NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.3 Solutions

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NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volume Exercise 13.3 Solutions are based on the following concepts:

  • Height of the cylinder based on given condition
  • Radius of the resulting sphere
  • Number of cones for a given situation.
  • Number of coins formed by melting a cuboid structured object.

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CBSE X Related Questions

  • 1.
    If for a data, median is 5 and mode is 4, then mean is equal to :

      • 7
      • 11
      • \(\frac{11}{2}\)
      • \(\frac{14}{3}\)

    • 2.
      The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

        • 2
        • \(-6\)
        • \(-2\)
        • 6

      • 3.
        In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

          • $6$
          • $4$
          • $\pm 4$
          • $3$

        • 4.
          If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

            • \(4 \text{ cm}\)
            • \(4\sqrt{2} \text{ cm}\)
            • \(8 \text{ cm}\)
            • \(2\sqrt{2} \text{ cm}\)

          • 5.
            If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

              • \( -\frac{2}{3} \)
              • \( \frac{2}{3} \)
              • \( \frac{1}{3} \)
              • \( -\frac{1}{3} \)

            • 6.
              In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

                • $55^\circ$
                • $20^\circ$
                • $35^\circ$
                • $70^\circ$

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