NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.4

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Lead

NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.4 is provided in this article with a step by step explanation. Chapter 10 Vector Algebra Exercise 10.4 covers basic concepts of the magnitude of vectors, and the vector or cross product of two vectors.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 10 Exercise 10.4

Check out the solutions of Class 12 Maths NCERT solutions chapter 10 Vector Algebra Exercise 10.4

Read More: NCERT Solutions For Class 12 Mathematics Chapter 10 Vector Algebra 

Check out other exercise solutions of Class 12 Maths Chapter 10 Vector Algebra

Class 12 Chapter 10 Vector Algebra Topics:

CBSE Class 12 Mathematics Study Guides:

CBSE CLASS XII Related Questions

  • 1.

    Evaluate:
    \[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]


      • 2.
        Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).


          • 3.

            A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length. 


              • 4.
                Find:

                The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

                  • \(-\frac{\pi}{2}\)
                  • \(-\frac{\pi}{4}\)
                  • \(\frac{\pi}{4}\)
                  • \(\frac{\pi}{2}\)

                • 5.

                  At a birthday party, children are being served orange juice in conical cups, as shown in the figure. 


                  Each cup is 15 cm deep and has a radius 5 cm. The juice is being poured into this cup at a rate of 0·1 cm3/s.
                  On the basis of the above information, answer the following questions :


                    • 6.
                      Find:

                      The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]

                        CBSE CLASS XII Previous Year Papers

                        Comments


                        No Comments To Show