NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.2 Solutions

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NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volume Exercise 13.2 Solutions are based on Volume of Combination of Solids.

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CBSE X Related Questions

  • 1.
    In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).


      • 2.
        \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

          • \(\frac{21}{4} \text{ cm}\)
          • \(\frac{28}{3} \text{ cm}\)
          • \(\frac{12}{7} \text{ cm}\)
          • \(5.5 \text{ cm}\)

        • 3.
          Prove that: $\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta$


            • 4.
              The natural number 1 is :

                • a prime number.
                • a composite number.
                • prime as well as composite.
                • neither prime nor composite.

              • 5.
                If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

                  • $x^2 + 5x - 4$
                  • $(x + 3) (-x + 8)$
                  • $a(x^2 + 5x - 24)$
                  • $x^2 - 24$

                • 6.
                  A chord of a circle, of radius 14 cm, subtends an angle of $60^\circ$ at the centre. Find the area of the smaller sector and perimeter of the smaller segment.

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