Diffraction Grating Formula: Definition & Solved Examples

Collegedunia Team logo

Collegedunia Team

Content Curator

A diffraction grating can be expressed as an optical component with a periodic structure that splits light into multiple beams traveling in different directions. Making several parallel scratches on the surface of a flat piece of transparent material results in a diffraction grating. 

  • When light strikes a diffraction grating, it multiplies for the source with parallel slits.
  • An example includes when a flat piece of transparent material is scratched with numerous parallel lines to create a diffraction grating. 
  • The material is susceptible to several scratches per centimeter.
  • For instance, the grating used will have 6,000 lines per cm.
  • Although the scratches are opaque, the gaps between them let light through.
  • Light creates a multiplicity for the source with a parallel slit when it hits a diffraction grating.

Read Also: Resolving Power of Microscopes and Telescopes

Key Terms: Diffraction, Diffraction Grating, Spectra, Light, Prism, Interference, Wavelength, Slits


What is Diffraction Grating?

[Click Here for Sample Questions]

A periodic optical element called a diffraction grating divides light into several beams that go in various directions. It serves as an alternative method for studying spectra to prisms

  • The divided light will frequently have maxima at an angle when light reaches the grating.
  • On the grating, the rays will land in a parallel bundle. 
  • Since the rays and wavefront are an orthogonal set, the wavefront will be perpendicular to the rays and parallel to the grating. 
  • In this situation, Huygens' Principle is applicable.
  • It states that every point on a wavefront and each transparent slit operate as new sources, causing cylindrical wavefronts to expand out from each.
  • The waves cancel if a peak hits a valley repeatedly, therefore there is no light there. 
  • Additionally, the light appears stronger where valleys frequently fall into peaks and peaks fall into valleys. 
  • An alternative to using a prism to find spectra is diffraction.

Read Also:


Diffraction Grating Formula

[Click Here for Previous Year Questions]

Take into account two rays that form an angle with a straight line as they emerge. If the difference between their two path lengths is an integral multiple of their wavelength, or in other words if there is constructive interference,

Then, the Diffraction Grating Formula can be expressed as, 

nλ = d sinθn

Where,

  • n = order of grating (n = 1, 2, 3)
  • d = distance between two fringes or spectra
  • λ = wavelength of light
  • θ = angle to maxima

Note: A grating element is also the distance between two successive slits (lines) of the grating. Calculated for grating element "d". Thus, the Grating element, d = Grating length/Line count. 

Read Also: Brewster's Law Formula


Solved Examples

Ques. Light is diffracted at 20o by a diffraction grating. If there are 2000 lines per millimeter of grating length, what will the wavelength of the light be?

Ans. Given the conditions are,

  • θ = 20o.
  • N = 2000 lines per millimeter 

⇒ Thus, d =1/N

⇒ d = 1/2000 mm

⇒ d = 0.5 x 10−6 m.

For n =1,

Using the formula  λn = dSinθn, (by setting n to 1)

λ = 0.5 x 10− 6 × sin 20o

λ = 0.17 × 10− 6 m = 1.7 x 10-7 m

Therefore, the wavelength will be 1.7 x 10-7​ m.

Ques. Light is diffracted at 30o by a diffraction grating. If there are 1000 lines per millimeter of grating length, what will the wavelength of the light be?

Ans. Given the conditions are,

  • θ = 30o.
  • N = 1000 lines per millimeter 

⇒ Thus, d =1/N

⇒ d = 1/1000 mm

⇒ d =  10−6 m.

For n =1,

Using the formula  λn = dSinθn, (by setting n to 1)

λ = 10− 6 × sin 30o

λ = 10− 6 x 0.5 m

Therefore, the wavelength will be 0.5 x 10-6​ m.


Previous Year Questions


Things to Remember 

  • When a diffraction grating is lit by a wide-spectrum (for instance, continuous light source), the colors of "rainbow" can be produced. 
  • A diffraction grating is a periodic optical element used in optics that divides light into many beams that go in various directions (i.e., different diffraction angles). 
  • The rays will fall in a parallel bundle on the grating. The wavefront will be perpendicular to the rays and parallel to the grating since the rays and wavefront constitute an orthogonal set. In this case, Huygens' Principle is relevant. 
  • When light strikes a diffraction grating, it multiplies for the source with a parallel slit.

Also Read:


Sample Questions

Ques. What is Diffraction Grating? (1 mark)

Ans. Diffraction grating can be expressed as a periodic optical element that divides light into several beams that go in various directions.

