Absolute Value Formula: Properties and Solved Examples

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Jasmine Grover

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The absolute value of an integer or number refers to the distance of a number from zero or origin in a number line. It is expressed as |a|, which states the magnitude of any integer or number ‘a’. The absolute value of a positive or negative integer or number will be the real numbers, regardless of the sign.  It is denoted by two vertical lines |a|, which is known as the modulus of ‘a’.

Keywords: Absolute value; absolute value formula; mod; modulus; integers; number line; real numbers

Also Read: Determinants


Absolute Value

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The absolute value of an integer or number is the actual distance of that integer from zero, in a number line. Thus, the absolute value is always positive and not a negative number.

The symbol of absolute value is expressed by the modulus symbol, ‘| |’, with the numbers between it. For example, the absolute value of 8 is denoted as |8|.

|x| is read as 'mod x' or 'modulus of x.'

The distance of any integer or number from the origin on the number line is the absolute value of that number. It also displays the polarity of the number whether it is positive or negative. It cannot be negative as it shows the distance and the distance can’t be negative. So, it is always positive.

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Absolute Value Formula

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The absolute values are defined like the following:

  • |x| = +x for x > 0
  • |x| = - x for x < 0

There is no absolute value for zero as the absolute value changes the sign of the numbers into positive and zero has no sign.

If the integer or number is positive then it will result in a positive number only. And if the integer or number is negative, then the modulus of that integer or number will also be a positive number. It is symbolized as |n|, where n is an integer.


Absolute Value Properties

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Sl.No. Absolute value properties Expression
1 Non negativity | x | ≥ 0
2 Positive definiteness | x | = 0 ↔ a = 0
3 Multiplicativity | x × y| = |x| × |y|
4 Subadditivity | x + y| ≤ | x | + | y |
5 Symmetry |-x| = |x|
6 Identity of indiscernible (comparable to positive definiteness) | x – y | = 0 ↔ a = b
7 Triangle inequality (comparable to subadditivity) | x – y | ≤ | x – z | + | z – x |
8 Preservation of division (comparable to multiplicativity) | x / y| = | x | / | y |
9 Equivalent to subadditivity | x – y | ≥ | | x | – | y | |

Absolute Value

Absolute Value


Things to Remember

  • The absolute value of any integer or number signifies the distance of the number from zero in a number line.
  • The symbol to characterize absolute value is |x|, where x is an integer.
  • Absolute value signifies an integer’s distance from zero on the number line without taking direction into account. An integer’s absolute value is never negative.
  • Absolute values are necessary because sometimes we just need to use positive values, and the absolute value is a handy tool for this. If we see an absolute value in a problem or equation, it signifies that everything inside it is always positive. Absolute values are often useful in distance questions and are sometimes used in inequalities.

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Sample Questions

Ques: What is the absolute value of a number -12/5? (2 marks)

Ans: |-12/5|

|-12/5| = 12/5

Thus, the absolute value of a number -12/5 is 12/5

Ques: Find the absolute value for the following numbers: (3 marks)
(a) |-1/2|
(b) |72|
(c) |3/4|

Ans: The absolute value of the numbers is:

(a) |-1/2| = ½

(b) |72| = 72

(c) |3/4| = ¾

Ques: What is the value of 2 | 5x – 1 | if x = – 2?(3 marks)

Ans: 2|5x – 1| = 2|5 (-2) – 1|
=> 2| 5x – 1| = 2| -10 – 1|
=>2| 5x – 1| = 2| -11|
=>2| 5x – 1| = 2 × 11
=>2| 5x – 1| = 22

Ques: Solve 4|x – 2| = 16 (3 marks)

Ans: 4 |x – 2| = 16
=>|x – 2| = 16/4
=> x – 2| = 4
=>x – 2 = 4 or x – 2 = – 4
=>x = 4 + 2 or x = – 4 + 2
=>x = 6 or – 2

Ques: Solve |5 – 3x| = 12(3 marks)

Ans: |5 – 3x| = 12

5 – 3x = 12 or 5 – 3x = –12

–3x = 7 or –3x = –7

x = –7/3 or x = 17/3

Ques: Solve |4x – 3|= |x + 6| (3 marks)

