NCERT Solutions for Differential Equations Exercise 9.6 Solutions

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Class 12 Maths NCERT Solutions Chapter 9 Differential Equations Exercise 9.6 is provided in the article. Class 12 Chapter 9 Differential Equations Exercises are based on solving the linear differential equations.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 9 Exercise 9.6

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CBSE CLASS XII Related Questions

  • 1.
    For a square matrix \(A\), \[ (3A)^{-1}= \]

      • \( 3A^{-1} \)
      • \( 9A^{-1} \)
      • \( \frac{1}{3} A^{-1} \)
      • \( \frac{1}{9} A^{-1} \)

    • 2.
      For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

        • local maximum value is 2
        • local minimum value is \( -2 \)
        • local maximum value is \( -2 \)
        • local minimum value \( < \) local maximum value

      • 3.

        Sports car racing is a form of motorsport which uses sports car prototypes.The competition is held on special tracks designed in various shapes. 

        The equation of a sports car racing track is given as: \[ f(x)= \begin{cases} x^4-4x^2+4, & 0\leq x<3,\\ x^2+40, & x\geq 3 \end{cases} \] Based on this information:


          • 4.
            A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.


              • 5.

                For two vectors \(\vec{a}\) and \(\vec{b}\):  

                Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

                  • Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
                  • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                  • Assertion (A) is true, but Reason (R) is false.
                  • Assertion (A) is false, but Reason (R) is true.

                • 6.

                  If \[ B(\operatorname{adj} B)= \begin{bmatrix} \frac{1}{3} & 0 & 0\\ 0 & \frac{1}{3} & 0\\ 0 & 0 & \frac{1}{3} \end{bmatrix}, \] then the value of \[ \det(B^{-1}) \] is: 

                    • \(\frac{1}{3}\)
                    • \(\frac{1}{9}\)
                    • \(3\)
                    • \(9\)
                  CBSE CLASS XII Previous Year Papers

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