NCERT Solutions for Class 12 Maths Chapter 1 Relations and Functions Exercise 1.2

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NCERT Solutions for Class 12 Maths Chapter 1 Relations and Functions Exercise 1.2 is mainly based on types of relations. 

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Check Class 12 NCERT Maths Chapter 1 Relations and Functions Exercises: 

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CBSE Class 12 Mathematics Study Guide:

CBSE CLASS XII Related Questions

  • 1.
    Find:

    If \[ (3\hat{i}-2\hat{j}+5\hat{k})\times(4\hat{i}+p\hat{j}+q\hat{k})=\vec{0} \] then find the values of \(p\) and \(q\).

      • \(p = -\frac{2}{3}, \, q = \frac{5}{3}\)
      • \(p = -\frac{8}{3}, \, q = \frac{20}{3}\)
      • \(p = \frac{20}{3}, \, q = -\frac{8}{3}\)
      • \(p = 0, \, q = 0\)

    • 2.
      Find:

      If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).

        • \(0\)
        • \(-2\)
        • \(-1\)
        • \(2\)

      • 3.

        An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.  
        Based on the above information, answer the following questions :


          • 4.
            Which of the following equations is NOT a Linear Differential Equation?

              • \((1 + x^2) \, dy + 2xy \, dx = \cot x \, dx\)
              • \(y + \frac{d}{dx}(xy) = x(\sin x + \log x)\)
              • \(x(1 + y^2) \, dx - y(1 + x^2) \, dy = 0\)
              • \(y \, dx - (x + 3y^2) \, dy = 0\)

            • 5.
              Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).


                • 6.
                  Find:

                  The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]

                    CBSE CLASS XII Previous Year Papers

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