NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.5

Jasmine Grover logo

Jasmine Grover

Education Journalist | Study Abroad Lead

NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.5 is given in this article. Chapter 6 Exercise 6.5 includes questions that deal with concepts of maxima and minima and maximum and Minimum Values of a Function in a Closed Interval.

Download PDF: NCERT Solutions for Class 12 Maths Chapter 6 Exercise 6.5

Check out the Class 12 Maths NCERT solutions chapter 6 Exercise 6.5:

Read More: NCERT Solutions For Class 12 Mathematics Chapter 6 Applications of Derivatives

Check out other exercise solutions of Class 12 Maths Chapter 6 Applications of Derivatives:

Class 12 Chapter 6 Applications of Derivatives Topics:

CBSE Class 12 Mathematics Study Guides:

CBSE CLASS XII Related Questions

  • 1.
    If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).


      • 2.
        Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).


          • 3.
            Find:

            The shortest distance between the lines: \[ \vec{r}=(4+\lambda)\hat{i}+(2\lambda-1)\hat{j}-3\lambda\hat{k} \] and \[ \vec{r}=(1+2\mu)\hat{i}+(4\mu-1)\hat{j}+(2-5\mu)\hat{k} \]


              • 4.
                Find:

                The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

                  • \(-\frac{\pi}{2}\)
                  • \(-\frac{\pi}{4}\)
                  • \(\frac{\pi}{4}\)
                  • \(\frac{\pi}{2}\)

                • 5.
                  Find:

                  If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).

                    • \(0\)
                    • \(-2\)
                    • \(-1\)
                    • \(2\)

                  • 6.
                    Differentiate \( \tan^{-1}\left( \frac{\sqrt{1 + x^2} + \sqrt{1 - x^2}}{\sqrt{1 + x^2} - \sqrt{1 - x^2}} \right) \) with respect to \( \cos^{-1}(x^2) \).

                      CBSE CLASS XII Previous Year Papers

                      Comments


                      No Comments To Show