Lagrange Interpolation Formula: Overview, Advantages, Disadvantages

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The Lagrange interpolation formula is a method for determining a polynomial, known as a Lagrange polynomial, that takes on specific values at random places. Lagrange's interpolation is a polynomial approximation to f of Nth degree (x). Interpolation is a technique for generating new values for any function from a set of existing values. Using this technique, we may find the unknown value on a point. When it comes to the linear interpolation formula, it can be used to find a new value from two provided points. The "n" set of numbers is required when comparing it to Lagrange's interpolation formula. The new value will then be found using Lagrange's approach. Interpolation is a statistical technique for estimating values between two points. Interpolation is a way of finding additional data points within a range of discrete data points. 

Key Terms: Lagrange interpolation, Polynomial, Linear Interpolation, Variable, Interpolation, Statistics, Function, Independent variable, Lagrange

Also Read: Isosceles Triangle Theorems


What is Lagrange Interpolation Theorem?

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Lagrange Interpolation theorem can be used to create a polynomial that passes through a set of points and takes particular values at random locations. This theorem gives the approximation formula for nth degree polynomials to a function f(x) if it is known at discrete places xi, I = 0, 1, 2,... (x). It also provides a demonstration of the theorem that is constructive. The theorem of Lagrange can be applied to both equally and unequally spaced sites. This signifies that the xs values are not evenly spaced.

It is a method for estimating a mathematical expression by using any intermediate value for the independent variable. Interpolation is mostly used to determine what extra data might exist outside of the obtained data. For their experiments, many experts such as photographers, physicists, mathematicians, and engineers use this strategy. When one interpolates the next position of a pixel based on the provided positions of pixels in an image, this is a popular use.

Theorem of Lagrange Interpolation 

In science, solving a difficult function takes a lot of time and effort. Experiments become difficult to conduct as a result of this. The interpolation approach is used to construct a little less complex version of the original function.

The capacity to deduce a value between two expressly given numbers in a table or on a line graph is known as linear interpolation, or simply interpolation. Extrapolation, which is related to interpolation, is the process of finding a corresponding value for a set of values outside of the range stated.

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Lagrange’s Interpolation Formula

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The formula for interpolation will be as follows:

Lagrange’s Interpolation Formula
Lagrange’s Interpolation Formula

Definition of Lagrange Interpolation 

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An algebraic expression with one or more terms is called a polynomial. A polynomial is defined as "many terms" because "poly" means "many" and "nominal" means "terms." Constants, variables, and exponents are all possible. They can all be joined using mathematical operations such as additions, subtraction, multiplication, and division, with the exception that a polynomial expression cannot be divided by a variable.

The technique of finding a specific value between two points on a line or curve is known as interpolation. We shall 'enter' into the data collection using the word 'inter.' This technique is important not only in statistics, but also in science, business, and a variety of other real-world applications that fall inside two data points. 

As a result, the interpolation formula can be regarded as a method of curve fitting that uses linear polynomials to build new data points within the range of a discrete collection of known data points. Linear interpolation has been used to fill in unknown values in tables since the dawn of time.

Also Read: Trigonometry


Advantages of Lagrange Interpolation

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  • Even when the arguments are not evenly spaced, this formula is used to find the function's value.
  • This formula is used to calculate the value of the independent variable x that corresponds to a given function value.

Disadvantages of Lagrange Interpolation

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  • In a Lagrangian polynomial, changing the degree necessitates a thorough recalculation of all terms.
  • The formula for a polynomial of the high degree includes a significant number of multiplications, making the operation sluggish.
  • The degree of polynomial is chosen at the start of the Lagrange Interpolation. As a result, determining the degree of approximating a polynomial that is appropriate for a particular set of tabulated points is tricky.

How to Find Lagrange Interpolation

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To get our solution, we can use the Lagrange interpolation formula.

The Lagrange’s Interpolation formula: 

If, y = f(x) takes the values y0, y1, … , yn corresponding to x = x0, x1 , … , xn then,

How to Find Lagrange Interpolation
How to Find Lagrange Interpolation

Things to Remember

  • The Lagrange theorem generalizes well-known mathematical facts such as the fact that a line is uniquely determined by two points, that the graph of a quadratic polynomial is uniquely determined by three points, and so on.
  • The Lagrange theorem is used in the picture enlargement approach to try to describe the propensity of image data using interpolation polynomials to estimate unknown data. This aids in the enlarging of images.
  • Only when the values of x are equidistant can the Newton forward and backward interpolation equations be utilized. We utilize Lagrange's interpolation formula if the values of x are equidistant or not equidistant.
  • In 1779, Waring created and published the formula for the first time. Euler rediscovered it in 1783, and Lagrange published it in 1795. Lagrange interpolating polynomials have been implemented in the Wolfram Language as Interpolating Polynomial data, var. In the formulation of Newton-Cotes formulae, Lagrange interpolating polynomials are commonly used.

