NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Miscellaneous Exercise

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Jasmine Grover

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NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra Miscellaneous Exercise is provided in this article with a step by step explanation. Chapter 10 Vector Algebra Miscellaneous Exercise Solutions covers basic concepts of types of vectors, the addition of vectors, and the product of two vectors.

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Class 12 Chapter 10 Vector Algebra Topics:

CBSE Class 12 Mathematics Study Guides:

CBSE CLASS XII Related Questions

  • 1.
    A relation $R$ on set $A=\{1,2,3\}$ defined as $R=\{(1,2),(2,1),(2,2)\}$ is

      • Reflexive only
      • Reflexive and Transitive
      • Symmetric and Transitive
      • Symmetric only

    • 2.
      If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).


        • 3.

          A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length. 


            • 4.
              Using integration, find the area of the region bounded by the curve \( y = x|x| \), the x-axis, and the vertical lines \( x = -2 \) and \( x = 2 \).


                • 5.
                  Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).


                    • 6.

                      Find:
                      Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).

                        • \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
                        • \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
                        • \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
                        • \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)
                      CBSE CLASS XII Previous Year Papers

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