For the given circuit, at steady state, the Ampere Maxwell Law can be modified to:

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For the given circuit, at steady state, the Ampere Maxwell Law can be modified to

We know that Ampere Maxwell Law is given by,

∮→B.→dl=μ0(ic+id)=μ0(ic+ϵ0dϕEdt)

For the given circuit, at a steady state, the capacitor act as an open switch, therefore conduction current is zero.

Also, the electric field between the plates of the capacitor is constant at a steady state, which means the electric flux is constant. Therefore, the displacement current is also zero.

So, the Ampere Maxwell Law will be ∮→B.→dl=0.

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