Two resistors X and Y with 2 Ω and 3 Ω resistances respectively are first connected parallelly and then in series. If voltage supplied is 5V, then:
(i) Draw the circuit diagram in order to depict the combination of resistors:

Resistance
(ii) Estimate voltage across the 3 Ω resistor in the series combination of resistors.
- Resistance of X = R1 = 2Ω
- Resistance of Y = R2 = 3Ω
- Voltage, V = 6V
In order to find the voltage across a 3Ω resistor in the series combination of resistors, we have to
We are already aware that the equivalent resistance (total resistance) in a series combination can be expressed as:
| Req = R1 + R2 |
Now, after replacing the values of R1 and R2 we will get:
⇒ Req= 2 + 3
⇒ Req = 5Ω
We know that current can be expressed as:
I = V/R
Here, I = V/Req
So, inserting the given values, we will get:
I = 55
I = 1A
Therefore, the current passing through the circuit is 1A.
Now, in order to find the voltage present across 3Ω resistors, we can also use the formula of voltage:
V = I × R
Now, after placing the required values, we get:
⇒ V = 1 × 3
⇒ V = 3V
Hence, the voltage across the 3Ω resistor is 3 Volts.
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