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Differentiation and Integration are two of the most significant branches of calculus, and the differentiation and integration formulas are also interchangeable. The outcome of integrating the derivative of a function is the original function. Integration is the reversal of differentiation, which is why an integral is also known as the antiderivative. Differentiation breaks down a function into components, while integration is used to put those parts back together to form the original function. The differentiation and integration formulas are used in geometry to compute the slope and area under a curve, respectively.
Table of Contents
| Table of Content |
Key Terms: Determinants, Differentiation, Integration, Variables, Function, Matrices, Derivative, Coefficient, Antiderivative, calculus, components
What are Determinants?
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A determinant is a scalar value derived from square matrix members. It is a numerical arrangement in the form given below:
\(A = \begin{bmatrix}a & b \\[0.3em]c & d \\[0.3em] \end{bmatrix}\)= |A| = ad – bc
Mathematicians defined the sign as a determinant of order 2, and its elements were four digits organised in a row and column. A determinant is an arrangement in which the coefficients of the equations are written in the way mentioned above. Horizontal lines are known as rows, while vertical lines are known as columns in a determinant. Every determinant has a square shape. There are n rows and n columns in a determinant of order n.
There is a number called the determinant of a square matrix that is associated with every square matrix A of order n x n.
- The determinant of a 1 x 1 matrix is A = [a].
- The determinant of a 2 x 2 matrix is:
The determinant of a 3 x 3 matrix is:
\(A = \begin{bmatrix}a & b \\[0.3em]c & d \\[0.3em] \end{bmatrix}\)= |A| = ad – bc
To find the determinant of a 3 X 3 matrix, do the following:
\(A = \begin{bmatrix}a & b & c\\[0.3em]d & e & f \\[0.3em]g & h &i \\[0.3em] \end{bmatrix}\) = a\(\begin{bmatrix}e & f \\[0.3em]h & i \\[0.3em] \end{bmatrix}\) – b\(\begin{bmatrix}d & f \\[0.3em]g & i \\[0.3em] \end{bmatrix}\) + c\(\begin{bmatrix}d & e \\[0.3em]g &h \\[0.3em] \end{bmatrix}\)
- Multiply a by the determinant of the 2 X 2 matrix that isn't in the same row or column as a.
- Similarly, for b and c.
- Add them up, but keep in mind the minus sign in front of the b.
The determinant of a 4 X 4 matrix is:
\(\begin{bmatrix}a & b & c & d\\[0.3em]e & f & g & h \\[0.3em]i & j & k & l \\[0.3em]m & n & o & p \\[0.3em] \end{bmatrix}\)= |A| = a.\(\begin{bmatrix}f & g&h\\[0.3em]j & k&l \\[0.3em] n & o&p\\[0.3em] \end{bmatrix}\) – b . \(\begin{bmatrix}e & g&h\\[0.3em]i & k&l \\[0.3em] m & o&p\\[0.3em] \end{bmatrix}\) + c . \(\begin{bmatrix}e & f&h\\[0.3em]i & j&l \\[0.3em] m & n&p\\[0.3em] \end{bmatrix}\) – d . \(\begin{bmatrix}e & f&g\\[0.3em]i & j&k \\[0.3em] m & n&o\\[0.3em] \end{bmatrix}\)
For 4X4 matrices, the pattern is, plus times the determinant of the matrix that is not in a's row or column, minus b times the determinant of the matrix that is not in b's row or column, plus c times the determinant of the matrix that is not in c's row or column, minus d times the determinant of the matrix that is not in the respective column or row (d).

Differentiation and Integration
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Determinants Detailed Video Explanation:
Read More: Minors and Cofactors of Determinant
Integration of Determinants
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Integration is the inverse operation, while differentiation is one of the two main operations in calculus. The following equation can be used to represent a function f(x) of a real variable x and an interval a, b of the real line:
∫ba f (x) dx
The signed area of the region in the xy-plane that is limited by the graph of f(x), the vertical lines(x = a and x = b), and the x-axis can be stated informally. The area below the x-axis subtracts from the total, whereas the area above the x-axis adds.
