NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.5 Solutions

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NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volume Exercise 13.5 Solutions are based on all the topics covered in the chapter, surface areas and volumes. 

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Exercise Solutions of Class 10 Maths Chapter 13 Surface Areas and Volume

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CBSE X Related Questions

  • 1.
    A circle centered at (2, 1) passes through the points A(5, 6) and B(-3, K). Find the value(s) of K. Hence find length of chord AB.


      • 2.
        In the given figure, \(AB \parallel DE\) and \(AC \parallel DF\). Show that \(\triangle ABC \sim \triangle DEF\). If \(BC = 10\) cm, \(EB = CF = 5\) cm and \(AB = 7\) cm, then find the length DE.


          • 3.
            PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


              • 4.
                The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

                  • 0
                  • 1
                  • 3
                  • 2

                • 5.
                  If the quadratic equation \(9x^2 + 8kx + 16 = 0\) has real and equal roots, then the value of k is

                    • 3
                    • –3
                    • –4
                    • \(\pm 3\)

                  • 6.
                    If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then

                      • \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
                      • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
                      • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
                      • \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)

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