CBSE Class 12 Chemistry Question Paper 2026 (Set 1 - 56/1/1) with Solutions is now available here for download. CBSE conducted the Class 12 Chemistry examination on February 28, 2026, from 10:30 AM to 1:30 PM.
CBSE Class 12 Chemistry paper is of total 100 marks out of which 70 marks are allocated to the theory paper and 30 marks are for practical examination.
Also Check: CBSE Class 12 Question Paper 2026 (All Subjects)
The theory paper consists of 33 questions divided into five sections:
- Section A contains Multiple Choice Questions (MCQs),
- Section B contains Very Short Answer Type (VSA) Questions,
- Section C contains Short Answer Type (SA) Questions,
- Section D contains Case-Study based Questions,
- Section E contains Long Answer (LA) Type Questions.
All sections are compulsory.
CBSE Class 12 Chemistry Question Paper 2026 (Set 1 - 56/1/1) with Solution PDF
| CBSE Official PDF | CD PDF | CD PDF with Solutions |
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CBSE Class 12 Chemistry 2026 Set 1 (56/1/1) Questions with Solutions
Which of the following solutions will have the lowest freezing point in water?
Which of the following is not a transition metal?
Which of the following represents the fraction of molecules with energies equal to or greater than \(E_a\)?
What will happen during the electrolysis of aqueous solution of \(CuCl_2\) by using platinum electrodes?
Aspirin is obtained by acetylation of
The secondary valency of Co in the complex \([Co(NH_3)_5(NO_2)]^{2+}\) is
At low temperature, phenol reacts with dil. \(HNO_3\) to yield
Which of the following is 'not' true about enantiomers?
Aniline on direct nitration yields
Which of the following amines has lowest \(pK_b\) value?
The deficiency of which of the following vitamins causes increased fragility of red blood cells and muscular weakness :
Assertion (A): It is not possible to separate the components of an azeotrope by fractional distillation.
Reason (R): Components of an azeotrope have the same composition in liquid and vapour phase and boil at a constant temperature.
Assertion (A): The presence of −OH group in phenols directs the incoming group to meta position in the ring.
Reason (R): −OH group in phenols activates the aromatic ring towards electrophilic substitution reaction.
Assertion (A): Actinoids show wide range of oxidation states.
Reason (R): Actinoids are radioactive in nature.
Assertion (A) : The pentaacetate of glucose does not react with \( \mathrm{H_2N-OH} \).
Reason (R) : It indicates the presence of free \( \mathrm{-CHO} \) group in glucose.
What type of deviation from Raoult's law is shown by a mixture of phenol and aniline? Give reason.
What will happen to the boiling point of the solution on mixing phenol and aniline?
Why are haloarenes less reactive towards nucleophilic substitution reaction? Give two reasons.
Write IUPAC names of the following coordination compounds:
(i) \([Ag(NH_3)_2][Ag(CN)_2]\)
(ii) \(K_3[Fe(C_2O_4)_3]\)
(i) Give a chemical test to show that \([Co(NH_3)_5SO_4]Cl\) and \([Co(NH_3)_5Cl]SO_4\) are ionisation isomers.
(ii) What is meant by the 'Chelate effect'? Give an example.
Differentiate between the following :
(i) Peptide linkage and Glycosidic linkage
(ii) Essential amino acids and Non-essential amino acids
Following reaction takes place in one step:
\(2A + B \rightarrow 2C\)
How will the rate of above reaction change if the volume of the reaction vessel is decreased to one third of its original volume? Will there be any change in the order of reaction with the reduced volume?
For the first order thermal decomposition reaction, following data was obtained :
\(C_2H_5Cl(g) \rightarrow C_2H_4(g) + HCl(g)\)
Calculate rate constant.
[Given : log 3 = 0.48]
Answer the following:
(i) Why is the Equilibrium Constant \(K_c\) related to \(E^\circ_{cell}\) and not to \(E_{cell}\)?
(ii) Two metals 'A' and 'B' have standard electrode potential values of \(-0.24\) V and \(+0.80\) V respectively. Which of these will liberate hydrogen gas from dil. \(H_2SO_4\)?
(iii) Write the cell reaction which occurs in lead storage battery when it is in charging.
What type of battery is Mercury cell? Why it is more advantageous than dry cell? Write overall reaction taking place in Mercury cell.
Calculate the boiling point of a solution containing 0.61 g of benzoic acid (Molar mass = 122 g mol\(^{-1}\)) in 5 g of \(CS_2\) in which it dimerises to the extent of 88%. The boiling point and \(K_b\) of \(CS_2\) are 46.2 \(^\circ C\) and 2.3 K kg mol\(^{-1}\) respectively.
Write the reactions of D-Glucose with the following:
(a) HI
(b) \(Br_2\) water
(c) Conc. \(HNO_3\)
Give reason for the following:
Nucleophilic addition of ammonia and its derivatives does not occur with carbonyl group in strongly acidic medium.
Nucleophilic addition of ammonia and its derivatives does not occur with carbonyl group in strongly acidic medium.
