NCERT Solutions for Applications of Integrals Exercise 8.2 Solutions

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Class 12 Maths NCERT Solutions Chapter 8 Applications of Integrals Exercise 8.2 is provided in the article. Class 12 Chapter 8 Applications of Integrals Exercises include questions on area between a curve, parabola, and ellipse. All questions under this chapter are solved using diagrams and an easy to understand method.

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p>Also Read:

Chapter 8 Applications of Integrals Important Topics
Trapezoidal Rule Formula	Area Under Curve Formula	Trapezoidal Rule
Applications of Integrals Important Questions	SImpsons Rule Formula	Surface Integral

Also Read:

CBSE Class 12 Mathematics Study Guides
Algebra	Arithmetic	Calculus
Mensuration	Trigonometry	Geometry
Permutation and Combination	Math Study Notes	Math MCQs
NCERT Solutions for Class 12 Maths	Math Formula	Difference between in Maths

CBSE CLASS XII Related Questions

1.
Find:

The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]
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2.
An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.
Based on the above information, answer the following questions :
3.
If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).
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4.
Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).
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5.
Which of the following equations is NOT a Linear Differential Equation?
- \((1 + x^2) \, dy + 2xy \, dx = \cot x \, dx\)
- \(y + \frac{d}{dx}(xy) = x(\sin x + \log x)\)
- \(x(1 + y^2) \, dx - y(1 + x^2) \, dy = 0\)
- \(y \, dx - (x + 3y^2) \, dy = 0\)
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6.
Find:
Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).
- \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
- \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
- \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
- \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)
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