NCERT Solutions for Class 12 Maths Chapter 3 Matrices Exercise 3.3

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Lead

Class 12 Maths NCERT Solutions Chapter 3 Matrices Exercise 3.3 is provided in this article. Chapter 3 Exercise 3.3 deals with questions on the transpose of a matrix, properties of transpose of a matrix, and symmetric and skew-symmetric matrices.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 3 Exercise 3.3

Check out the solutions for Class 12 Maths NCERT solutions chapter 3 Matrices Exercise 3.3:

Read More: NCERT Solutions For Class 12 Mathematics Chapter 3 Matrices

Check out other exercise solutions of Class 12 Maths Chapter 3 Matrices

Class 12 Chapter 3 Matrices Topics:

CBSE Class 12 Mathematics Study Guides:

CBSE CLASS XII Related Questions

  • 1.
    Find:

    The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

      • \(-\frac{\pi}{2}\)
      • \(-\frac{\pi}{4}\)
      • \(\frac{\pi}{4}\)
      • \(\frac{\pi}{2}\)

    • 2.
      Which of the following equations is NOT a Linear Differential Equation?

        • \((1 + x^2) \, dy + 2xy \, dx = \cot x \, dx\)
        • \(y + \frac{d}{dx}(xy) = x(\sin x + \log x)\)
        • \(x(1 + y^2) \, dx - y(1 + x^2) \, dy = 0\)
        • \(y \, dx - (x + 3y^2) \, dy = 0\)

      • 3.
        Find: \[ \int \frac{x^2}{(x^2-1)(x^2+4)}\,dx \]


          • 4.

            Find:
            Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).

              • \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
              • \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
              • \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
              • \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)

            • 5.
              If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).


                • 6.

                  A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length. 

                    CBSE CLASS XII Previous Year Papers

                    Comments


                    No Comments To Show