Cells in Series and Parallel Important Questions

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Cells in series and parallel are the two ways of connection in a circuit. This topic has more weightage in Class 12 Chapter 3 Current Electricity. In a series connection, the cells are connected end to end whereas in a parallel connection, the cells are connected in parallel to one another. 

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Series and Parallel Circuit

Series and Parallel Circuit


Advantage of Parallel connection over Series connection

  • If any of the electrical components in a series connection gets disconnected, the entire circuit fails.
  • But this is overcome in a parallel circuit, where even if any of the components is broken, the rest of the circuit continues working.
  • This is why parallel circuits are used for domestic purposes so that even if any electrical device is disconnected, others continue to work.
  • In a parallel circuit, the internal resistance of the circuit is very minimal compared to the series combination.

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Important Questions on Combinations of cells in Series and Parallel

Ques. Batteries of 10V and 5 V are connected in series such that their emfs point in the same direction. Find the equivalent resistance for the system. (2 Marks)

Ans. The formula for equivalent series emf is given by,

Eeq = E1 + E2 + … 

Given

  • E1 = 10 V 
  • E2 = 5 V

Substituting these values in the equation, 

E = E1 + E2 

E = 10 + 5

E = 15 V

Ques. Batteries of 3, 5, and 10 ohms are connected in series such that their emfs point in the same direction. Find the equivalent resistance for the system. (2 Marks)

Ans. The formula for equivalent series emf is given by,

Eeq = E1 + E2 + E3 … 

Given

  • E1 = 3 V
  • E2 = 5 V
  • E3 = 10 V

Substituting these values in the equation, 

E = E1 + E2 + E3

E = 3 + 5 + 10 

E = 18 V

Ques. Batteries of 10V and 5 V are connected in series such that their emfs point in the same direction. The internal resistances of the batteries are 2 and 10 ohms respectively. Find the equivalent resistance for the system. (3 Marks)

Ans. The formula for equivalent series emf is given by,

Eeq = E1 + E2 + E3 … 

Given

  • E1 = 10 V
  • E2 = 5 V

Substituting these values in the equation, 

E = E1 + E2 

E = 10 + 5

E = 15 V

Equivalent resistance is also given by a similar equation, 

req = r1 + r2 + ….

  • r1 = 2 ohm
  • r2 = 10 ohm

substituting these values in the equation, 

r = r1 + r2 

⇒ r = 2 + 10

⇒ r = 12 ohms

Ques. Three batteries of internal resistances 2, 2, and 4 ohms are connected in parallel. Find the equivalent resistance for the system. (3 Marks)

Ans. Given

  • R1 = 2 ohm
  • R2 = 2 ohm
  • R3 = 4 ohm

The formula for equivalent resistance is given by,

\(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ......\)

Substituting these values in the equation, 

1/R = 1/2 + 1/2 + 1/4

1/R = (2+2+1)/4

1/R = 5/4

R = 4/5 ohm

Ques. Three batteries of internal resistances 5 ohm, 5 ohm, and 10 ohm, each of 10 V are connected in parallel. Find the equivalent resistance and emf for the system. (3 Marks)

Ans. 

Given

  • R1 = 5 ohm
  • R2 = 5 ohm
  • R3 = 10 ohm

The formula for equivalent resistance is given by,

\(\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ......\)

Substituting these values in the equation, 

1/R = 1/5 + 1/5 + 1/10

1/R = (2+2+1)/10

1/R = 5/10 = 1/2

R = 2 ohm

Now when n number of identical batteries are connected in parallel then equivalent emf is equal to the emf due to a single cell. Therefore

Eequivalent = 10 V

Ques. Why is it preferable to connect bulbs in parallel than in series? (2 Marks)

Ans. Bulbs are connected in parallel so that even if one of the bulbs is disconnected, the others continue to get a current supply.

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Ques. Calculate the total resistance between points A and B. (3 Marks)

Calculate the total resistance between points A and B

Ans. From figure, the equivalent resistance of 1 ohm and 2 ohm resistance is given vy

Equivalent resistance, 1/Req = 1/R1 + 1/R2 +....

1/Req = 1/1 + 1/2 

1/Req = (2+1)/2

1/Req = 3/2

Req = 2/3 

Total Resistance of the circuit = 4 + 3 + 2/3 = 23/3

Total Resistance of the circuit = 7.67 ohm

Ques. In which circuit, the total resistance is greater than the largest resistance in the circuit? (2 Marks)

Ans. In series circuits, the total resistance is the sum of all the resistance in the circuit, hence the total is greater than the largest resistance.

Ques. In which circuit, the total resistance is smaller than the smallest resistance in the circuit? (2 Marks)

Ans. In a parallel circuit, the equivalent resistance is the sum of the reciprocals of all the resistances in the circuit. Hence it is smaller than the smallest resistance in the circuit.

Ques. Which is the most cost-efficient connection? (2 Marks)

Ans. Series connection is the most cost-efficient connection, due to the following reasons.

  • Less wiring is needed.
  • Less space is needed.

Ques. What are the advantages of parallel connections? (2 Marks)

Ans. Some of the advantages of parallel connections are:

  • If any one of the cells connected in parallel is damaged or disconnected, the other cells are not affected.
  • If the cells are connected in parallel they will not exhaust easily.
  • It has less internal resistance.

Ques. What are the disadvantages of parallel connections? (2 Marks)

Ans. Some of the disadvantages of parallel connections are:

  • The voltage developed will not be increased by increasing the number of cells in the parallel combination.
  • The output power is based on one cell. Therefore, the brightness of the bulb connected will not be very high.

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CBSE CLASS XII Related Questions

  • 1.
    An electric field $\vec{E}$ is established across the ends of a cylindrical conductor of length L and area of cross-section A. Discuss how electrons attain an average velocity, independent of time. Hence, obtain a relation between current in the conductor and this ‘average velocity’ of electrons.


      • 2.
        A charged particle $+q$ in an electric field $\vec{E}$ experiences a force in the direction of the electric field. As a result, its kinetic energy changes. Similarly, the charged particle also experiences a force when it moves in a magnetic field $\vec{B}$. But this magnetic force is perpendicular to both velocity $\vec{v}$ of the charged particle and the magnetic field $\vec{B}$, so it cannot change the kinetic energy of the charged particle. Consider two charged particles 1 and 2 of masses $m$ and $\frac{m}{2}$ having charges $-q$ and $+2q$ respectively. They are accelerated from rest through the same potential difference $V$ and acquire kinetic energy $K_1$ and $K_2$. Then they enter in a region of uniform magnetic field $\vec{B}$ perpendicular to their velocities.


          • 3.
            A student sets up the circuit as shown in the figure to find the value of unknown resistance X and records a set of readings of the voltmeter and the ammeter by using the rheostat.


              • 4.
                An astronomical telescope consists of two converging lenses. One of them of large aperture and large focal length is called objective lens and the other one, of smaller focal length and smaller aperture is called the eyepiece. It is used to see distant objects which are not seen clearly with naked eyes. The image formed by the objective lens acts as an object for the eyepiece and the final image produced by the eyepiece is magnified.


                  • 5.
                    Write two advantages of reflecting telescope over refracting telescope.


                      • 6.
                        Two air-filled capacitors of capacitances $C_1$ and $C_2$ are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant K is inserted between the plates of each capacitor. How will the (i) charge on each capacitor and (ii) energy stored in the capacitor affected after the slab is introduced.

                          CBSE CLASS XII Previous Year Papers

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