NCERT Solutions for Applications of Integrals Exercise 8.2 Solutions

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Class 12 Maths NCERT Solutions Chapter 8 Applications of Integrals Exercise 8.2 is provided in the article. Class 12 Chapter 8 Applications of Integrals Exercises include questions on area between a curve, parabola, and ellipse. All questions under this chapter are solved using diagrams and an easy to understand method.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 8 Exercise 8.2

Read More: NCERT Solutions For Class 12 Mathematics Chapter 8 Application of Integrals

Also check other Exercise Solutions of Class 12 Maths Chapter 8 Applications of Integrals

p>Also Read:

Chapter 8 Applications of Integrals Important Topics
Trapezoidal Rule Formula	Area Under Curve Formula	Trapezoidal Rule
Applications of Integrals Important Questions	SImpsons Rule Formula	Surface Integral

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CBSE CLASS XII Related Questions

1.
If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]
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2.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.
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3.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.
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4.
Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]
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5.
Assertion (A) : In an experiment of throwing an unbiased die, the probability of getting a prime number given that number appearing on the die being odd is \( \frac{2}{3} \).
Reason (R) : For any two events \( A \) and \( B \), \( P(A|B) = \frac{P(A \cup B)}{P(B)} \).
- Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true and Reason (R) is false.
- Assertion (A) is false and Reason (R) is true.
View Solution
6.
For a square matrix \(A\), \[ (3A)^{-1}= \]
- \( 3A^{-1} \)
- \( 9A^{-1} \)
- \( \frac{1}{3} A^{-1} \)
- \( \frac{1}{9} A^{-1} \)
View Solution

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Application of Integrals: Introduction and Explanation

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