NCERT Solutions for Class 12 Chapter 9 Differential Equations Exercise 9.5 Solutions

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Class 12 Maths NCERT Solutions Chapter 9 Differential Equations Exercise 9.5 is provided in the article. Class 12 Chapter 9 Differential Equations Exercises provided in the chapter are based on Homogeneous Differential Equations.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 9 Exercise 9.5

Also check other Exercise Solutions of Class 12 Maths Chapter 9 Differential Equations

Also Read:

Chapter 9 Differential Equations Important Topics
Differential Equations Applications	Difference between parametric and nonparametric	Partial Differential Equation
Ordinary differential equations	Differential Equations Formula	Differential Calculus
Partial Derivative	How to Solve Linear Differential Equation	Homogeneous Differential Equation

Also Read:

CBSE Class 12 Mathematics Study Guides
Algebra	Arithmetic	Calculus
Mensuration	Trigonometry	Geometry
Permutation and Combination	Math Study Notes	Math MCQs
NCERT Solutions for Class 12 Maths	Math Formula	Difference between in Maths

CBSE CLASS XII Related Questions

1.
The motion of a particle is described as \( S = 2t^{3} - 6t^{2} + 8 \). Its velocity \( \frac{dS}{dt} \), when the acceleration \( \frac{d^{2}S}{dt^{2}} \) vanishes is :
- \( -6 \) unit/sec
- \( 0 \) unit/sec
- \( 18 \) unit/sec
- \( 6 \) unit/sec
View Solution
2.
For the given Linear Programming Problem, shade the feasible region on the graph and write the coordinates of the corner points.
Minimize \(Z = 5x + 7y\)
subject to constraints
\[ 2x + y \geq 8 \]
\[ x + 2y \geq 10 \]
\[ x,\ y \geq 0. \]
View Solution
3.
For events A and B, if \(P(B)=\frac{3}{5}\), \(P(A/B)=\frac{1}{2}\) and \(P(A\cup B)=\frac{4}{5}\), then \(P(A)\) is :
- \(\frac{1}{2}\)
- \(\frac{3}{5}\)
- \(\frac{1}{5}\)
- \(\frac{3}{10}\)
View Solution
4.
Find the sum of maximum and minimum values of \(f(x) = \sin x\,(1 + \cos x)\) in the interval \([0, \pi]\).
View Solution
5.
If \(y = \sqrt{\log \left\{ \sin \left( \dfrac{x^2}{3} + 1 \right) \right\}}\), then show that
\[ \frac{dy}{dx} = \frac{x \cot \left( \dfrac{x^2}{3} + 1 \right)}{3y}. \]
View Solution
6.
Solve the differential equation \( y + \frac{d}{dx}(xy) = x(\sin x + \log x) \).
View Solution

View All

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You can also check

NCERT Solutions for Class 12 Chapter 9 Differential Equations Exercise 9.5 Solutions

CBSE CLASS XII Related Questions

1.
The motion of a particle is described as \( S = 2t^{3} - 6t^{2} + 8 \). Its velocity \( \frac{dS}{dt} \), when the acceleration \( \frac{d^{2}S}{dt^{2}} \) vanishes is :

2.
For the given Linear Programming Problem, shade the feasible region on the graph and write the coordinates of the corner points.
Minimize \(Z = 5x + 7y\)
subject to constraints
\[ 2x + y \geq 8 \]
\[ x + 2y \geq 10 \]
\[ x,\ y \geq 0. \]

3.
For events A and B, if \(P(B)=\frac{3}{5}\), \(P(A/B)=\frac{1}{2}\) and \(P(A\cup B)=\frac{4}{5}\), then \(P(A)\) is :

4.
Find the sum of maximum and minimum values of \(f(x) = \sin x\,(1 + \cos x)\) in the interval \([0, \pi]\).

5.
If \(y = \sqrt{\log \left\{ \sin \left( \dfrac{x^2}{3} + 1 \right) \right\}}\), then show that
\[ \frac{dy}{dx} = \frac{x \cot \left( \dfrac{x^2}{3} + 1 \right)}{3y}. \]

6.
Solve the differential equation \( y + \frac{d}{dx}(xy) = x(\sin x + \log x) \).

Similar Mathematics Concepts

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NCERT Solutions for Class 12 Chapter 9 Differential Equations Exercise 9.5 Solutions

CBSE CLASS XII Related Questions

1.The motion of a particle is described as \( S = 2t^{3} - 6t^{2} + 8 \). Its velocity \( \frac{dS}{dt} \), when the acceleration \( \frac{d^{2}S}{dt^{2}} \) vanishes is :

2.For the given Linear Programming Problem, shade the feasible region on the graph and write the coordinates of the corner points.Minimize \(Z = 5x + 7y\)subject to constraints\[ 2x + y \geq 8 \]\[ x + 2y \geq 10 \]\[ x,\ y \geq 0. \]

3.For events A and B, if \(P(B)=\frac{3}{5}\), \(P(A/B)=\frac{1}{2}\) and \(P(A\cup B)=\frac{4}{5}\), then \(P(A)\) is :

4.Find the sum of maximum and minimum values of \(f(x) = \sin x\,(1 + \cos x)\) in the interval \([0, \pi]\).

5.If \(y = \sqrt{\log \left\{ \sin \left( \dfrac{x^2}{3} + 1 \right) \right\}}\), then show that\[ \frac{dy}{dx} = \frac{x \cot \left( \dfrac{x^2}{3} + 1 \right)}{3y}. \]

6.Solve the differential equation \( y + \frac{d}{dx}(xy) = x(\sin x + \log x) \).

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The motion of a particle is described as \( S = 2t^{3} - 6t^{2} + 8 \). Its velocity \( \frac{dS}{dt} \), when the acceleration \( \frac{d^{2}S}{dt^{2}} \) vanishes is :

2.
For the given Linear Programming Problem, shade the feasible region on the graph and write the coordinates of the corner points.
Minimize \(Z = 5x + 7y\)
subject to constraints
\[ 2x + y \geq 8 \]
\[ x + 2y \geq 10 \]
\[ x,\ y \geq 0. \]

3.
For events A and B, if \(P(B)=\frac{3}{5}\), \(P(A/B)=\frac{1}{2}\) and \(P(A\cup B)=\frac{4}{5}\), then \(P(A)\) is :

4.
Find the sum of maximum and minimum values of \(f(x) = \sin x\,(1 + \cos x)\) in the interval \([0, \pi]\).

5.
If \(y = \sqrt{\log \left\{ \sin \left( \dfrac{x^2}{3} + 1 \right) \right\}}\), then show that
\[ \frac{dy}{dx} = \frac{x \cot \left( \dfrac{x^2}{3} + 1 \right)}{3y}. \]

6.
Solve the differential equation \( y + \frac{d}{dx}(xy) = x(\sin x + \log x) \).