CBSE Class 10 Tibetan Question Paper 2018 with Answer Key (March 19, Set 4)

CBSE Class 10 Tibetan Question Paper 2018 with Answer Key Set 4 is available for download. The exam was conducted by the Central Board of Secondary Education on March 19, 2018 in the Morning Session 10:30 AM to 1:30 PM. The medium of paper was Tibetan. The question paper comprised a total of 9 questions divided among 4 sections.

CBSE Class 10 Tibetan Set 4 Question Paper 2018 with Answer Key (March 19)

CBSE Class 10 Tibetan Question Paper 2018 PDF	CBSE Class 10 Tibetan Answer Key 2018 PDF
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CBSE Class 10 Previous Year Question Papers

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CBSE X Questions

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

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2.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

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3.
How does the change in curvature of the eye lens help us in the process of seeing the nearby objects clearly?

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4.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

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5.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

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6.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

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CBSE Class 10 Tibetan Question Paper 2018 with Answer Key (March 19, Set 4)

CBSE Class 10 Tibetan Set 4 Question Paper 2018 with Answer Key (March 19)

CBSE Class 10 Previous Year Question Papers

CBSE X Questions

1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

3.
How does the change in curvature of the eye lens help us in the process of seeing the nearby objects clearly?

4.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

5.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

6.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

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CBSE Class 10 Tibetan Set 4 Question Paper 2018 with Answer Key (March 19)

CBSE Class 10 Previous Year Question Papers

CBSE X Questions

1.Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

3. How does the change in curvature of the eye lens help us in the process of seeing the nearby objects clearly?

4.Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

5.In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

6.Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.

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1.
Use graphical method to solve the system of linear equations : $x = -3$ and $5x - 2y = -5$.

2.
A bag contains 25 balls. Some of them are yellow and others are green. One ball is drawn at random. If probability of getting a green ball is $3/5$, then find the number of yellow balls.

3.
How does the change in curvature of the eye lens help us in the process of seeing the nearby objects clearly?

4.
Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$

5.
In the given figure, point D divides the side BC of $\Delta ABC$ in the ratio $1 : 2$. Find length AD.

6.
Prove that $14 - 2\sqrt{3}$ is an irrational number, given that $\sqrt{3}$ is irrational.