NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.1

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NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volume Exercise 13.1 Solutions are based on the following concepts:

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CBSE X Related Questions

  • 1.
    D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.


      • 2.
        If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

          • 3
          • –3
          • –4
          • \(\pm 3\)

        • 3.
          If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

            • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
            • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
            • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
            • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

          • 4.
            The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

              • 0
              • 1
              • 3
              • 2

            • 5.
              The HCF of 960 and 432 is :

                • 48
                • 54
                • 72
                • 36

              • 6.
                In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.

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