An electric current of 3 A flows via a wire of resistance 15 ohms. How much heat will be produced in a minute?

As per the given data,

  • Current via resistance, I = 3 A.
  • The value of the resistance, R = 15 Ω.
  • Time required for heat development = t = 60 seconds

Step 1: Joule’s Law of Heating

  1. Joule's law says that when current I flows in a conductor of resistance R for time T sec, then the generated heat on the conductor is directly proportional to the square of the electric current.
  2. Joule's law of heating can be expressed by H = I2RT (Q = generated heat on the conductor).

Step 2: Heat Calculation

In order to determine the given question, we need to apply Joule’s Law,

H = I2RT = 32 \(\times\) 15 \(\times\) 60

Thus, H = 8100 Joule

Hence, 8100 Joule heat will be produced in a minute.

Also Check: NCERT Solutions for Class 6 to 12


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  6. A Galvanometer Having Resistance 100 Ohms Shows Full Scale Deflection With Current 10 MA. Find Value Of Shunt To Convert It Into An Ammeter Of 10 Ampere Range.
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  8. Two Identical Resistors With Resistances 15 Ohm Are Connected In Series And Parallel To A Battery Of 6 V. Calculate Ratio Of Power Consumed.
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CBSE CLASS XII Related Questions

  • 1.
    Capacitors are manufactured with certain standard capacitances and working voltages. However, these standard values may not be the ones that are actually needed in a particular application. Two or more capacitors can be grouped in series or in parallel to achieve desired capacitance and voltage. When connected in series, the total capacitance decreases while the voltage rating increases, whereas in parallel connections, the total capacitance increases and maintains the same voltage rating. A capacitor stores energy in the electric field between its plates and stored energy is proportional to the square of the voltage and capacitance $U = \frac{1}{2}CV^2$, where symbols have their usual meanings.
    Two capacitors, one of $3 \ \mu$F and the other of $6 \ \mu$F, are connected in series in the circuit as shown in the figure, for a long time. }


      • 2.
        Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

          • The total charge of the two spheres is conserved.
          • Both spheres attain the same potential.
          • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
          • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

        • 3.
          Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

            • \( (M_x - M_z)<M_y \)
            • \( (M_x - M_y)<M_z \)
            • \( M_x>(M_y + M_z) \)
            • \( M_x<(M_y + M_z) \)

          • 4.
            A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.


              • 5.
                Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.


                  • 6.
                    Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.

                      CBSE CLASS XII Previous Year Papers

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