Time constant T for the shown circuit containing resistance and capacitor is

CBSE CLASS XII Related Questions

  • 1.
    In a region, the electric potential varies as \(V = 10 - 50x\), where \(V\) is in volts and \(x\) is in meters. The electric field in the region is

      • \(10\ \text{N/C}\) along \(+x\)
      • \(10\ \text{N/C}\) along \(-x\)
      • \(50\ \text{N/C}\) along \(+x\)
      • \(50\ \text{N/C}\) along \(-x\)

    • 2.

      A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:

        • 5 V
        • 3.5 V
        • 2.5 V
        • Zero V

      • 3.
        Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

          • \( (M_x - M_z)<M_y \)
          • \( (M_x - M_y)<M_z \)
          • \( M_x>(M_y + M_z) \)
          • \( M_x<(M_y + M_z) \)

        • 4.
          Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:

            • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{\sqrt{2}Q}{d^2} (-\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (\hat{i} - \hat{j})\)
            • \(\frac{1}{4\pi\epsilon_0} \frac{Q}{d^2} (-\hat{i} - \hat{j})\)

          • 5.
            A current of \(4.0\,\text{A}\) flows through a wire of length \(1\,\text{m}\) and cross-sectional area \(1.0\,\text{mm}^2\), when a potential difference of \(2\,\text{V}\) is applied across its ends. Calculate the resistivity of the material of the wire.


              • 6.

                A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

                  • 80 Wb
                  • 16 Wb
                  • \(8 \times 10^{-2}\) Wb
                  • \(8 \times 10^{-3}\) Wb
                CBSE CLASS XII Previous Year Papers

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