NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.9

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NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.9 is covered in this article. This exercise of Chapter 7 deals with the Fundamental Theorem of Calculus, Area function, The first fundamental theorem of integral calculus, The second fundamental theorem of integral calculus. NCERT Solutions for Class 12 Maths Chapter 7 will carry a weightage of around 6-18 marks in the CBSE Term 2 Exam 2022. NCERT has provided a total of 22 problems and solutions based on the important topics of the exercise.

Download PDF NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.9

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Important topics covered in Integrals Chapter are:

Double Integral
Continuous Integration
Properties of Definite Integral
Line Integral
Integrals of Particular Function

Also check: NCERT Solutions for Class 12 Maths Chapter 7 Integrals

CBSE CLASS XII Related Questions

1.
Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]
View Solution
2.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]
- Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false, but Reason (R) is true.
View Solution
3.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.
View Solution
4.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:
- \([-1, 1]\)
- \([4, 6]\)
- \([-7, -3]\)
- \([2, 3]\)
View Solution
5.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]
- local maximum value is 2
- local minimum value is \( -2 \)
- local maximum value is \( -2 \)
- local minimum value \( < \) local maximum value
View Solution
6.
Evaluate: \[ \cos\left[\sin^{-1}(-1)-\tan^{-1}(-\sqrt{3})\right]. \]
View Solution

View All

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You can also check

Exercise 7.1 Solutions	22 Questions
Exercise 7.2 Solutions	39 Questions
Exercise 7.3 Solutions	24 Questions
Exercise 7.4 Solutions	25 Questions
Exercise 7.5 Solutions	23 Questions
Exercise 7.6 Solutions	24 Questions
Exercise 7.7 Solutions	11 Questions
Exercise 7.8 Solutions	6 Questions
Exercise 7.9 Solutions	22 Questions
Exercise 7.10 Solutions	10 Questions
Exercise 7.11 Solutions	21 Questions
Miscellaneous Exercise Solutions	44 Questions

Fundamental Theorem of Calculus	Integration by Partial Fractions	Definite Integral Formula
Calculus Formula	Differentiation and Integration Formula	Substitution Method
Methods of Integration	List of Integral Formulas	Double Integral
Continuous integration	Properties of Definite Integral	Line Integral

Arithmetic	Calculus	Algebra
NCERT Solutions for Class 12 Maths	Maths MCQs	Maths Syllabus
Mathematics Notes	Trigonometry	Maths Study Material

NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.9

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Other Exercises Solutions of Class 12 Maths Chapter 7 Integrals

CBSE CLASS XII Related Questions

1.
Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]

2.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

3.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

4.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:

5.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

6.
Evaluate: \[ \cos\left[\sin^{-1}(-1)-\tan^{-1}(-\sqrt{3})\right]. \]

Similar Mathematics Concepts

Comments

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NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.9

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Other Exercises Solutions of Class 12 Maths Chapter 7 Integrals

CBSE CLASS XII Related Questions

1. Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]

2.For two vectors \(\vec{a}\) and \(\vec{b}\): Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

3.Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

4.The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:

5. For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

6. Evaluate: \[ \cos\left[\sin^{-1}(-1)-\tan^{-1}(-\sqrt{3})\right]. \]

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]

2.
For two vectors \(\vec{a}\) and \(\vec{b}\):

Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

3.
Check whether the function \[ f(x)= \begin{cases} \dfrac{|x-3|}{2(x-3)}, & x<3,\\[6pt] \dfrac{x-6}{6}, & x\geq 3 \end{cases} \] is continuous at \(x=3\) or not.

4.
The domain of \[ f(x)=\cos^{-1}(2x-5) \] is:

5.
For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

6.
Evaluate: \[ \cos\left[\sin^{-1}(-1)-\tan^{-1}(-\sqrt{3})\right]. \]