The relationship between Kp and Kc is Kp = Kc (RT)Δn
Derivation of Relation between Kp and Kc
For a general reaction aA + bB ⇌ cC + dD
Kc is an equilibrium constant denoted in terms of molar concentrations.
Kc = \({[C]^c[D]^d \over [A]^a[B]^b}\)
Kp is an equilibrium constant denoted in terms of partial pressures.
Kp = \((PC)^c(PD)^d \over (PA)^a(PB)^b\)
P = \(nRt \over V\)= [Conc]RT
Kp = \({([C]RT)^c([D]RT)^d \over ([A]RT)^a([B]RT)^b} = Kc {(RT)^c(RT)^d \over (RT)^a(RT)^b}\)
Therefore, the relation between Kp and Kc is expressed as –
Kp = KcRTΔn
Kp and Kc Related Questions
- In the reaction, 2NO ⇌ N2 + O2, are the values of Kc and Kp the same?
- What is the relation between kp and kc for a gaseous reaction, 2B -> A?
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