Water Pressure: Concept, Formula, Equation

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Water pressure is defined as the force applied perpendicular to the surface of the object per area over which the force is distributed. The gauge pressure is the pressure in relation to the surrounding atmosphere. Pressure is expressed using a variety of units. Pascal is the SI unit of pressure (Pa). Water pressure, on the other hand, is a term used to describe the force of water flowing through a channel or pipe.

Key Takeaways: water pressure, force, density of water, fluid, weight, area


Concept of water pressure

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It is true for both liquids and gases because they are both fluids, yet the pressure in a liquid differs slightly from that of a gas. Because liquids do not fill the full container like gases do, we can clearly see that this is not the case.

This is due to the bonds that exist between the liquid's molecules. When we pour a liquid into a container, gravity pulls it down, so it fills the bottom first. The gravitational force will be the same as our scale reading. It is the weight of the liquid that causes pressure in that liquid.

Concept of water pressure

Also, because of gravity, the pressure in the liquid increases with depth. The bottom liquid must support the weight of all the liquid above it, as well as the weight of air above it. When we swim at the bottom of a pool, we can feel the difference in pressure. The pressure grows as we travel further underwater because there is more and more weight on top of us.

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Water Pressure Formula

The formula for calculating water pressure is as follows:

P = ρgh

Where,

P = water pressure in Pa

ρ = density of water in kg.m-3

g = gravitational force in 9.81 m.s-2

h = height in m

Water Pressure Calculation Formula

Water Pressure Calculation Formula

The height of the container is 'h,' and the area is A. 

The bottom of the container supports the complete weight of the water in it. The vertical sides, on the other hand, cannot exert an upward force on the fluid since it is not strong enough to withstand a shearing force, which is why the bottom supports everything.

As can be seen, the container's bottom supports the weight of the fluid inside, which is given as:

w = mg

We also know that the pressure is equal to the weight of the fluid mg divided by the area of the container's bottom (here, A is the area of the container's bottom, which is given by:

P = mg/A      …(1)

The mass of the fluid is given as:

m= ρV      …(2)

The volume of the fluid inside the container is given as:

V= Ah      …(3)

Here, 

A= cross-sectional area

h= depth

The water pressure calculator by height is obtained by entering the values of (2) and (3) in (1):

P  =  ρAhg/A

P  =  ρgh

This equation can be used to compute a fluid's water pressure.

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Water Pressure Equation

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The water pressure equation is valid in a wide range of situations other than those in which it is derived here. If the container were not present, the surrounding fluid would still exert this pressure, causing the fluid to remain static.

As a result, the equation P =  ρhg denotes the pressure exerted by the weight of any fluid with an average density  ρ of at any depth h below its surface.

The pressure underwater formula still remains true to great depths for liquids that are almost incompressible.

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Points to Remember

  • Pressure is defined as a force exerted perpendicular to the object's surface.
  • Assume that someone is swimming underwater. The deeper the swimmer swims tThe greater the water pressure.
  • Because of gravity, the pressure in the liquid increases with depth.
  • The density of the liquid also affects the water pressure.

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Sample Questions

Ques: A water tank with a 5 m height is filled with water. Compute the pressure at the bottom using the water pressure formula. (3 Marks)

Ans: Given,

Density of water= 1000 kg/m3

g= 10 m/s2

Height = 5 m

The water pressure on the tank will be 

P  =  ρgh

P = 1000 x 5 x 10

P = 50,000 Pa

Ques: A water tank with a 6.2 m height is filled with water. Compute the pressure at the bottom using the water pressure formula. (3 Marks)

Ans: Given,

Density of water= 1000 kg/m3

g= 10 m/s2

Height = 6.2 m

The water pressure on the tank will be 

P  =  ρgh

P = 1000 x 6.2 x 10

P = 62000 Pa

Ques: A water tank with a 0.8 m height is filled with water. Compute the pressure at the bottom using the water pressure formula. (3 Marks)

Ans: Given,

Density of water= 1000 kg/m3

g= 10 m/s2

Height = 0.8 m

The water pressure on the tank will be 

P  =  ρgh

P = 1000 x 0.8 x 10

P = 8000 Pa

Ques: The height of a waterfall is 200 metres. Calculate how much pressure is lost when it reaches the surface. (2 Marks)

Ans: Given:

Density of water, ρ = 1000 kg/m3

g = 9.8 m/s2

h = 200 m

The formula for calculating pressure loss is as follows : 0.4335 ×200 = 86.7 Pa.

Ques: The height of a waterfall is 240 metres. Calculate how much pressure is lost when it reaches the surface. (2 Marks)

Ans: Given:

Density of water, ρ = 1000 kg/m3

g = 9.8 m/s2

h = 240 m

Pressure loss = 0.4335 x h = 0.4335 × 240 = 104.04 Pa.

Ques: The height of a waterfall is 140 metres. Calculate how much pressure is lost when it reaches the surface. (2 Marks)

Ans: Given:

Density of water, ρ = 1000 kg/m3

g = 9.8 m/s2

h = 140 m

Pressure loss = 0.4335 x h = 0.4335 × 140 = 60.69 Pa.

Ques: The height of a waterfall is 40 metres. Calculate how much pressure is lost when it reaches the surface. (2 Marks)

Ans: Given:

Density of water, ρ = 1000 kg/m3

g = 9.8 m/s2

h = 40 m

Pressure loss = 0.4335 x h = 0.4335 × 40 = 17.34 Pa.

Ques: The height of a waterfall is 25 metres. Calculate how much pressure is lost when it reaches the surface. (2 Marks)

Ans: Given:

Density of water, ρ = 1000 kg/m3

g = 9.8 m/s2

h = 25 m

Pressure loss = 0.4335 x h = 0.4335 × 25 = 10.8 Pa.

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CBSE CLASS XII Related Questions

  • 1.
    The resistance of a metal wire at \( 20^\circ \text{C} \) is \( 1.05 \, \Omega \) and at \( 100^\circ \text{C} \) is \( 1.38 \, \Omega \). Determine the temperature coefficient of resistivity of this metal.


      • 2.
        An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.


          • 3.
            Two metal spheres of radii $r_1$ and $r_2$ ($> r_1$) having charges $q_1$ and $q_2$ respectively kept in air, are brought in contact. Which of the following statements is not correct ?

              • The total charge of the two spheres is conserved.
              • Both spheres attain the same potential.
              • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2)}{(r_1 + r_2)}$
              • The final potential of the system equals $\frac{1}{4\pi\epsilon_0} \frac{(q_1 + q_2) (r_1 + r_2)}{r_1 r_2}$

            • 4.
              Read the following paragraph and answer the questions that follow.
              In an experiment with convex lens of focal length f, the screen is fixed at a distance D from the object. A student slowly moves the lens away from the object towards the screen and finds that she is able to form sharp image of the object for two positions of the lens. The distance between these two positions of the lens is d.


                • 5.
                  Write two advantages of reflecting telescope over refracting telescope.


                    • 6.
                      This ‘average velocity’ is found be few mm/s for currents in range of a few amperes. How then is current established almost the instant a circuit is closed ?

                        CBSE CLASS XII Previous Year Papers

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