) is false.
                  • Both Assertion (A) and Reason (R) are false.

                • 6.
                  If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

                    CBSE CLASS XII Previous Year Papers

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