What is the dimensional formula of magnetic flux/electric flux?

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Jasmine Grover

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Ques: What is the dimensional formula of magnetic flux/electric flux?

Ans: In physics, the dimensional formula of magnetic flux is given by:

Magnetic Flux = [M] [L]2 [T]-2 [I]-1

Where:

also, the dimensional formula of electric flux is given by:

[Electric Flux] = [M] [L]3 [T]-3 [I]-1

Therefore, the dimensional formula of magnetic flux to electric flux can be obtained by dividing the dimensional formula of magnetic flux by the dimensional formula of electric flux. 

Thus, the dimensional formula of Magnetic flux/Electric flux = [M] [L]2 [T]-2 [I]-1/[M] [L]3 [T]-3 [I]-1 = [L]-1 [T]

Important Facts about Electric Flux & Magnetic Flux

  • Magnetic flux is a physical quantity which can be defined as a measure of the strength of a magnetic field passing through a given area. It is used to describe the behaviour of magnetic fields in different materials.
  • Electric flux is a measure of the strength of an electric field passing through a given area. It is calculated by taking the dot product of the electric field vector and the area vector.
  • The ratio of magnetic flux to electric flux is measured in inverse length and time.
  • The ratio of electric flux to magnetic flux is given by Electric flux/magnetic flux = [M] [L]3 [T]-3 [I]-1/[M] [L]2 [T]-2 [I]-1
  • Dimensional of electric flux to magnetic flux is LT−1

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CBSE CLASS XII Related Questions

  • 1.
    An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.


      • 2.
        This ‘average velocity’ is found be few mm/s for currents in range of a few amperes. How then is current established almost the instant a circuit is closed ?


          • 3.
            In a telescope the objective has much larger aperture than the eye piece. Why ?


              • 4.
                Read the following paragraph and answer the questions that follow.
                A p-type or n-type semiconductor can be converted into a p-n junction by doping it with suitable impurity. The motion of majority charge carriers causes diffusion current across the junction while the barrier electric field causes motion of minority carriers for drift current. In case of unbiased diode, the diffusion and drift currents are equal. This equilibrium is disturbed by the biasing batteries. Diodes, therefore, allow currents in one direction. This property of diode is used in making rectifiers.


                  • 5.
                    Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

                      • The total charge of the two spheres is conserved.
                      • Both spheres attain the same potential.
                      • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
                      • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

                    • 6.
                      Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.

                        CBSE CLASS XII Previous Year Papers

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