Angle of minimum deviation for prism of refractive index 1.5 is equal to angle of prism of given prism. Calculate angle of prism.

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The angle of minimum deviation for a prism occurs when the angle of incidence and the angle of emergence are equal.

Let the angle of prism be A and the refractive index be n. Then, using the prism formula, we can write:

sin[(A+D)/2] / sin(A/2) = n

where D is the angle of deviation.

For the angle of minimum deviation, D is minimum, which means that sin(D/2) is minimum. This occurs when D is minimum, and for a prism of small angle, the minimum angle of deviation occurs when D = 0.

So, we have:

sin[(A+D)/2] / sin(A/2) = n sin(A/2) / sin(A/2) = n 1 = n

Thus, for a prism of refractive index 1.5, the angle of minimum deviation is equal to the angle of the prism. This means that A = sin^-1(n) = sin^-1(1.5) = 41.81 degrees.

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Angle of minimum deviation for prism of refractive index 1.5 is equal to angle of prism of given prism. Calculate angle of prism.

CBSE CLASS XII Related Questions

1.
Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.

2.
Write two advantages of reflecting telescope over refracting telescope.

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Angle of minimum deviation for prism of refractive index 1.5 is equal to angle of prism of given prism. Calculate angle of prism.

CBSE CLASS XII Related Questions

1.Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.

2.Write two advantages of reflecting telescope over refracting telescope.

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Derive an expression for the capacitance of a parallel plate capacitor of plate area A and plate separation d with air present between the plates.

2.
Write two advantages of reflecting telescope over refracting telescope.