Ratio Formula: Calculation, Properties & Table

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Jasmine Grover

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Ratio formula is predominantly used in cases where there is a requirement to compare the relationship between two numbers of a similar kind. In other words, the ratio formula is referred to as a separation between the numbers which is represented by a colon (:). Other than colon, division sign (/) is also used to express the ratios between the two numbers. 

Key Takeaways: Ratio, Ratio Formula, Equivalent Ratios, Greatest Common Factor, Antecedent, Consequent, Number, Colon, Division, Fraction


What is Ratio?

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Ratio is used to compare two quantities which are of similar kind in order to compare them with ease. This ratio can also be expressed as a fraction wherein the numerator is compared to the denominator.

Ratios can be further divided into two types: 

  • Part Ratio 
  • Whole Ratio

In part ratio, it denotes how two distinct groups or numbers or entities are related to each other. For instance, in the case of a class, the ratio between boys and girls is 4:10.

In whole ratio, it denotes the relationship which exists between a specific group as compared to the whole. For instance, in a generalized case, out of 20 people, 10 of them are interested in books and like to read. Thus, the whole ratio becomes 10:20, which infers that every 10 people from a group of 20 people like to read books.

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Ratio Formula

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Ratio formula is used to express relation between two numbers or quantities. In order to express ratios between two quantities, for instance ‘a’ and ‘b’, it can be represented as ‘a:b’, which is generally read as ‘a is to b’. Furthermore, the fraction form for the same is represented as ‘a/b’. Here, ‘a’ can also be called as the antecedent or the numerator and ‘b’ can be called as the consequent or the denominator.


Calculation of Ratios

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The following steps can be used to calculate the ratio of the two said quantities. This can be elaborated using an example. For instance, if 20 cups of flour and 25 cups of sugar are required to prepare sponge cake, the ratio of the flour and sugar utilized in the recipe can be calculated as follows:

Step 1: Finding the quantities of both the items for which the ratio has to be determined. In

this scenario, it is 20 and 25.

Step 2: Writing these quantities in a fraction form of ‘a/b’. Thus, the quantities can be written

as 20/25.

Step 3: Simplifying the fraction even further, if it is possible, in order to give the final ratio. 

Thus, for the quantities, 20/25 can be simplified further as 4/5.

Step 4: Thus, the ratio of the flour to the sugar can be expressed as 4:5.

Also Read: Sequence and Series


Simplification of Ratios

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In order to express how much of one entity or quantity is required in comparison to the other, the two terms in the ratio can be further classified and expressed in their lowest forms. This is done because ratios when expressed in their lowest forms are easier to understand.

The following steps can be followed to simplify a ratio using an example of ratio 18:10.

Step 1: Writing of the provided ratio ‘a:b’ as fraction ‘a/b’. On writing as such, the fraction form will be 18/10.

Step 2: Finding the greatest common factor (GCF) of both ‘a’ and ‘b’. Here, it will be 2 in case of 18 and 10.

Step 3: Dividing the numerator as well as the denominator of the fraction with the GCF in order to obtain a more simplified fraction. Here, dividing the numerator and the denominator by 2, we get 9/5.

Also, the fraction obtained can be represented in a ratio form as 9:5.

Also Read: Complex numbers and Quadratic equations


Properties of Ratios

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The main properties of ratios are as follows:

  • If a < b in the ratio a : b, then a : b < 1.
  • In case both the numbers 'a' and 'b' are equal in the ratio a: b, then a: b = 1
  • If a > b in the ratio a : b, then a : b > 1.

Equivalent Ratio

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In the case of equivalent ratios, they are almost similar to the equivalent fractions. Here, if the antecedent (numerator) and the consequent (denominator) of any given ratio is either multiplied or divided by the same number (any number other than zero), it then gives an equivalent ratio. For instance, when the antecedent and the consequent of the ratio 2:4 are multiplied by 2, we get, (2x2) : (4x2) or 4:8. Here, 2:4 and 4:8 are the equivalent ratios. Similarly, when both the terms of the ratio 30:20 are divided by 10, it gives 3:2. Here, 30:20 and 3:2 are equivalent ratios.

Thus, an infinite number of equivalent ratios of any given ratio can be found by multiplying the antecedent and the consequent by a positive integer.

Read Also: Class 12 Differential Equation


Ratio Table

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Ratio table refers to a list containing the equivalent ratios of any particular given ratio in a structured manner. The following ratio table gives the relation between the ratio 1:4 and four of its equivalent ratios. 

For instance, by taking the ratio 1:4 and finding its four equivalent ratios, by multiplying both the terms of the ratio by 2, 3, 6 and 9, we get 2:8, 3:12, 6:24, and 9:36. 


Things to Remember 

  • Ratio is used to find relations between two or more quantities with respect to each other.
  • In a ratio, the dividend is called the 'antecedent' and the divisor is called the 'consequent'.
  • The symbol ‘:’ is used to denote ratio.
  • A ratio table refers to a list of equivalent ratios that are obtained either by multiplying or dividing both antecedent and consequent by the same value.
  • Two ratios are equivalent, if the fractions corresponding to them are equivalent.

