NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.1

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Lead

NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.1 is given in this article. Chapter 6 Applications of Derivatives Exercise 6.1 includes questions on the introduction of derivatives and the rate of change of quantities. The exercise includes a total of 18 questions including 10 long questions, 6 short questions and 2 MCQs.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 6 Exercise 6.1

Check out solutions of Class 12 Maths NCERT solutions chapter 6 Applications of Derivatives Exercise 6.1

Read More: NCERT Solutions For Class 12 Mathematics Chapter 6 Applications of Derivatives

Check out other exercise solutions of Class 12 Maths Chapter 6 Applications of Derivatives

Class 12 Chapter 6 Applications of Derivatives Topics:

CBSE Class 12 Mathematics Study Guides:

CBSE CLASS XII Related Questions

  • 1.

    The motion of a particle is described as \( S = 2t^{3} - 6t^{2} + 8 \). Its velocity \( \frac{dS}{dt} \), when the acceleration \( \frac{d^{2}S}{dt^{2}} \) vanishes is :

      • \( -6 \) unit/sec
      • \( 0 \) unit/sec
      • \( 18 \) unit/sec
      • \( 6 \) unit/sec

    • 2.

      If \(P(A) = 0.3\), \(P(B) = 0.7\) and \(P(B/A) = 0.5\), then \(P(A \cup B)\) is :

        • \(0.35\)
        • \(0.85\)
        • \(0.5\)
        • \(0.21\)

      • 3.

        If \(y = \sqrt{\log \left\{ \sin \left( \dfrac{x^2}{3} + 1 \right) \right\}}\), then show that

        \[ \frac{dy}{dx} = \frac{x \cot \left( \dfrac{x^2}{3} + 1 \right)}{3y}. \]


          • 4.

            Solve the differential equation \( (x+y)\,dy + (x-y)\,dx = 0 \), given that \( y(1) = 1 \).


              • 5.

                Solve the differential equation \( y + \frac{d}{dx}(xy) = x(\sin x + \log x) \).


                  • 6.

                    Find the product of the maximum and minimum values of the function \( f(x) = \cos x - \frac{1}{2}\cos 2x,\ x \in \left[0, \frac{\pi}{2}\right] \).

                      CBSE CLASS XII Previous Year Papers

                      Comments


                      No Comments To Show