NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.9

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NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.9 is covered in this article. This exercise of Chapter 7 deals with the Fundamental Theorem of Calculus, Area function, The first fundamental theorem of integral calculus, The second fundamental theorem of integral calculus. NCERT Solutions for Class 12 Maths Chapter 7 will carry a weightage of around 6-18 marks in the CBSE Term 2 Exam 2022. NCERT has provided a total of 22 problems and solutions based on the important topics of the exercise.

Download PDF NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.9

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Important topics covered in Integrals Chapter are:

  • Double Integral
  • Continuous Integration
  • Properties of Definite Integral
  • Line Integral
  • Integrals of Particular Function

Also check: NCERT Solutions for Class 12 Maths Chapter 7 Integrals 

Other Exercises Solutions of Class 12 Maths Chapter 7 Integrals

Chapter 7 Integrals Topics:

CBSE Class 12 Mathematics Study Guides:

CBSE CLASS XII Related Questions

  • 1.

    Sports car racing is a form of motorsport which uses sports car prototypes.The competition is held on special tracks designed in various shapes. 

    The equation of a sports car racing track is given as: \[ f(x)= \begin{cases} x^4-4x^2+4, & 0\leq x<3,\\ x^2+40, & x\geq 3 \end{cases} \] Based on this information:


      • 2.
        For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

          • local maximum value is 2
          • local minimum value is \( -2 \)
          • local maximum value is \( -2 \)
          • local minimum value \( < \) local maximum value

        • 3.

          Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not. 


            • 4.
              Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]


                • 5.
                  For a square matrix \(A\), \[ (3A)^{-1}= \]

                    • \( 3A^{-1} \)
                    • \( 9A^{-1} \)
                    • \( \frac{1}{3} A^{-1} \)
                    • \( \frac{1}{9} A^{-1} \)

                  • 6.

                    If \[ B(\operatorname{adj} B)= \begin{bmatrix} \frac{1}{3} & 0 & 0\\ 0 & \frac{1}{3} & 0\\ 0 & 0 & \frac{1}{3} \end{bmatrix}, \] then the value of \[ \det(B^{-1}) \] is: 

                      • \(\frac{1}{3}\)
                      • \(\frac{1}{9}\)
                      • \(3\)
                      • \(9\)
                    CBSE CLASS XII Previous Year Papers

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