NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.2

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Jasmine Grover

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NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.2 is provided in this article. Chapter 6 Exercise 6.2 includes questions that deal with concepts of increasing and decreasing functions. The exercise includes a total of 19 questions with 10 long questions, 7 short questions and 2 MCQs.

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CBSE CLASS XII Related Questions

  • 1.
    Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).


      • 2.
        Find:

        If \[ (3\hat{i}-2\hat{j}+5\hat{k})\times(4\hat{i}+p\hat{j}+q\hat{k})=\vec{0} \] then find the values of \(p\) and \(q\).

          • \(p = -\frac{2}{3}, \, q = \frac{5}{3}\)
          • \(p = -\frac{8}{3}, \, q = \frac{20}{3}\)
          • \(p = \frac{20}{3}, \, q = -\frac{8}{3}\)
          • \(p = 0, \, q = 0\)

        • 3.

          A carpenter needs to design a wooden box in the shape of a cuboid such that the sum of its length and breadth is 3 cm more than its height. Twice of its length, thrice of its breadth and its height add up to 10 cm. Its breadth added to 7 times its height is 1 cm less than 3 times its length. 


            • 4.
              Find:

              If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).

                • \(0\)
                • \(-2\)
                • \(-1\)
                • \(2\)

              • 5.
                Find:

                The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]


                  • 6.
                    Find:

                    The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

                      • \(-\frac{\pi}{2}\)
                      • \(-\frac{\pi}{4}\)
                      • \(\frac{\pi}{4}\)
                      • \(\frac{\pi}{2}\)
                    CBSE CLASS XII Previous Year Papers

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