Give reason for the following:
Carboxylic acids have higher boiling point than alcohols of comparable molecular masses.
Give reason for the following:
Alpha (\(\alpha\)) hydrogens of aldehydes and ketones are acidic in nature.
Write the reaction involved in the following:
Reimer-Tiemann reaction
Write the reaction involved in the following:
Kolbe's reaction
Write the reaction involved in the following:
Friedel-Crafts acylation of anisole
Compound 'X' with molecular formula \(C_4H_9Br\) reacts with aqueous KOH to give an alcohol. The rate of this reaction depends only on the concentration of the compound 'X'. When an optically active isomer 'Y' of the compound 'X' was treated with aqueous KOH solution, the rate of reaction was found to be dependent on concentration of compound 'Y' and aqueous KOH both.
(a) Write down the structural formula of both 'X' and 'Y'.
(b) Out of 'X' and 'Y', which one will undergo racemisation and why?
(c) Out of 'X' and 'Y', which one will form product with inversion of configuration and why?
The reaction of amines with mineral acids to form ammonium salts shows that these are basic in nature. Aliphatic amines are stronger bases than ammonia whereas aromatic amines are weaker bases than ammonia. Aliphatic and aromatic primary and secondary amines react with acid chlorides, anhydrides and esters by nucleophilic substitution reaction. The main problem encountered during electrophilic substitution reactions of aromatic amines is that of their high reactivity. Substitution tends to occur at ortho-and para-positions. Hinsberg reagent is used for the identification and distinction between primary, secondary and tertiary amines. Aryldiazonium salts, usually obtained from arylamines, undergo replacement of the diazonium group with a variety of nucleophiles to provide advantageous methods for producing aryl halides, cyanides, phenols and arenes.
30(a)(i).
Why \(CH_3 - NH_2\) is a stronger base than \((CH_3)_3N\) in aqueous solution?
Write structural formulae of the compound A and B:
\(CH_3CONH_2 \xrightarrow{NaOBr} A \xrightarrow[Base]{C_6H_5COCl} B\)
A compound ‘X’ with molecular formula \(C_3H_9N\) reacts with Hinsberg reagent to give a product insoluble in alkali. Identify ‘X’.
Why is \(-NH_2\) group of aniline acetylated before carrying out nitration?
The reaction of amines with mineral acids to form ammonium salts shows that these are basic in nature. Aliphatic amines are stronger bases than ammonia whereas aromatic amines are weaker bases than ammonia. Aliphatic and aromatic primary and secondary amines react with acid chlorides, anhydrides and esters by nucleophilic substitution reaction. The main problem encountered during electrophilic substitution reactions of aromatic amines is that of their high reactivity. Substitution tends to occur at ortho-and para-positions. Hinsberg reagent is used for the identification and distinction between primary, secondary and tertiary amines. Aryldiazonium salts, usually obtained from arylamines, undergo replacement of the diazonium group with a variety of nucleophiles to provide advantageous methods for producing aryl halides, cyanides, phenols and arenes.
Answer the following question :
(b) How can you convert aniline to benzonitrile ?
The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometry of coordination compounds. The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges), on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields. Answer the following questions :
29(a).
In octahedral crystal field, energies of which d-orbitals will be raised when ligands approach the central metal atom/ion ? Give reason in support of your answer.
\( [NiCl_4]^{2-} \) is paramagnetic while \( [Ni(CO)_4] \) is diamagnetic though both are tetrahedral. Why? [At. No. Ni=28]
The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometry of coordination compounds. The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges), on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields.
Answer the following question :
(b) Using crystal field theory, write the electronic configuration of central metal atom/ion of the following :
(i) \( \mathrm{[CoF_6]^{3-}} \)
(ii) \( \mathrm{[Co(NH_3)_6]^{3+}} \)
[At. No. : Co = 27]
The Valence Bond Theory (VBT) explains the formation, magnetic behaviour and geometry of coordination compounds. The Crystal Field Theory (CFT) of coordination compounds is based on the effect of different crystal fields (provided by the ligands taken as point charges), on the degeneracy of d-orbital energies of the central metal atom/ion. The splitting of the d-orbitals provides different electronic arrangements in strong and weak crystal fields.
Answer the following question :
(c) Write hybridization and magnetic behaviour of the complex \( \mathrm{[Fe(CN)_6]^{3-}} \).
[Atomic No. : Fe = 26]
An organic compound (X) has the molecular formula C5H10O. Draw structures for (X) if it: (I) does not give Tollen's test but gives a positive iodoform test; (II) does not give Tollen's test and iodoform test but undergoes Aldol condensation; (III) undergoes Cannizzaro's reaction.
Show how each of the following compounds can be converted to benzoic acid: (I) Acetophenone; (II) Ethyl benzene.
(b) Answer the following questions :
(i) Draw structure of the 2, 4-dinitrophenyl hyzdrazone derivative of benzaldehyde.
