NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.4 Solutions

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NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volume Exercise 13.4 Solutions are based on the following concepts:

  • Height of the cylinder based on given condition
  • Radius of the resulting sphere
  • Number of cones for a given situation.
  • Number of coins formed by melting a cuboid structured object.

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CBSE X Related Questions

  • 1.
    The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

      • $q - 9p$
      • $p - 9q$
      • $p + 9q$
      • $2p + 9q$

    • 2.
      The HCF of 960 and 432 is :

        • 48
        • 54
        • 72
        • 36

      • 3.
        \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

          • \(\frac{21}{4} \text{ cm}\)
          • \(\frac{28}{3} \text{ cm}\)
          • \(\frac{12}{7} \text{ cm}\)
          • \(5.5 \text{ cm}\)

        • 4.
          PQ and PR are two tangents to a circle with centre O and radius 5 cm. AB is another tangent to the circle at C which lies on OP. If \(OP = 13\) cm, then find the length AB and PA.


            • 5.
              If the zeroes of a polynomial p(x) are $-3$ and 8, then p(x) equals

                • $x^2 + 5x - 4$
                • $(x + 3) (-x + 8)$
                • $a(x^2 + 5x - 24)$
                • $x^2 - 24$

              • 6.
                Prove that :
                \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).

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