NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3

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NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3 is covered in this article with a detailed explanation. Chapter 10 Vector Algebra Exercise 10.1 covers basic concepts of the product of two vectors, multiplication of vector by a scalar, and projection of a vector on a line.

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Class 12 Chapter 10 Vector Algebra Topics:

Properties of scalar product of two vectors	Laws of Vector Addition	Vector Formula
Magnitude of a vector	Vector Projection Formula	Scalar triple product of vectors
Direction of a vector	Adjacency Matrix	Components of vector
Vector Space	Cross product	Vector Calculus

CBSE Class 12 Mathematics Study Guides:

NCERT Solutions for Class 12 Maths	Math Formula	Difference between in Maths
Math MCQs	Math Study Notes	Calculus
Mensuration	Arithmetic	Trigonometry

CBSE CLASS XII Related Questions

1.
An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.
Based on the above information, answer the following questions :

2.
Evaluate:
\[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]

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3.
If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).

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4.
Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).

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5.
Find:

The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

\(-\frac{\pi}{2}\)
\(-\frac{\pi}{4}\)
\(\frac{\pi}{4}\)
\(\frac{\pi}{2}\)

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6.
Find: \[ \int \frac{x^2}{(x^2-1)(x^2+4)}\,dx \]

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NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3

CBSE CLASS XII Related Questions

2.
Evaluate:
\[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]

3.
If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).

4.
Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).

5.
Find:

The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

6.
Find: \[ \int \frac{x^2}{(x^2-1)(x^2+4)}\,dx \]

Similar Mathematics Concepts

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NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Exercise 10.3

CBSE CLASS XII Related Questions

2.Evaluate:\[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]

3.If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).

4.Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).

5. Find: The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

6.Find: \[ \int \frac{x^2}{(x^2-1)(x^2+4)}\,dx \]

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

2.
Evaluate:
\[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]

3.
If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).

4.
Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).

5.
Find:

The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

6.
Find: \[ \int \frac{x^2}{(x^2-1)(x^2+4)}\,dx \]