The most reactive metal is:

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The most reactive metal is Sodium (Na). Sodium is a soft, silvery-white metal that is highly reactive, especially in moist air or water. The high reactivity of sodium is due to the loose grip that its outer electron has on the atom, making it easily donated to form chemical compounds.

  1. Sodium is so reactive that it never occurs as a free element in nature, but is instead found in compounds such as sodium chloride (table salt) and sodium hydroxide.
  2. When sodium is cut or scratched, it reacts quickly with oxygen in the air to form a white layer of sodium oxide, which protects the metal from further oxidation.
  3. Sodium is a highly reactive metal, but it also has many important industrial and household uses.
  4. Sodium is used in the production of aluminum, as well as in the production of soaps, detergents, and other cleaning products.
  5. Sodium is also used in the medical field, as the primary ingredient in many electrolyte solutions used to treat dehydration.

In conclusion, the most reactive metal is sodium, due to its high reactivity and easily donated electrons. Despite its reactivity, sodium has many important industrial and household uses, making it a valuable element.

Reactivity Series

Sodium (Na)

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CBSE CLASS XII Related Questions

  • 1.

    (a) Define 'Denatured Protein' with an example.

    (b) What happens when glucose reacts with HCN ? Write the reaction involved.

    (c) Name the disease caused by the deficiency of Vitamin C.


      • 2.

        Write the reactions taking place at anode and cathode in a lead storage battery, when it is in use.


          • 3.

            (i) Give a chemical test to distinguish between Propanal and Propanone.

            (ii) Which of the given acids is stronger and why ? \( \mathrm{F_3C{-}C_6H_4{-}COOH} \) or \( \mathrm{H_3C{-}C_6H_4{-}COOH} \)

            (iii) Complete the given reaction sequence :

            \[ \mathrm{CH_3CH_2CH_2COOC_2H_5} \xrightarrow{\mathrm{NaOH}} \mathrm{A + C_2H_5OH} \]

            \[ \mathrm{A} \xrightarrow{\mathrm{H_3O^+}} \mathrm{B} \]


              • 4.
                Consider the decomposition of hydrogen peroxide \( (\mathrm{H_2O_2}) \) as per the equation given below : \[ 2\mathrm{H_2O_2} \xrightarrow[\text{Alkaline medium}]{I^-} 2\mathrm{H_2O} + \mathrm{O_2} \] The mechanism for this reaction was found to be : Step I : \( \mathrm{H_2O_2} + I^- \longrightarrow \mathrm{H_2O} + IO^- \) (slow) Step II : \( \mathrm{H_2O_2} + IO^- \longrightarrow \mathrm{H_2O} + I^- + \mathrm{O_2} \) (fast) (a) Write the rate law expression. (b) Determine the order of reaction with respect to \( \mathrm{H_2O_2} \), \( I^- \) and overall order of reaction. (c) What is the molecularity of the reaction in Step II ?


                  • 5.

                    Conductivity of \( 2.5 \times 10^{-4} \) M methanoic acid solution is \( 5.25 \times 10^{-5} \) S cm\(^{-1}\).

                    (a) Calculate its molar conductivity.

                    (b) Calculate its degree of dissociation.

                    [Given : \( \lambda^{\circ}_{(\mathrm{H^+})} = 349.5 \) S cm\(^2\) mol\(^{-1}\) and \( \lambda^{\circ}_{(\mathrm{HCOO^-})} = 50.5 \) S cm\(^2\) mol\(^{-1}\)]


                      • 6.
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                          • Dimethylglyoxime
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                        CBSE CLASS XII Previous Year Papers

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