MCQs On Voltage Divider Formula

Collegedunia Team logo

Collegedunia Team

Content Curator

A voltage divider is a resistor or series of resistors or capacitors which is provided with taps at a certain point and used to provide various potential differences from a single power source. A voltage dividers are very useful in providing different voltage levels from a common supply voltage and the common supply is a single supply either positive or negative.


MCQs On Voltage Divider Formula 

Ques. Find the value displayed by a voltmeter in the given image. (1 Mark)

  1. 1V
  2. 1A
  3. 4A
  4. 4V

 Find the value displayed by a voltmeter in the given image

Click here for the answer

Ans. a. 1V

Explanation: Voltage across is 1KΩ is;

V1 = R1/ R1+R2 *V

Putting value in the formula:

V2 = 1/1+4 * 5 = 1V

Ques. Calculate potential difference across 60-watt lamps; Two 220-volt lamps, the first 60 watt and the second 75 watt are connected to a series of 440-volt supplies. (1 Mark)

  1. 300 volt
  2. 245 volt
  3. 200 volt
  4. 345 volt

Click here for the answer

Ans. b 245 volt

Explanation: Given;

P1 - 60W; P2 - 75W

V1 - 200V; V2 - 440V

Ques. Where the current division problem arises (1 Mark)

  1. Series connected resistors
  2. Parallel connected resistors
  3. When resistors are equal
  4. Both series and parallel resistors.

Click here for the answer

Ans. d. Both series and parallel resistors.

Explanation: The current division problem arises in both series and parallel resistors.

Also Check:

Ques. 490Ω is connected across a voltage source Vs = 150V. The internal resistance of a source is 10Ω. Calculate the output voltage across the load. (1 Mark)

  1. 180V
  2. 150V
  3. 147V
  4. 120V

Click here for the answer

Ans. C. 147V.

Explanation: V = Vs * RL/RL+RS

V = 150 * 490/ 490+10

V = 150 * 490/ 500

V = 147V

Ques. Evaluate the value of resistor R1 in the given figure. (1 Mark)

  1. 1.3Ω
  2. 1.5Ω
  3. 1.7Ω
  4. 1.9Ω

Evaluate the value of resistor R1 in the given figure

Click here for the answer

Ans. b. 1.5Ω

Explanation: The voltage across R1= 6V

Current through R1 = I=4A

Therefore, 

6V = 4R1

Hence R1 = 6/4 = 1.5Ω

Ques. R1 = 1Ω, R2 = 3Ω, R3 = 5Ω and R4 = 7Ω connected in series. Total voltage = 20V, Current I, V2 =? (1 Mark)

  1. I = 1.16, V2 = 3.72
  2. I = 1.25, V2 = 3.75
  3. I = 1.15, V2 =3.73
  4. I = 1.23, V2 = 3.75

Click here for the answer

Ans. d. I = 1.23, V2 = 3.75

Explanation: V = I/R

V = I (R1+R2)

R1 R2 = 12.26V

I1 = 1R2/ R1 = R2 = 1.725A

I2 = IR1/ R1+R2

= 2.875A

Ques. Voltage division is necessary for parallel resistance networks (1 Mark)

  1. False
  2. True

Click here for the answer

Ans. a. False

Explanation: In parallel, the connection voltage is the same so division is not required.

Ques. Why is the current division necessary? (1 Mark)

  1. Due to different voltage
  2. Kirchhoff's Law
  3. In parallel current differs
  4. In series current, it is the same

Click here for the answer

Ans. c. In parallel current differs

Explanation: because in parallel the current differs from all

Ques. Find i =? (1 Mark)

Find i =?

  1. -1A
  2. -2A
  3. +1A
  4. +2A

Click here for the answer

Ans. d. +2A

Explanation: i = 1/1+3(8)

= 2A 

Ques. What is an internal voltage drop in an ideal constant voltage source? (1 Mark)

  1. Zero
  2. High
  3. Low
  4. Moderate

Click here for the answer

Ans. a. Zero

Explanation: An ideal voltage source has zero source resistance.

Also Check:

CBSE CLASS XII Related Questions

  • 1.
    Two thin lenses of focal length \( f_1 \) and \( f_2 \) are placed in contact with each other coaxially. Prove that the focal length \( f \) of the combination is given by \[ f = \frac{f_1 f_2}{f_1 + f_2}. \]


      • 2.
        Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.


          • 3.
            If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.


              • 4.
                Suppose a pure Si crystal has \( 5 \times 10^{28} \) atoms per \( \text{m}^3 \). It is doped with \( 5 \times 10^{22} \) atoms per \( \text{m}^3 \) of Arsenic. Calculate majority and minority carrier concentration in the doped silicon. (Given: \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \))


                  • 5.
                    A long solenoid of length \( L \) and radius \( r_1 \) having \( N_1 \) turns is surrounded symmetrically by a coil of radius \( r_2 \, (r_2>r_1) \) having \( N_2 \) turns (\( N_2 \ll N_1 \)) around its mid-point. Derive an expression for the mutual inductance of solenoid and coil. Is \( M_{12} = M_{21} \) valid in this case?


                      • 6.
                        What is displacement current (\( i_d \))? Considering the case of charging of a capacitor, show that \( i_d = \varepsilon_0 \frac{d\Phi_E}{dt} \). What is the value of \( i_d \) for a conductor across which a constant voltage is applied?

                          CBSE CLASS XII Previous Year Papers

                          Comments


                          No Comments To Show