CBSE Class 10 Sherpa Question Paper 2018 with Answer Key (March 20, Set 4)

CBSE Class 10 Sherpa Question Paper 2018 with Answer Key Set 4 is available for download. The exam was conducted by the Central Board of Secondary Education on March 20, 2018 in the Morning Session 10:30 AM to 1:30 PM. The medium of paper was Shepa. The question paper comprised a total of 13 questions.

CBSE Class 10 Sherpa Set 4 Question Paper 2018 with Answer Key (March 20)

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CBSE X Questions

1.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

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2.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

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3.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

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4.
How does the change in curvature of the eye lens help us in the process of seeing the nearby objects clearly?

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5.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

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6.
In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

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CBSE Class 10 Sherpa Question Paper 2018 with Answer Key (March 20, Set 4)

CBSE Class 10 Sherpa Set 4 Question Paper 2018 with Answer Key (March 20)

CBSE Class 10 Previous Year Question Papers

CBSE X Questions

1.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

2.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

3.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

4.
How does the change in curvature of the eye lens help us in the process of seeing the nearby objects clearly?

5.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

6.
In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

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CBSE Class 10 Sherpa Set 4 Question Paper 2018 with Answer Key (March 20)

CBSE Class 10 Previous Year Question Papers

CBSE X Questions

1.PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

2.In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

3.Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

4. How does the change in curvature of the eye lens help us in the process of seeing the nearby objects clearly?

5.A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

6.In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.

Comments

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1.
PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If OP = 13 cm, then find the length AB and PA.

2.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

3.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

4.
How does the change in curvature of the eye lens help us in the process of seeing the nearby objects clearly?

5.
A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

6.
In the given figure, $AB \parallel DE$ and $AC \parallel DF$. Show that $\Delta ABC \sim \Delta DEF$. If $BC = 10\text{ cm}$, $EB = CF = 5\text{ cm}$ and $AB = 7\text{ cm}$, then find the length $DE$.