Ques.Light is diffracted at 20 by a diffraction grating. If there are 1000 lines per millimeter of grating length, what will the wavelength of the light be? (3 marks)

Ans: Given conditions are,

Θ = 20∘.

1000 lines per millimeter 

⇒ Thus, d =1/N

⇒ d = 1/1000 mm

⇒ d = 10−6 m.

for n =1,

Using the formula  λn = dSinθn, (by setting n to 1)

= 10− 6 × sin20o

= 3.4 × 10− 5 m

Therefore, the wavelength will be 3.4 x 105 m.

Ques.Find the slit spacing for a diffraction grating with a 2 cm width that exhibits a 30° second-order deviation when illuminated by light with a 500 nm wavelength. (3 marks)

Ans: As per the question,

n = 2 is the order.

The deviation's angle, = 30°, and

The wavelength is 500 nm or 500 10-9 meters.

Using the diffraction grating formula, this follows:

nλ = d sin θ

2 × 500 × 10-9 m = d × sin 30°

d = 2 × 10-6

Ques. Monochromatic light illuminates a grating with 5000 slits per centimeter, which creates the second-order brilliant line at a 30° angle. Identify the light's used wavelength. (1 Å = 10-10 m) (3 marks)

Ans: n = 2 is the order.

The deviation's angle, = 30°, and

N = 5000, number of slits per cm

This indicates that d = 1/N = 1/5000 cm = 5 10-4 cm = 5 10-6 m is the distance between slits.

Using the diffraction grating formula, this follows:

nλ = d sin θ

2 × λ = 5 × 10-6 m × sin 30°

λ = 1.25 × 10-6 m

= 1250 Å 

Ques. What is the slit spacing for a 1 cm wide diffraction grating that, when used with the light of 1000 nm wavelength, exhibits a 30-degree deviation in the fourth order? (3 marks)

Ans: The n-th order is 4.

The deviation's angle, = 30°, and

Its wavelength is 1000 nm or 1000 10-9 meters.

Using the diffraction grating formula, this follows:

nλ = d sin θ

4 × 1000 × 10-9 m = d × sin 30°

d = 8 × 10-6 m

Ques. Find the separation between the slits in a diffraction grating with a width of 1 cm that exhibits a 30° deviation in the second order when illuminated by light with a wavelength of 300 nm. (5 marks)

Ans: Here,

n = 2 is the order.

The deviation's angle, = 30°, and

The wavelength is 300 nm or 300 10-9 meters.

Using the diffraction grating formula, this follows:

nλ = d sin θ

2 × 300 × 10-9 m = d × sin 30°

d = 1.2 × 10-5 m

Ques. To produce a fourth-order brilliant line when monochromatic light with a wavelength of 600 nm strikes a grating at an angle of 30°, determine the number of slits per centimeter. (5 marks)

Ans. Here,

The n-th order is 4.

The deviation's angle, = 30°, and

The wavelength is 600 nm, which equals 600 10-9 m.

Using the diffraction grating formula, this follows:

nλ = d sin θ

4 × 600 × 10-9 m = d × sin 30°

or

d= 4.8 × 10-6 m

The number of slits per centimeter is now stated as follows:

x = 1 / 4.8 × 10-6 m

= 2.08 × 105/ m

= 2.08 × 105 / 102 cm

= 2.08 × 103 / cm

= 2080 / cm

Do Check Out: 

CBSE CLASS XII Related Questions

  • 1.
    Write any two features of nuclear forces.


      • 2.
        Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.


          • 3.
            Two parallel plate capacitors X and Y are connected in series to a 6 V battery. They have the same plate area and same plate separation but capacitor X has air between its plates, whereas capacitor Y contains a material of dielectric constant 4. Calculate the capacitances of X and Y, if the equivalent capacitance of the combination of X and Y is \( 4 \, \mu\text{F} \). Calculate the potential difference across the plates of X and Y.


              • 4.
                Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

                  • attract with a force \( \frac{F}{2} \)
                  • repel with a force \( \frac{F}{2} \)
                  • repel with a force \( F \)
                  • attract with a force \( F \)

                • 5.
                  Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).


                    • 6.
                      Two thin lenses of focal length \( f_1 \) and \( f_2 \) are placed in contact with each other coaxially. Prove that the focal length \( f \) of the combination is given by \[ f = \frac{f_1 f_2}{f_1 + f_2}. \]

                        CBSE CLASS XII Previous Year Papers

                        Comments


                        No Comments To Show