NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.10

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NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.10 is covered in this article. This exercise of Chapter 7 deals with the “Evaluation of Definite Integrals by Substitution”. NCERT Solutions for Class 12 Maths Chapter 7 will carry a weightage of around 6-18 marks in the CBSE Term 2 Exam 2022. NCERT has provided a total of 10 problems and solutions based on the important topics of the exercise.

Download PDF NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.10

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Important topics covered in Integrals Chapter are:

Double Integral
Continuous Integration
Properties of Definite Integral
Line Integral
Integrals of Particular Function

Also check: NCERT Solutions for Class 12 Maths Chapter 7 Integrals

CBSE CLASS XII Related Questions

1.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.
View Solution
2.
Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]
View Solution
3.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]
- Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
4.
Sports car racing is a form of motorsport which uses sports car prototypes.The competition is held on special tracks designed in various shapes.
The equation of a sports car racing track is given as: \[ f(x)= \begin{cases} x^4-4x^2+4, & 0\leq x<3,\\ x^2+40, & x\geq 3 \end{cases} \] Based on this information:
5.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.
View Solution
6.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]
- local maximum value is 2
- local minimum value is \( -2 \)
- local maximum value is \( -2 \)
- local minimum value \( < \) local maximum value
View Solution

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You can also check

Exercise 7.1 Solutions	22 Questions
Exercise 7.2 Solutions	39 Questions
Exercise 7.3 Solutions	24 Questions
Exercise 7.4 Solutions	25 Questions
Exercise 7.5 Solutions	23 Questions
Exercise 7.6 Solutions	24 Questions
Exercise 7.7 Solutions	11 Questions
Exercise 7.8 Solutions	6 Questions
Exercise 7.9 Solutions	22 Questions
Exercise 7.10 Solutions	10 Questions
Exercise 7.11 Solutions	21 Questions
Miscellaneous Exercise Solutions	44 Questions

Fundamental Theorem of Calculus	Integration by Partial Fractions	Definite Integral Formula
Continuous integration	Properties of Definite Integral	Line Integral
Calculus Formula	Differentiation and Integration Formula	Substitution Method
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Arithmetic	Calculus	Algebra
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NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.10

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Other Exercises Solutions of Class 12 Maths Chapter 7 Integrals

CBSE CLASS XII Related Questions

1.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

2.
Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]

3.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

5.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.

6.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

Similar Mathematics Concepts

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NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.10

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Other Exercises Solutions of Class 12 Maths Chapter 7 Integrals

CBSE CLASS XII Related Questions

1.Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

2. Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]

3.For two vectors \(\vec{a}\) and \(\vec{b}\): Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

5. A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.

6. For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

2.
Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]

3.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

5.
A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.

6.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]