NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.5

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NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.5 is given in this article. Chapter 6 Exercise 6.5 includes questions that deal with concepts of maxima and minima and maximum and Minimum Values of a Function in a Closed Interval.

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Check out the Class 12 Maths NCERT solutions chapter 6 Exercise 6.5:

Check out other exercise solutions of Class 12 Maths Chapter 6 Applications of Derivatives:

Class 12 Chapter 6 Applications of Derivatives Topics:

Increasing Decreasing Functions	Tangents and Normals	Approximations
Linear Approximation Formula	Derivatives formula	Interpolation Formula
Lagrange Interpolation Formula	Newton Method Formula	Linear Interpolation Formula
Linear Regression Formula	Differential Calculus approximation	Continuity and Differentiability

CBSE Class 12 Mathematics Study Guides:

Math Formula	Math MCQs	Calculus
NCERT Solutions for Class 12 Maths	Difference between in Maths	Math Study Notes
Mensuration	Algebra	Trigonometry

CBSE CLASS XII Related Questions

1.
Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.
View Solution
2.
Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]
View Solution
3.
For a square matrix \(A\), \[ (3A)^{-1}= \]
- \( 3A^{-1} \)
- \( 9A^{-1} \)
- \( \frac{1}{3} A^{-1} \)
- \( \frac{1}{9} A^{-1} \)
View Solution
4.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.
View Solution
5.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]
- Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
6.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:
- \([-1, 1]\)
- \([4, 6]\)
- \([-7, -3]\)
- \([2, 3]\)
View Solution

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NCERT Solutions for Class 12 Maths Chapter 3 Matrices

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NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.5

CBSE CLASS XII Related Questions

1.
Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.

2.
Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]

3.
For a square matrix \(A\), \[ (3A)^{-1}= \]

4.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.

5.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

6.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:

Similar Mathematics Concepts

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NCERT Solutions for Class 12 Maths Chapter 6 Applications of Derivatives Exercise 6.5

CBSE CLASS XII Related Questions

1.Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.

2.Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]

3. For a square matrix \(A\), \[ (3A)^{-1}= \]

4. A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.

5.For two vectors \(\vec{a}\) and \(\vec{b}\): Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

6.The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Check whether \[ f:\mathbb{R}-\{3\}\rightarrow\mathbb{R} \] defined as \[ f(x)=\frac{x-2}{x-3} \] is onto or not.

2.
Find the domain of \[ q(x)=\cos^{-1}(4x^2-3). \] Hence, find the value of \(x\) for which \[ q(x)=0. \] Also, write the range of \[ 3q(x)-\pi. \]

3.
For a square matrix \(A\), \[ (3A)^{-1}= \]

4.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.

5.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

6.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is: