The CBSE conducted the Class 12 Chemistry Board Exam on February 27, 2025, from 10:30 AM to 1:30 PM. The Chemistry theory paper has 70 marks, while 30 marks are allocated for the practical assessment.The paper is divided into Physical, Organic, and Inorganic Chemistry, with MCQ (1 mark each), short-answer questions (3 marks each), and long-answer questions (5 marks each).

CBSE Class 12 Chemistry 56-4-2 Question Paper and Detailed Solutions PDF is available for download here.

CBSE Class 12 2025 Chemistry 56-4-2 Question Paper with Solution PDF

CBSE Class 12 Chemistry Question Paper With Answer Key Download PDF Check Solutions
cbse class 12 2025 Question paper with Solution

Question 1:

Alkenes are formed by heating alcohols with conc. \(H_2SO_4\). The first step in the reaction is:

  • (A) formation of carbocation
  • (B) formation of ester
  • (C) protonation of alcohol molecule
  • (D) elimination of water
Correct Answer: (C) protonation of alcohol molecule
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Question 2:

Polyhalogen compounds have wide application in industries and agriculture. DDT is also a very important polyhalogen compound. It is a:

  • (A) greenhouse gas
  • (B) fertilizer
  • (C) biodegradable insecticide
  • (D) non-biodegradable insecticide
Correct Answer: (D) non-biodegradable insecticide
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Question 3:

The product of the oxidation of \(I^–\) with \(MnO_4^–\) in alkaline medium is:

  • (A) \(IO_4^-\)
  • (B) \(I_2\)
  • (C) \(IO^–\)
  • (D) \(IO_3^–\)
Correct Answer: (A) \(IO_3^–\)
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Question 4:

In the given reaction sequence, the structure of Y would be:


Correct Answer: (D)
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Question 5:

Out of 2-Bromobutane, 1-Bromobutane, 2-Bromopropane and 1-Bromopropane, the molecule which is chiral in nature is:

  • (A) 2-Bromobutane
  • (B) 1-Bromobutane
  • (C) 2-Bromopropane
  • (D) 1-Bromopropane
Correct Answer: (A) 2-Bromobutane
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Question 6:

In the Haworth structure of the following carbohydrate, various carbon atoms have been numbered. The anomeric carbon is numbered as:


  • (A) 1
  • (B) 2
  • (C) 3
  • (D) 5
Correct Answer: (A) 1
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Question 7:

The value of Henry’s constant \( K_H \) is:

  • (A) greater for gases with higher solubility
  • (B) greater for gases with lower solubility
  • (C) constant for all gases
  • (D) not related to the solubility of gases
Correct Answer: (B) greater for gases with lower solubility
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Question 8:

Out of the following statements, the \textbf{incorrect} statement is:

  • (A) La is actually an element of transition series.
  • (B) Zr and Hf have almost identical atomic radii because of lanthanoid contraction.
  • (C) Ionic radius decreases from \(La^{3+}\) to \(Lu^{3+}\) ion.
  • (D) Lanthanoids are radioactive in nature.
Correct Answer: (D) Lanthanoids are radioactive in nature.
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Question 9:

In an electrochemical cell, the following reaction takes place:

2Ag+ (aq) + Mg (s) → 2Ag (s) + Mg2+ (aq)

E\(_cell\) = 2.96 V

As the reaction progresses, what will happen to the overall voltage of the cell?

  • (A) Voltage will remain constant.
  • (B) It will decrease as [Mg2+] increases.
  • (C) It will increase as [Ag+] increases.
  • (D) It will increase as [Mg2+] increases.
Correct Answer: (B) It will decrease as [Mg2+] increases.
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Question 10:

Out of Ti3+, Cr3+, Mn2+ and Ni2+ ions, the one which has the highest magnetic moment is:

  • (A) Ti3+
  • (B) Cr3+
  • (C) Mn2+
  • (D) Ni2+
Correct Answer: (C) Mn2+
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Question 11:

Hofmann Bromamide degradation reaction is given by:

  • (A) \(CH_{3}NO_{2}\)
  • (B) \(CH_{3}NH_{2}\)
  • (C) \(CH_{3}CONH_{2}\)
  • (D) \(CH_{3}CH_{2}NH_{2}\)
Correct Answer: (C) \(CH_{3}CONH_{2}\)
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Question 12:

What amount of electric charge is required for the oxidation of 1 mole of $H_2O$ to $O_2$?

