MCQs On Voltage Divider Formula

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A voltage divider is a resistor or series of resistors or capacitors which is provided with taps at a certain point and used to provide various potential differences from a single power source. A voltage dividers are very useful in providing different voltage levels from a common supply voltage and the common supply is a single supply either positive or negative.

MCQs On Voltage Divider Formula

Ques. Find the value displayed by a voltmeter in the given image. (1 Mark)

1V
1A
4A
4V

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Ans. a. 1V

Explanation: Voltage across is 1KΩ is;

V1 = R1/ R1+R2 *V

Putting value in the formula:

V2 = 1/1+4 * 5 = 1V

Ques. Calculate potential difference across 60-watt lamps; Two 220-volt lamps, the first 60 watt and the second 75 watt are connected to a series of 440-volt supplies. (1 Mark)

300 volt
245 volt
200 volt
345 volt

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Ans. b 245 volt

Explanation: Given;

P1 - 60W; P2 - 75W

V1 - 200V; V2 - 440V

Ques. Where the current division problem arises (1 Mark)

Series connected resistors
Parallel connected resistors
When resistors are equal
Both series and parallel resistors.

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Ans. d. Both series and parallel resistors.

Explanation: The current division problem arises in both series and parallel resistors.

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Ques. 490Ω is connected across a voltage source Vs = 150V. The internal resistance of a source is 10Ω. Calculate the output voltage across the load. (1 Mark)

180V
150V
147V
120V

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Ans. C. 147V.

Explanation: V = Vs * RL/RL+RS

V = 150 * 490/ 490+10

V = 150 * 490/ 500

V = 147V

Ques. Evaluate the value of resistor R1 in the given figure. (1 Mark)

1.3Ω
1.5Ω
1.7Ω
1.9Ω

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Ans. b. 1.5Ω

Explanation: The voltage across R1= 6V

Current through R1 = I=4A

Therefore,

6V = 4R1

Hence R1 = 6/4 = 1.5Ω

Ques. R1 = 1Ω, R2 = 3Ω, R3 = 5Ω and R4 = 7Ω connected in series. Total voltage = 20V, Current I, V2 =? (1 Mark)

I = 1.16, V2 = 3.72
I = 1.25, V2 = 3.75
I = 1.15, V2 =3.73
I = 1.23, V2 = 3.75

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Ans. d. I = 1.23, V2 = 3.75

Explanation: V = I/R

V = I (R1+R2)

R1 R2 = 12.26V

I1 = 1R2/ R1 = R2 = 1.725A

I2 = IR1/ R1+R2

= 2.875A

Ques. Voltage division is necessary for parallel resistance networks (1 Mark)

False
True

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Ans. a. False

Explanation: In parallel, the connection voltage is the same so division is not required.

Ques. Why is the current division necessary? (1 Mark)

Due to different voltage
Kirchhoff's Law
In parallel current differs
In series current, it is the same

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Ans. c. In parallel current differs

Explanation: because in parallel the current differs from all

Ques. Find i =? (1 Mark)

Find i =?

-1A
-2A
+1A
+2A

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Ans. d. +2A

Explanation: i = 1/1+3(8)

= 2A

Ques. What is an internal voltage drop in an ideal constant voltage source? (1 Mark)

Zero
High
Low
Moderate

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Ans. a. Zero

Explanation: An ideal voltage source has zero source resistance.

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MCQs On Voltage Divider Formula

MCQs On Voltage Divider Formula

CBSE CLASS XII Related Questions

1.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

2.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

3.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

4.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

5.
Write any two features of nuclear forces.

6.
Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

Similar Physics Concepts

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MCQs On Voltage Divider Formula

MCQs On Voltage Divider Formula

CBSE CLASS XII Related Questions

1. If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

2.Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

3.The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

4.Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

5. Write any two features of nuclear forces.

6.Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
If Bohr’s quantization postulate (angular momentum \( = \frac{nh}{2\pi} \)) is a basic law of nature, it should be equally valid for the case of planetary motion also. Why, then, do we never speak of quantization of orbits of planets around the Sun? Explain.

2.
Two small identical metallic balls having charges \( q \) and \( -2q \) are kept far at a separation \( r \). They are brought in contact and then separated at distance \( \frac{r}{2} \). Compared to the initial force \( F \), they will now:

3.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

4.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

5.
Write any two features of nuclear forces.

6.
Assertion (A) : All atoms have a net magnetic moment. Reason (R) : A current loop does not always behave as a magnetic dipole.