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The angle of minimum deviation in a prism is the angle at which a ray of light passing through the prism emerges parallel to the base of the prism. It is denoted by the symbol "δm".
The angle of a prism is given as 60 degrees. The refractive index of the material of the prism is given as √2.
Using the formula for the angle of minimum deviation, which is given by:
sin[(A+δm)/2]/sin(A/2) = n
where A is the angle of the prism and n is the refractive index of the prism material.
Substituting the given values, we get:
sin[(60+δm)/2]/sin(60/2) = √2
Simplifying this equation, we get:
sin[(30+δm)/2] = 1/√2
Taking the inverse sine of both sides, we get:
(30+δm)/2 = 45
Solving for δm, we get:
δm = 30 degrees
Therefore, the angle of minimum deviation for the prism is 30 degrees.
The angle of a prism is 60∘ and its refractive index is √2. The angle of minimum deviation suffered by a ray of light in passing through it is 30 degrees.
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