  • (A) 1F
  • (B) 2F
  • (C) 3F
  • (D) 4F
Correct Answer: (D) 4F
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Question 13:

Assertion (A): Cuprous salts are diamagnetic.

Reason (R): In cuprous ion, 3d-orbitals are partially filled.

Correct Answer: (C) Assertion (A) is true, but Reason (R) is false.
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Question 14:

Assertion (A): Acetanilide is more basic than aniline.

Reason (R): Acetylation of aniline results in decrease of electron density on nitrogen.

Correct Answer: (D) Assertion (A) is false, but Reason (R) is true.
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Question 15:

Assertion (A): Electrolysis of aqueous NaCl gives \(H_2\) at cathode and \(Cl_2\) at anode.

Reason (R): Chlorine has higher oxidation potential than \(H_2O\).

Correct Answer: (A) Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
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Question 16:

Assertion (A): n-Butyl chloride has higher boiling point than n-Butyl bromide.

Reason (R): C–Cl bond is more polar than C–Br bond.

Correct Answer: (D) Assertion (A) is false, but Reason (R) is true.
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Question 17:

What is meant by essential amino acids? Why are amino acids amphoteric in nature?

Correct Answer:
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Question 18:

(a) Reactant ‘A’ underwent a decomposition reaction. The concentration of ‘A’ was measured periodically and recorded in the table given below:
 

Time/Hours [A]/M
0 0.40
1 0.20
2 0.10
3 0.05

Based on the above data, predict the order of the reaction and write the expression for the rate law.

Correct Answer:
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Question 19:

(b) The reaction between \(H_2\) (g) and \(I_2\) (g) was carried out in a sealed isothermal container. The rate law for the reaction was found to be:

\[ \text{Rate} = k[H_2][I_2] \]

If 1 mole of \(H_2\) (g) was added to the reaction chamber and the temperature was kept constant, then predict the change in rate of the reaction and the rate constant.

Correct Answer:
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Question 20:

\(PtCl_4 2KCl\) doesn’t give precipitate of \(AgCl\) with \(AgNO_3\) solution. Write the structural formula and IUPAC name of the complex.

Correct Answer:
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Question 21:

Define fuel cell. Give two advantages of fuel cell over ordinary cell.

Correct Answer:
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Question 22:

Write the structures of the main products of the following reactions:




(a) 6 R–COOH + 2Al \(\rightarrow\)

Correct Answer:
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Question 23:

(a) Can sodium methoxide and t-butyl bromide be used for the preparation of t-butyl methyl ether? Give suitable reason. Justify your answer by suggesting the appropriate starting material if required for the preparation of t-butyl methyl ether.

Correct Answer:
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Question 24:

(b) Give the IUPAC name of the above mentioned ether.

Correct Answer:
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Question 25:

Arrange the following compounds as asked:


(a) In increasing order of pK\(_{\text{b}}\) values: \( \text{C}_2\text{H}_5\text{NH}_2 \), \( (\text{C}_2\text{H}_5)_2\text{NH} \), \( \text{C}_6\text{H}_5\text{NHCH}_3 \), \( \text{C}_6\text{H}_5\text{NH}_2 \)

Correct Answer:
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Question 26:

Calculate the cell voltage of the voltaic cell which is set up by joining the following half-cells at 25°C:

\( \text{Al}/\text{Al}^{3+} (0.001 \, \text{M}) \) and \( \text{Ni}/\text{Ni}^{2+} (0.001 \, \text{M}) \)

Given: \( E^0_{\text{Ni}^{2+}/\text{Ni}} = -0.25 \, \text{V} \), \( E^0_{\text{Al}^{3+}/\text{Al}} = -1.66 \, \text{V} \)

Correct Answer:
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Question 27:

Account for the following:

(i) Allyl chloride is hydrolysed more readily than n-propyl chloride.

Correct Answer:
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Question 28:

Complete the following reactions by writing the structural formulae of ‘A’ and ‘B’:


(i) \[ \text{CH}_3\text{CH}=\text{CH}_2 \xrightarrow{\text{HBr, Peroxide}} \text{‘A’} \xrightarrow{\text{aq. KOH}} \text{‘B’} \]


(ii) \[ \text{CH}_3\text{CH}_2\text{CH(Cl)CH}_3 \xrightarrow{\text{alc. KOH, } \Delta} \text{‘A’} \xrightarrow{\text{HBr}} \text{‘B’} \]


(iii) \[ \text{‘A’} \xrightarrow{\text{Mg}} \text{CH}_3\text{CH}_2\text{CH}_2\text{MgCl} \xrightarrow{\text{H}_2\text{O, H}^+} \text{‘B’ (Main product)} \]

Correct Answer:
View Solution

Question 29:

Give explanation for each of the following observations:


(a) \( \text{Mn}^{3+} \) is an oxidising agent, whereas \( \text{Cr}^{2+} \) is a reducing agent (both \( \text{d}^4 \) configuration).