As a result, the term integral also refers to the anti-derivative, which is a function f(x) whose derivative is the provided function. This is known as an indefinite integral, and it's expressed like this: F (x) = ∫ f (x) dx
If f(x) is a continuous real-valued function defined on a closed interval a,b, then definite integrals are related to differentiation. As a result, the definite integral of f over that interval can be calculated as follows:
∫baf (x) dx = [F (x) ] ba = F(b) – F(a)
Integration of determinants is given by for example if f(x), g(x), and h(x) are functions of x, and a, b, c, l, m, n and are constants, then:

Integration of determinants
Read More: Definite, Indefinite and Methods of Integration
Differentiation of Determinants
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Differentiation is a derivative of an independent variable's value that can be used to calculate characteristics in an independent variable per unit change.
Let, a function of x, be y = f(x).
The rate of change of "y" per unit change in "x" is then calculated as follows:
dy/dx
Differentitation of determinants is done by, for example, f1, f2, f3, g1, g2, g3, h1, h2, h3 are functions of the same variable, then.

Differentitation of determinants
Read More: Inverse Matrix Formula
Things to Remember
- A determinant is a scalar value derived from square matrix members. There are n rows and n columns in a determinant of order n.
- If the rows and columns are switched around, the determinant value remains unchanged. If any two rows or columns of a determinant are swapped, the sign of the determinant changes. If a determinant's two rows or columns are identical, the determinant is 0.
- The determinant can be stated as the sum of two or more determinants if some or all elements of a row or column are expressed as the sum of two or more terms.
- Differentiation is a derivative of an independent variable's value that can be used to calculate characteristics in an independent variable per unit change.
- Let, a function of x, be y = f(x). The rate of change of "y" per unit change in "x" is then calculated as dy/dx
- Integration is the inverse operation, while differentiation is one of the two main operations in calculus. The following equation can be used to represent a function f(x) of a real variable x and an interval a, b of the real line as ∫f(x)dx.
Also Read:
Sample Questions
Ques. What will be the xΔdx for a given determinant whose limits are 0∫∏/4 \(\begin{bmatrix}- csc^2 x & sec^2 x & sin2 x \\[0.3em]3 & 2 & 1 \\[0.3em]4 & 1 & 0 \\[0.3em] \end{bmatrix}\)(3 Marks)
Ans. Δ(x) = \(\begin{bmatrix}- csc^2 x & sec^2 x & sin2 x \\[0.3em]3 & 2 & 1 \\[0.3em]4 & 1 & 0 \\[0.3em] \end{bmatrix}\)
0∫∏/4Δ (x)dx
=\(\begin{bmatrix} \int^{\prod /4}_ 0- csc^2 xdx & \int^{\prod /4}_ 0sec^2 xdx & \int^{\prod /4}_ 0sin2 xdx \\[0.3em]3 & 2 & 1 \\[0.3em]4 & 1 & 0 \\[0.3em] \end{bmatrix}\)
= \(\begin{bmatrix}1 & 1 & \frac{1}{2} \\[0.3em]3 & 2 & 1 \\[0.3em]4 & 1 & 0 \\[0.3em] \end{bmatrix}\)
= – 1 + 4 + 5/2
= – 11/2
Ques. Given that: \(\begin{bmatrix}x^2 & 6x & x \\[0.3em]1 & 5 & 0 \\[0.3em]- 2 & 3 & x+1 \\[0.3em] \end{bmatrix}\)Find the value of \(\int_0^1 \bigtriangleup (x) dx\). (3 Marks)
Ans. Δ(x) = \(\begin{bmatrix}x^2 & 6x & x \\[0.3em]1 & 5 & 0 \\[0.3em]- 2 & 3 & x+1 \\[0.3em] \end{bmatrix}\)
\(\int_0^1 \bigtriangleup (x) dx = \int _0^1 [ \frac{5x^4}{4} - \frac{x^2}{3} + \frac{8x^2}{2} - 6x] + c\)
By substituting the limit values,
= 5/4 = ⅓ + 4 – 6
= 5/4 – 1/3 – 2
= – 13/12
= \(\int_0^1 \bigtriangleup (x) dx\)
= x2((5x+5)-0) - 6x((x+1)-0) + x(3-(-5))
= x2(5x+5) - 6x((x+1) + x(3+5)
= 5x3 + 5x2 - 6x2 – 6 +8x
= 5x3 – x2 +8x – 6
Ques. What do you understand by the term determinant? (2 marks)
Ans. A determinant is defined as a specific scalar feature overall rectangular matrices that are distributive over matrix expansion, multilinear inside the queues and sections, and takes the fee of one for the unit matrix. The abbreviation for a determinant is “det”.
