How do you solve an unbalanced bridge?

The unbalanced Wheatstone Bridge can be solved by the use of Kirchhoff’s Current Law and Voltage Law.

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Wheatstone Bridge – Important Topics
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Types of Circuits	Difference between air conditioning and refrigeration	Voltage
Current	Difference between kva and kw	Electrical Formula
Electric Dipole	Relation between kva and kw	Combination of Resistors
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Static Electricity	Ohm’s Law and its Limitations	Resistor Colour Codes
Current Electricity	Resistivity Temperature Dependence	Permittivity And Permeability
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Resistance	Difference Between Primary Cell and Secondary Cell	Resistivity formula
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CBSE CLASS XII Related Questions

1.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.
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2.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:
- attract with a force \( \frac{F}{2} \)
- repel with a force \( \frac{F}{2} \)
- repel with a force \( F \)
- attract with a force \( F \)
View Solution
3.
If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.
View Solution
4.
Write any two features of nuclear forces.
View Solution
5.
Two heaters rated as \((P_1,V)\) and \((P_2,V)\) are connected in series across a dc source of \(V/2\) volt. The power consumed by the combination will be –
- \((P_1+P_2)\)
- \(\dfrac{P_1+P_2}{2}\)
- \(\dfrac{P_1P_2}{2(P_1+P_2)}\)
- \(\dfrac{P_1P_2}{4(P_1+P_2)}\)
View Solution
6.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:
- \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
- \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
- \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
- Zero
View Solution

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Meter Bridge: Definition, Working Principle & Examples

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CBSE CLASS XII Previous Year Papers

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Physics Preparation Guides

Electric Charges and Fields: Flux, Gauss Law & Coulomb's Law

Applications of Gauss Law: Formula & Gauss Theorem

Coulomb’s Law: Formula, Vector Form & Limitations

Electric Charge: Definition, Formula, Types and Properties

Electric Field: Definition, Formula & Electric Field Direction

Gauss Law: Formula, Gauss Theorem & Electric Flux

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Electric Dipole: Definition, Significance and Electric Dipole Moment

Electric Flux: Formula, Equation, Symbol & SI Unit

Electrostatic Potential: Definition, Formula and SI Unit

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Pressure Formula: Partial, Osmotic & Absolute Pressure

NCERT Solutions For Class 12 Physics Chapter 1: Electric Charges and Fields

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NCERT Solutions for Class 12 Physics Chapter 13: Nuclei

NCERT Solutions For Chapter 14: Semiconductor Electronics

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