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Sample Questions

Ques: What is the Lagrange interpolation function? (2 marks)

Ans: The Lagrange interpolation formula is a method for determining a polynomial, known as a Lagrange polynomial, that takes on specific values at random places. Lagrange's interpolation is a polynomial approximation to f of Nth degree (x).

Ques: What is the Lagrange formula? (2 marks)

Ans: j = 0. (xi - xj) i = 0. j ¹ 1 Because Lagrange's interpolation is likewise a Nth degree polynomial approximation to f(x), and the Nth degree polynomial traveling through (N+1) points is unique, the Lagrange's and Newton's divided difference approximations are identical.

Ques; What are Lagrange elements? (2 marks)

Ans: Lagrange elements are a type of zero-order Hermitian interpolation function. Because the continuity of the slope is not required for Lagrange elements, the order of interpolation is zero, or n = 0. In this case, the element's length is L and the coordinate is x.

Ques: What is the Lagrange basis function? (2 marks)

Ans; Lagrange interpolating polynomials are constructed using linear combinations of Lagrange basis functions. In finite element analysis, Lagrange basis functions are frequently employed as the basis for element shape-functions.

Ques: What is the Lagrange equation of motion? (2 marks)

Ans: Lagrange's equations are one of the most well-known. The Lagrangian L is defined as L = T V, where T is the system's kinetic energy and V is its potential energy.

Ques: Why are Lagrange elements preferred over serendipity? (2 marks)

Ans: Because the internal nodes of higher-order Lagrange elements do not contribute to inter-element connectivity, the deletion of internal nodes reduces the size of the element matrices.

Ques: What is the formula for linear interpolation? (2 marks)

Ans: Understand the formula for linear interpolation. y = y1 + ((x – x1) / (x2 – x1)) * (y2 – y1), where x is the known value, y is the unknown value, x1 and y1 are coordinates below the known x value, and x2 and y2 are positions above the x value.

Ques: What is Lagrange's linear equation? (2 marks)

Ans: The Linear Equation of Lagrange. Lagrange's Linear Equation is a partial differential equation of the form Pp+Qq=R, where P, Q, R are functions of x, y, and z (which are or first order and linear in p and q).

Ques: What is an interpolating function? (2 marks)

Ans: The answer is stated in terms of an interpolating function, which is a table of unknown function values for various independent variable values. Interpolation in this table is used by the computer to determine a numerical value of the function for a specified value of the independent variable.

Ques: What is cubic interpolation? (2 marks)

Ans: Cubic spline interpolation is a type of spline interpolation that is frequently used to avoid the Runge's phenomenon problem. This method produces an interpolating polynomial that is smoother and has a lower error than other interpolating polynomials like the Lagrange and Newton polynomials.

Ques: What is linear interpolation? (2 marks)

Ans: Linear interpolation is a method of curve fitting that uses linear polynomials to create new data points within the range of a discrete set of known data points in mathematics. Linear interpolation is a technique for estimating the value of a function f using two known values of the function at different times.

Ques: What is linear spline interpolation? (2 marks)

Ans: Spline interpolation is a sort of interpolation in numerical analysis where the interpolant is a special type of piecewise polynomial known as a spline.

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CBSE CLASS XII Related Questions

  • 1.
    If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).


      • 2.
        Find a point on the line \( \frac{x - 2}{3} = \frac{1 - y}{2} = \frac{z - 3}{2} \) at a distance of \( \sqrt{2} \) units from the point \( (1, 2, 3) \).


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            At a birthday party, children are being served orange juice in conical cups, as shown in the figure. 


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              • 4.
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                The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

                  • \(-\frac{\pi}{2}\)
                  • \(-\frac{\pi}{4}\)
                  • \(\frac{\pi}{4}\)
                  • \(\frac{\pi}{2}\)

                • 5.

                  Evaluate:
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                    • 6.

                      Find:
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                        • \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
                        • \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
                        • \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
                        • \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)
                      CBSE CLASS XII Previous Year Papers

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