Correct Answer:
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Question 30:

An aqueous solution of NaOH was made and its molar mass from the measurement of osmotic pressure at 27°C was found to be \( 25 \, \text{g mol}^{-1} \). Calculate the percentage dissociation of NaOH in this solution.

Correct Answer:
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Question 31:

A compound ‘A’ with molecular formula \( \text{C}_4\text{H}_8\text{O} \) gives positive 2,4-DNP test. It gives yellow precipitate of compound ‘B’ on treatment with sodium hydrogen sulphite. Compound ‘A’ does not react with Tollen’s or Fehling’s reagent; on oxidation with \( \text{KMnO}_4 \), it forms carboxylic acid ‘C’. Elucidate the structures of ‘A’, ‘B’ and ‘C’. Also give their IUPAC names.

Correct Answer:
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Question 32:

The initial concentration of \( \text{N}_2\text{O}_5 \) in the first order reaction:
\[ \text{N}_2\text{O}_5 (\text{g}) \rightarrow 2\text{NO}_2 (\text{g}) + \frac{1}{2} \text{O}_2 (\text{g}) \]
was \( 1.2 \times 10^{-2} \, \text{mol L}^{-1} \). The concentration of \( \text{N}_2\text{O}_5 \) after 60 minutes was \( 0.2 \times 10^{-2} \, \text{mol L}^{-1} \). Calculate the rate constant of the reaction at 318 K.
[log 6 = 0.778]

Correct Answer:
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Question 33:

Complete the following reactions by writing the structure of the main products:






(I)
\(C(=O)-NHNH_2 + H_{2}NCONHNH_{2}\) \(\rightarrow\)

Correct Answer:
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Question 34:

Give simple chemical test to distinguish the following pairs of compounds:


(I) Ethyl benzoate and benzoic acid

Correct Answer:
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Add NaHCO\textsubscript{3 solution. Benzoic acid gives brisk effervescence (CO\textsubscript{2 gas), but ethyl benzoate does not react.


(II) Propanal and propanone

% Solution
Solution:

Use Tollen’s reagent. Propanal (an aldehyde) gives silver mirror test; propanone (a ketone) does not react.
Quick Tip: Use bicarbonate test for acids; Tollen’s test for aldehydes vs ketones.


Question 35:

Complete each synthesis by giving missing starting material, reagent or products:






(I) \(Ph-CH_2CH_3\) \(\Rightarrow\)(i) \(KMnO_4, KOH\)
(ii) \(H_3O^+\) ?

Correct Answer:
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Question 36:

Carry out the following conversions:


(I) Benzaldehyde to Benzophenone

Correct Answer:
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Question 37:

Give reasons:


(I) \( [\text{Ni}(\text{CO})_4] \) is diamagnetic whereas \( [\text{NiCl}_4]^{2-} \) is paramagnetic.

Correct Answer:
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Question 38:

Using Crystal Field Theory, write the number of unpaired electrons in octahedral complexes of \( \text{Fe}^{3+} \) in the presence of:


(I) Strong field ligand

Correct Answer:
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\( \text{Fe}^{3+} \Rightarrow [\text{Ar}] \, 3\text{d}^5 \).

Strong field ligand causes pairing in \( \text{t}_{2\text{g}} \) orbitals.

So configuration: \( \text{t}_{2\text{g}}^5 \, \text{e}_{\text{g}}^0 \)

Number of unpaired electrons = 1


(II) Weak field ligand

% Solution
Solution:

Weak field ligand does not cause pairing.

So configuration: \( \text{t}_{2\text{g}}^3 \, \text{e}_{\text{g}}^2 \)

Number of unpaired electrons = 5
Quick Tip: Strong field ligands result in fewer unpaired electrons (low spin), while weak field ligands maintain high spin state.


Question 39:

Name the type of isomerism exhibited and draw isomers:


(I) \( [\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6] \)

Correct Answer:
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Question 40:

Differentiate between weak field and strong field ligands. How does the strength of the ligand influence the spin of the complex?

Correct Answer:
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