Ques. What will be the value of the determinant: \(\begin{bmatrix}6 & 2\\[0.3em]5 &3\\[0.3em]\end{bmatrix}\) (3 Marks)
Ans. The value of the determinant will be calculated as follows;
Δ(x) =
(6 x 3) - (5 x 2) = 8
Ques. If \(f (x) = \begin{bmatrix}1 & 2a\\[0.3em]x &2x^2\\[0.3em]\end{bmatrix}\), find the value of f’(x). (3 Marks)
Ans. Given that\(f (x) = \begin{bmatrix}1 & 2a\\[0.3em]x &2x^2\\[0.3em]\end{bmatrix}\)
Since, dΔ(x)/dx is the sum of the n determinant that is obtained by differentiating the elements of one row of Δ(x) and leaving the elements of other (n−1) rows unaltered
Therefore, \(f (x) = \begin{bmatrix}0 & 0\\[0.3em]x &2x^2\\[0.3em]\end{bmatrix} +\begin{bmatrix}1 & 2a\\[0.3em]1 &4x\\[0.3em]\end{bmatrix}\)
= f’(x) = 0 + 4x – 2a
= f’(x) = 4x – 2a
= f’(a) = 4a – 2a
= f’(a) = 2a
Ques. If Δ(x) = \(\begin{bmatrix}x & x^2 & x^3\\[0.3em]1 & 2 &3x \\[0.3em]0 & 2 & 5x \\[0.3em] \end{bmatrix}\), where a is any constant, then find the derivative of Δ(x). (3 Marks)
Ans. Given that
Δ(x) =\(\begin{bmatrix}x & x^2 & x^3\\[0.3em]1 & 2 &3x \\[0.3em]0 & 2 & 5x \\[0.3em] \end{bmatrix}\)
Since, dΔ(x)/dx is the sum of the n determinant that is obtained by differentiating the elements of one row of Δ(x) and leaving the elements of other (n−1) rows unaltered
Therefore,
dΔ(x)/dx =\(\begin{bmatrix}1 & 2x & 3x^2\\[0.3em]1 & 2 &5x \\[0.3em]0 & 2 & 5x \\[0.3em] \end{bmatrix}\) + \(\begin{bmatrix}x & x^2 & x^3\\[0.3em]0 & 0 & 3 \\[0.3em]0 & 2 & 5x \\[0.3em] \end{bmatrix}\)+ \(\begin{bmatrix}x & x^2 & x^3\\[0.3em]1 & 2 &3x \\[0.3em]0 & 0 & 5 \\[0.3em] \end{bmatrix}\)
dΔ(x)/dx = 4x(1–x)+(–6x)+5x(2–x)
dΔ(x)/dx =4x–4x2–6x+10x–5x2
dΔ(x)/dx = 9x2 + 8x
Ques. What will be the coefficient of x in the expansion of the given? \(\begin{bmatrix}(1 - x)^{22} & (1 - x)^{44} & (1 - x)^{66}\\[0.3em](1 - x)^{33} & (1 - x)^{66} & (1 - x)^{99}\\[0.3em](1 - x)^{44} & (1 - x)^{88} & (1 - x)^{144}\\[0.3em] \end{bmatrix}\)(3 Marks)
Ans. Let us consider that
f(x)=\(\begin{bmatrix}(1 - x)^{22} & (1 - x)^{44} & (1 - x)^{66}\\[0.3em](1 - x)^{33} & (1 - x)^{66} & (1 - x)^{99}\\[0.3em](1 - x)^{44} & (1 - x)^{88} & (1 - x)^{144}\\[0.3em] \end{bmatrix}\)
Since f(x) is a polynomial, therefore
f(x) = A0+A1x+Ax2+⋯+A232x232
Coefficient of x =f′ (0)=A1
Differentiating both sides with respect to x and putting x=0 on both sides,
f’ (0) = \(\begin{bmatrix}22 & 44 & 66\\[0.3em]1 & 1 &1 \\[0.3em]1 & 1 & 1 \\[0.3em] \end{bmatrix}\) + \(\begin{bmatrix}1 & 1 &1 \\[0.3em]33 & 66 & 99\\[0.3em]1 & 1 & 1 \\[0.3em] \end{bmatrix}\)+ \(\begin{bmatrix}1 & 1 &1 \\[0.3em]1 & 1 & 1 \\[0.3em] 44 & 88 & 144\\[0.3em]\end{bmatrix}\)
If two rows of a determinant are identical, then, we know that the value of the determinant is zero.
f′ (0) = 0+0+0=0
Coefficient of x in the given determinant is 0.
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