What is the dimensional formula of magnetic flux/electric flux?

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Lead

Ques: What is the dimensional formula of magnetic flux/electric flux?

Ans: In physics, the dimensional formula of magnetic flux is given by:

Magnetic Flux = [M] [L]2 [T]-2 [I]-1

Where:

also, the dimensional formula of electric flux is given by:

[Electric Flux] = [M] [L]3 [T]-3 [I]-1

Therefore, the dimensional formula of magnetic flux to electric flux can be obtained by dividing the dimensional formula of magnetic flux by the dimensional formula of electric flux. 

Thus, the dimensional formula of Magnetic flux/Electric flux = [M] [L]2 [T]-2 [I]-1/[M] [L]3 [T]-3 [I]-1 = [L]-1 [T]

Important Facts about Electric Flux & Magnetic Flux

  • Magnetic flux is a physical quantity which can be defined as a measure of the strength of a magnetic field passing through a given area. It is used to describe the behaviour of magnetic fields in different materials.
  • Electric flux is a measure of the strength of an electric field passing through a given area. It is calculated by taking the dot product of the electric field vector and the area vector.
  • The ratio of magnetic flux to electric flux is measured in inverse length and time.
  • The ratio of electric flux to magnetic flux is given by Electric flux/magnetic flux = [M] [L]3 [T]-3 [I]-1/[M] [L]2 [T]-2 [I]-1
  • Dimensional of electric flux to magnetic flux is LT−1

Read More:

CBSE CLASS XII Related Questions

  • 1.
    Read the following paragraph and answer the questions that follow.
    A p-type or n-type semiconductor can be converted into a p-n junction by doping it with suitable impurity. The motion of majority charge carriers causes diffusion current across the junction while the barrier electric field causes motion of minority carriers for drift current. In case of unbiased diode, the diffusion and drift currents are equal. This equilibrium is disturbed by the biasing batteries. Diodes, therefore, allow currents in one direction. This property of diode is used in making rectifiers.


      • 2.
        The resistance of a metal wire at \( 20^\circ \text{C} \) is \( 1.05 \, \Omega \) and at \( 100^\circ \text{C} \) is \( 1.38 \, \Omega \). Determine the temperature coefficient of resistivity of this metal.


          • 3.
            Capacitors are manufactured with certain standard capacitances and working voltages. However, these standard values may not be the ones that are actually needed in a particular application. Two or more capacitors can be grouped in series or in parallel to achieve desired capacitance and voltage. When connected in series, the total capacitance decreases while the voltage rating increases, whereas in parallel connections, the total capacitance increases and maintains the same voltage rating. A capacitor stores energy in the electric field between its plates and stored energy is proportional to the square of the voltage and capacitance $U = \frac{1}{2}CV^2$, where symbols have their usual meanings.
            Two capacitors, one of $3 \ \mu$F and the other of $6 \ \mu$F, are connected in series in the circuit as shown in the figure, for a long time. }


              • 4.
                Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.


                  • 5.
                    Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

                      • The total charge of the two spheres is conserved.
                      • Both spheres attain the same potential.
                      • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
                      • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

                    • 6.
                      An electric field $\vec{E}$ is established across the ends of a cylindrical conductor of length L and area of cross-section A. Discuss how electrons attain an average velocity, independent of time. Hence, obtain a relation between current in the conductor and this ‘average velocity’ of electrons.

                        CBSE CLASS XII Previous Year Papers

                        Comments


                        No Comments To Show