Also Read:


Sample Questions

Ques. In a class of 70 students, 43 are girls and the remaining students are boys. Using the ratio formula, find out the ratio of the total number of boys to the number of girls. (3 marks)

Ans. Given;

Total number of students in the class=70

Number of girls = 43

Number of boys = Total number of students - Number of girls

= 27

Using ratio formula;

The ratio of number of boys to the number of girls = Number of boys: Number of girls = 27:43

Ques. The ratio of x and y is 6:5. If x = 78, what is the value of y? (2 marks)

Ans. Given;

Ratio of x to y = 6:5

Using ratio formula,

x:y = 6:5

x/y = 6/5

78/y = 6/5

y = (5/6) × 78

y = 65

Ques. Find the simplest form of 80:75 using the ratio formula. (2 marks)

Ans. Greatest Common Factor of 80 and 75 is 5.

On dividing each term in the ratio by 5.

We get 80/5:75/5 = 16:15.

Ques.Simplify the given ratio, 87:75. (2 marks)

Ans. To simplify the given ratio, GCF should be found out first. 

Here, GCF of 87 and 75, is 3. Further, on dividing each term by 3, that is, (87 ÷ 3)/(75 ÷ 3) , we get 29/25.

Thus, the ratio 87:75 in the simplest form is 29:25.

Ques. A music class in a particular academy has 30 students. 10 of them were adults and the rest were children. What is the ratio of the number of children to the total number of students in the music class? (3 marks)

Ans. Given; 

Total number of students in the music class=30 

The total number of adults = 10. 

Number of children who attended the music class=30 -10 = 20. 

Thus, the ratio of the total number of children to the total number of students in the music class is 20: 30, which on simplification gives 2:3.

Ques. There are around 49 boys and 28 girls in a particular school auditorium. Express the ratio of the number of boys to that of girls in the auditorium. (3 marks)

Ans. Given;

Number of boys = 49

Number of girls = 28

On finding GCF of 49 and 28, it is 7. 

In order to simplify, divide the two terms by their GCF which is 7. This means, (49 ÷ 7)/(28 ÷ 7) = 7/4. 

Thus, the ratio of the number of boys to that of girls is 7:4.

Ques. Two individuals A and B went into partnership and started a business. They agreed to divide the profit in the ratio of 2 : 4. What is their part of profit at the end of the financial year, if they made Rs. 10,000 in profits? (2 marks)

Ans. The ratio in which the profit to be divided is 2/4

The profit for each of them will be;

A = 10000 × 2/6= 3333.33/-

B = 10000 × 4/6= 6666.67/-

Ques. In a random class, there are 20 girls and 15 boys.
(a) What is the ratio of the number of girls to the number of boys?
(b) What is the ratio of the number of girls to the number of students in the class? (5 marks)

Ans. (a). Number of girls = 20

Number of boys = 15

Total number of students = 20 + 15 = 35

The ratio of the number of girls to the number of boys is 

Thus, the ratio will be 4:3.

(b) Ratio of the number of girls to the number of students is 

Thus, the ratio will be 4 : 7.

Ques. Distances travelled by Hamid and Akhtar in an hour are 9 km and 12 km. Find the ratio of speed of Hamid to the speed of Akhtar. (3 marks)

Ans. Distance travelled by Hamid = 9 km.

Distance travelled by Akhtar = 12 km.

Speed of Hamid per hour = 9 km

Per hour Speed of Akhtar = 12 km per hour

Thus, the ratio of the speed of Hamid to the speed Akhtar is 

Thus, the ratio is 3 : 4. 

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CBSE CLASS XII Related Questions

  • 1.
    Find:

    The principal value of \[ \sec^{-1}(\sqrt{2})+2\csc^{-1}(-2) \] is:

      • \(-\frac{\pi}{2}\)
      • \(-\frac{\pi}{4}\)
      • \(\frac{\pi}{4}\)
      • \(\frac{\pi}{2}\)

    • 2.

      Find:
      Let \(A=[a_{ij}]\) be a \(2\times2\) matrix whose elements are given by \[ a_{ij}=\frac{(2i-j)^2}{3} \] Find the transpose matrix \(A'\).

        • \(\begin{bmatrix} \frac{1}{3} & 3 \\ 0 & \frac{4}{3} \end{bmatrix}\)
        • \(\begin{bmatrix} \frac{1}{3} & 0 \\ 3 & \frac{4}{3} \end{bmatrix}\)
        • \(\begin{bmatrix} \frac{4}{3} & 3 \\ 1 & 0 \end{bmatrix}\)
        • \(\begin{bmatrix} \frac{4}{3} & 0 1 & \frac{3}{3} \end{bmatrix}\)

      • 3.

        Evaluate:
        \[ \int_{0}^{1} \frac{x \tan^{-1}x}{(1+x^2)^{3/2}}\,dx \]


          • 4.

            An NGO organises a charity event in which they decide to distribute woollen caps to protect children from winter. The caps to be distributed are in three separate boxes, Box I has 30 red caps, Box II has 20 red and 10 green caps, and Box III has 30 green caps. The probability that a Box i is selected and a cap picked out is i/6, where i = 1, 2, 3.  
            Based on the above information, answer the following questions :


              • 5.
                Find:

                If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).

                  • \(0\)
                  • \(-2\)
                  • \(-1\)
                  • \(2\)

                • 6.
                  Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).

                    CBSE CLASS XII Previous Year Papers

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