NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.4

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NCERT Solutions for Class 12 Maths Chapter 7 Integrals contains the solutions for all Exercise 7.4 questions. Exercise 7.4 is based on the Integrals of Some Particular Functions. NCERT Solutions for Class 12 Maths Chapter 7 will carry a weightage of around 6-18 marks in the CBSE Term 2 Exam 2022. NCERT has provided a total of 25 problems and solutions based on the important topics.

Download PDF NCERT Solutions for Class 12 Maths Chapter 7 Integrals Exercise 7.4

NCERT Solutions for Class 12 Maths Chapter 7: Important Topics

Important topics covered in Integrals Chapter are:

  • Double Integral
  • Continuous Integration
  • Properties of Definite Integral
  • Line Integral
  • Integrals of Particular Function

Also check: NCERT Solutions for Class 12 Maths Chapter 7 Integrals 

Other Exercises Solutions of Class 12 Maths Chapter 7 Integrals

Chapter 7 Integrals Topics:

CBSE Class 12 Mathematics Study Guides:

CBSE CLASS XII Related Questions

  • 1.
    Find: \[ \int \frac{x^2}{(x^2+9)(x^2+16)}\,dx \]


      • 2.
        A function \[ f:\mathbb{R}-\left\{\frac{3}{5}\right\} \to \mathbb{R}-\left\{\frac{3}{5}\right\} \] is defined as \[ f(x)=\frac{3x+2}{5x-3}. \] Show that \(f\) is one-one and onto.


          • 3.

            For two vectors \(\vec{a}\) and \(\vec{b}\):  

            Assertion (A): \[ |\vec{a}\times\vec{b}|^2+(\vec{a}\cdot\vec{b})^2 = |\vec{a}|^2|\vec{b}|^2 \] Reason (R): \[ |\vec{a}\times\vec{b}| = (\vec{a}\cdot\vec{b})\tan\theta, \quad \theta\neq\frac{\pi}{2}. \]

              • Both Assertion (A) and Reason (R) are true and the Reason (R) is the correct explanation of the Assertion (A).
              • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
              • Assertion (A) is true, but Reason (R) is false.
              • Assertion (A) is false, but Reason (R) is true.

            • 4.
              If \[ \frac{d}{dx}(F(x))=\frac{1}{e^x+1}, \] then find \(F(x)\), given that \[ F(0)=\log\left(\frac{1}{2}\right). \]


                • 5.
                  The least value of \[ f(x)=e^{-x} \] in the interval \[ [0,3] \] is:

                    • \( e^{-3} \)
                    • \( -1 \)
                    • \( 1 \)
                    • \( -e^3 \)

                  • 6.
                    For \[ f(x)=x+\frac{1}{x}, \quad x\neq 0. \]

                      • local maximum value is 2
                      • local minimum value is \( -2 \)
                      • local maximum value is \( -2 \)
                      • local minimum value \( < \) local maximum value
                    CBSE CLASS XII Previous Year Papers

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