(ii) Arrange the following in increasing order of their reactivity towards HCN :
Di-tert. butyl ketone, Acetaldehyde, Acetone
(iii) Give a simple chemical test to distinguish between benzoic acid and ethyl benzoate.
(iv) Write the name of the reagent to convert Ethanenitrile to Ethanal.
(v) Draw the structure of 'X' in the following reaction :
What happens when acidic solution of potassium permanganate is allowed to stand for sometime ? Give the equation involved. What is this type of reaction called ?
(i) From the given data of \( E^\circ \) values, answer the following questions:
| M | V | Cr | Mn | Fe | Co | Ni | Cu |
| \( E^\circ_{\mathrm{M^{2+}/M}} \) | -1.18 | -0.91 | -1.18 | -0.44 | -0.28 | -0.25 | +0.34 |
(I) Why \( E^\circ_{\mathrm{M^{2+}/M}} \) show irregular trend in the above values?
(II) Why is \( E^\circ_{\mathrm{Cu^{2+}/Cu}} \) value exceptionally positive?
(III) Why \( E^\circ_{\mathrm{Mn^{2+}/Mn}} \) value is highly negative?
(ii) Write the ionic equations for the oxidising action of potassium permanganate for its reaction with \( \mathrm{I^-} \) in both acidic and alkaline solutions.
(b) Answer the following questions:
(i) Name a member of the lanthanoid series
(I) which exhibits +4 oxidation state
(II) which exhibits +2 oxidation state.
(ii) Why transition metals act as good catalyst?
(iii) Why Cr has higher melting point than Mn?
Calculate emf and \(\Delta G\) for the following cell at \(298 \text{ K}\) :
\(Mg(s) / Mg^{2+}(0.01 \text{ M}) // Ag^+(0.001 \text{ M}) / Ag(s)\)
Given : \(E^\circ_{Mg^{2+}/Mg} = -2.37 \text{ V}\), \(E^\circ_{Ag^+/Ag} = +0.80 \text{ V}\)
\([1 \text{ F} = 96500 \text{ C mol}^{-1}, \log 10 = 1]\)
For the reaction :
\(2AgCl(s) + H_2(g) (0.4 \text{ atm}) \rightarrow 2Ag(s) + 2H^+(0.1 \text{ M}) + 2Cl^-(0.2 \text{ M})\)
Calculate emf of the cell at \(25 \text{ } ^\circ\text{C}\).
Given : \(\Delta G^\circ = -43500 \text{ J mol}^{-1}\)
\([\log 10 = 1, 1 \text{ F} = 96500 \text{ C mol}^{-1}]\)
CBSE Class 12 Chemistry Question Paper Pattern and Marking Scheme
The CBSE Class 12 Chemistry 2026 question paper is of 70 marks and has 33 questions in five sections, A to E, all compulsory. The tables below give the section-wise paper pattern and the marking rules from the official CBSE marking scheme.
CBSE Class 12 Chemistry Question Paper Pattern 2026
| Section | Questions | Question Type | Marks per Question | Marks |
|---|---|---|---|---|
| A | Q1 - Q16 | Multiple choice questions | 1 | 16 |
| B | Q17 - Q21 | Very short answer type | 2 | 10 |
| C | Q22 - Q28 | Short answer type | 3 | 21 |
| D | Q29 - Q30 | Case-based questions | 4 | 8 |
| E | Q31 - Q33 | Long answer type | 5 | 15 |
| Total | 33 questions | 70 |
CBSE Class 12 Chemistry Marking Scheme 2026
| Marking point | How it is applied |
|---|---|
| Value-point marking | Marks are awarded against the value points (steps) given in the official marking scheme; the marks of an answer are split across its steps. |
| Own expression | The marking scheme carries suggested value points only. A correct answer in the student's own words is awarded due marks. |
| Competency-based questions | If a competency-based answer is not from the marking scheme but shows the correct competency, due marks are awarded. |
| Errors | An error is penalised only once; no marks are deducted for its cumulative effect. |
| Incorrect answer | A totally incorrect answer is awarded zero (0) marks. |
| Choice (OR) questions | If both options of a question with internal choice are attempted, marks are awarded for both and the higher score is taken; if only one option is attempted, the other is marked NA (not attempted). |
| Scale of marks | The full scale of 0 to 70 marks is used and full marks are awarded whenever the answer deserves them. |
CBSE Class 12 Chemistry Unit-Wise Weightage
| Unit No. | Unit Name | Marks |
|---|---|---|
| 1 | Solutions | 7 |
| 2 | Electrochemistry | 9 |
| 3 | Chemical Kinetics | 7 |
| 4 | d- and f-Block Elements | 7 |
| 5 | Coordination Compounds | 7 |
| 6 | Haloalkanes and Haloarenes | 6 |
| 7 | Alcohols, Phenols and Ethers | 6 |
| 8 | Aldehydes, Ketones and Carboxylic Acids | 8 |
| 9 | Amines | 6 |
| 10 | Biomolecules | 7 |
| Total | — | 70 |
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