Triangles Formula: Perimeter, Area and Solved Examples

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Shwetha S

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A polygon with three sides and three corners is a triangle. In geometry, it is one of the fundamental themes of geometry. A triangle with vertices A, B, and C is represented as △ABC. In Euclidean geometry, any three non-collinear points simultaneously determine a unique triangle and plane. There are three angles in a triangle. Any angle is formed when any two sides of the triangle meet at a common point called the vertex.

Read more: Euclid’s division lemma

KeyTerms: Triangle, Isosceles triangle, Scalene Triangle, Area of Triangles, Perimeter of Triangles, Pythagoras Theorem. 


Triangle

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A triangle is a three-sided polygon composed of three edges and three vertices. The most important property of a triangle is that the sum of the interior angles of a triangle equals 180 degrees. This property is called the angle sum property of the triangle. If ABC is a triangle, then it is referred to as ABC, where A, B, and C are the vertices of the triangle. A triangle is a two-dimensional shape in Euclidean geometry viewed as three non-collinear points in a unique plane

Pythagorean Theorem An equation relating the lengths of the sides of a right triangle, a2 + b2 = c2, where a and b are the lengths of the sides closest to the right form angles, and c is the length of the hypotenuse.

Pythagorean theorem

Pythagorean theorem


Perimeter of Triangle Formula

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The perimeter of a polygon is the sum of the edge lengths. 

In a triangle, perimeter = the sum of the three sides.

Perimeter (P) = a + b + c

Perimeter of triangle

Perimeter of triangle


Area of a Triangle

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The triangle area is the total area enclosed by the three sides of a given triangle. It corresponds to half the height of the basic periods. Therefore, in order to find the box of a three-sided polygon, we need to know the base and height of it. The area of different types of triangles are as follows:

Area of Isosceles Triangle

In an isosceles triangle, two sides are equal in length. Also equal are the two angles opposite the two equal sides.

  • In case base and height are given, we use the following formula:

A = ½ × height × base

  • If three sides are given :

A = ½[√(a2 − b2/4) × b]

  • Using 2 sides of the triangle and an angle between them : 

A = ½ × b × c × sin(α)

  • Using two angles between two sides and their length :

A = [c2 × sin(β) × sin(α)/ 2 × sin(2π−α−β)]

Area of Isosceles Triangle

Area of Isosceles Triangle

Area of Scalene Triangle Formula

An uneven triangle is a type of triangle that has different lateral measurements on all three sides is known as scalene triangle . This makes the three angles different from each other.

A = ½ × height × base

Area of scalene triangle 

Area of scalene triangle 

Area of Equilateral Triangle Formula

In an equilateral triangle, all three sides are equal. Consequently, all interior angles are equal, i.e. each angle is 60°.

A = (√3)/4 × side2

where,

A is the area of the triangle.

a is the length of the triangle.

b is the base of the triangle.

c is the third side of the triangle.

h is the height of the triangle.

α and β are the angles between two sides.

Area of equilateral triangle 

Area of equilateral triangle 


Things to remember

  • Area of triangle, A = [(½) b × h]; where 'b' is the triangle's base and 'h' is the triangle's height.
  • The perimeter of a triangle, P = (a + b + c), where a, b, and c are the triangle's three sides.
  • A triangle has three sides and three angles. 
  • The sum of the angles of a triangle is always 180 degrees. 
  • The outer angles of a triangle always add up to 360 degrees. 
  • Area of an equilateral triangle is A = (√3)/4 × side2).

Solved Questions

Ques. Determine a triangle area with a base of 12cm and a height of 10cm (2 marks)

Ans. Area of a triangle = ½ × height × base

= ½ × 12 × 10

= 6 × 10

= 60 cm2

Ques. Find the area of a triangle with a base of 20 cm and a height of 10 cm (2 marks)

Ans. Area of triangle = (1/2) × b × h

A = 1/2 × 20 × 10

A = 1/2 × 200

Thus, the area of a triangle is 100 cm2.

Ques. Find the area of a triangle with a base of 6 cm and a height of 3 cm (2 marks)

Ans. Area of triangle = (1/2) × b × h

A = 1/2 × 6×3

A = 1/2 ×18

Thus, the area of a triangle is 9 cm2.

Ques. Find the area of a triangle with a base of 12 cm and a height of 16 cm (2 marks)

Ans. Area of triangle = (1/2) × b × h

A = 1/2 × 12 × 16

A = 96

Thus, the area of the triangle is 96 cm2.

Ques. Find the area of an equilateral triangle with a side of 12 cm (3 marks)

Ans. Area of an Equilateral Triangle = A = (√3)/4 × (side)2

Given the side of equilateral triangle = 12cm

A = (√3)/4 × (side)2

A = (√3)/4 × (12)2

A = (√3)/4 × 144

A = 36√3 cm2

Ques. Find the area of a triangle with base 60 cm and height are 10cm (2 marks)

Ans. Area of triangle=1/2×base×height

=1/2×60×10

=60×5

=300 cm2

Therefore, the area of triangle is 300 cm2

Ques. The total area of triangle has 3 sides (3 marks)

Ans. Therefore we have only 2 sides, so our third side will be x

Area of triangle = l × b × h

60cm + 10cm + x = 180°

70cm + x = 180°

x = 180° - 70 cm

x = 110°

Therefore the third side of the triangle will be 110 cm / 110°

Ques. Find the height of a triangle whose base is 60cm and area is 0.06sq.m base = 60 cm =0.6 m (2 marks)

Ans. Area of a triangle = ½ x b x h

= ½ × 0.6 × h

 h = 0.06/0.3

 h = 0.2 m = 20cm

Ques. Find the height of a triangle whose area is 60cm2and base is 12 cm (2 marks)

Ans. Area of a triangle = ½ × base × height

60=½ ×12×h

60=6h

h=10cm.

Ques. Find the height of triangle whose area=300cm2 base=60cm (2 marks)

Ans. Area of triangle = ½ × base ×height

=> 300 cm2 = ½ ×60cm×h

=>300cm2= 30cm×h

=>h=300cm2/30cm

=>h=10cm

Ques. Find the area of a triangle whose base is 2 cm and height is 60cm (5 marks)

Ans. Given,

Base of triangle = 2 cm

Height of triangle = 60 cm

As known,

Triangle is a three sided figure,

Sum of all angles of the triangle is 180 degrees.

The area of triangle can be determined by using formula

area of triangle = ½ × base ×height

=½ x 2 x 60

= 60 cm2


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CBSE X Related Questions

  • 1.
    The dimensions of a window are $156\text{ cm} \times 216\text{ cm}$. Arjun wants to put grill on the window creating complete squares of maximum size. Determine the side length of the square and hence find the number of squares formed.


      • 2.
        Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$


          • 3.
            PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.


              • 4.
                Assertion (A) : The system of linear equations $3x - 5y + 7 = 0$ and $-6x + 10y + 14 = 0$ is inconsistent.
                Reason (R) : When two linear equations don't have unique solution, they always represent parallel lines.

                  • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
                  • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                  • Assertion (A) is true, but Reason (R) is false.
                  • Assertion (A) is false, but Reason (R) is true.

                • 5.
                  The value of p for which roots of the quadratic equation $x^2 - px + 6 = 0$ are rational, is

                    • $1$
                    • $-5$
                    • $25$
                    • $\sqrt{5}$

                  • 6.
                    Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

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