Ans: |4x – 3|= |x + 6|

⇒4x – 3 = x + 6 or ⇒ 4x – 3 = – (x + 6)

⇒ 3x = 9 or ⇒ 4x – 3 = – x – 6

⇒ x = 3 or ⇒ 5x = –3

⇒ x = 3 or ⇒ x = –3/5

Ques:  Solve |2x+3|<6 (3 marks)

Ans: |2x+3|<6

⇒–6 < 2x+3 < 6

⇒–6 –3 <2x + 3 – 3 < 6 –3

⇒–9 < 2x < 3

⇒−9/2 < x < 3/2

Thus, the solution to the given absolute value inequality is the interval (−9/2 < x < 3/2).

Ques: Find all the possible values of xx which satisfy |2x|=16 (2 marks)

Ans: Given, |2x|=16
⇒2x=±16
⇒2x=16or 2x=–16
⇒x=8or x=–8

Ques: Simplify –|–8+4–3| (2 marks)

Ans: Given, –|–8+4–3|
⇒–|–11+4|

⇒–|–7|

⇒–7

Ques. What is the absolute value of 20–36(2) +2(40–37)? (2 marks)

Ans: Given, |20–36(2) +2(40–37) |
⇒|20–72+6|
⇒|–46|=46

Ques. Solve the equation given below |x+4|=5 (2 marks)

Ans: |x+4|=5
⇒x+4=±5
⇒x+4=5⇒x+4=5 or x+4=–5x+4=–5
⇒x=1⇒x=1 or x=–9x=–9

Ques. Solve the equation |x|=x+2. (2 marks)

Ans: |x|=x+2
⇒x=±(x+2)
⇒x=x+2⇒x=x+2    or   ⇒x=–x–2⇒x=–x–2
⇒x=–1

Ques: Solve |2x – 5| = x + 4 (3 marks)

Ans: 2x – 5 = x + 4 or 2x – 5 = -(x + 4)

2x – x = 5 + 4  or 2x – 5 = -x – 4

x = 9   or    2x + x = 5 – 4

3x = 1

 x = 1/3

Thus, the possible values of x after solving the equation |2x – 5| = x + 4 are 9, 1/3.

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CBSE CLASS XII Related Questions

  • 1.

    At a birthday party, children are being served orange juice in conical cups, as shown in the figure. 


    Each cup is 15 cm deep and has a radius 5 cm. The juice is being poured into this cup at a rate of 0·1 cm3/s.
    On the basis of the above information, answer the following questions :


      • 2.
        Find:

        If the function \[ f(x)= \begin{cases} \frac{\sin x}{x}+\cos x, & x\neq0\\ k, & x=0 \end{cases} \] is continuous at \(x=0\), then find the value of \(k\).

          • \(0\)
          • \(-2\)
          • \(-1\)
          • \(2\)

        • 3.
          Find the vector and cartesian equations of the line passing through the point of intersection of the lines \( \vec{r} = (\hat{i} + \hat{j} - \hat{k}) + \lambda(3\hat{i} - \hat{j}) \) and \( \vec{r} = (4\hat{i} - \hat{k}) + \mu(2\hat{i} + 3\hat{k}) \) and parallel to the line \( \frac{x - 1}{-2} = \frac{7 - y}{-3} = z \).


            • 4.
              If \( xy = e^{x - y} \), then find \( \frac{dy}{dx} \).


                • 5.
                  Find a point on the line \( \frac{x - 2}{3} = \frac{1 - y}{2} = \frac{z - 3}{2} \) at a distance of \( \sqrt{2} \) units from the point \( (1, 2, 3) \).


                    • 6.
                      Find:

                      If \[ (3\hat{i}-2\hat{j}+5\hat{k})\times(4\hat{i}+p\hat{j}+q\hat{k})=\vec{0} \] then find the values of \(p\) and \(q\).

                        • \(p = -\frac{2}{3}, \, q = \frac{5}{3}\)
                        • \(p = -\frac{8}{3}, \, q = \frac{20}{3}\)
                        • \(p = \frac{20}{3}, \, q = -\frac{8}{3}\)
                        • \(p = 0, \, q = 0\)
                      CBSE CLASS XII Previous Year Papers

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