Unit of Current Important Questions

Collegedunia Team logo

Collegedunia Team

Content Curator

Unit of Current is Ampere. It is denoted by the symbol A. It is also denoted by the shorted form ‘amps’. One ampere is equal to 6.241509074 × 1018 electrons worth of charge moving past a point in a second. The charge of an electron e is 1.602 176634 ×10-19 Coulomb. Unit of current is an SI unit and thus used universally for all current measurements. This topic is under Class 12 Chapter 3 Current Electricity

Check Out:


Important Questions on Unit of Current

Ques 1. Define Ampere. (2 marks)

Ans. Ampere is the flow of electric charge at the rate of 1 coulomb per second. Ampere is denoted by the symbol A.

Ques 2. What are the uses of Ammeter? (2 marks)

Ans. Ammeter is a device used to measure electric current. It can measure both alternating current and direct current. It is connected in series inorder to measure the current.

Ques 3. Calculate the resistance of a light bulb if its voltage is 10V and carries a current 5A. (3 marks)

Ans: By Ohm’s law,

V = IR

R = V/I

R =10/5

R = 2 Ohms

Ques 4. A battery connected to a 0.8 amp light bulb can effectively store 5,500 C of charge when fully charged. How long will the battery last before going dead if the light is left on? (3 marks)

Ans. We know that

I = Q/t

t = Q/I

= 5500/0.8

= 6875 sec

= 1.91 hours

Ques 5. A light bulb draws 300mA of current when its voltage is 240V. Calculate the resistance. (3 marks)

Ans. I = 300mA = 300/1000 A

= 0.3 A

V = 240V

By Ohm’s law,

V = IR

R = V/I

R = 240/0.3

R = 800 Ohms

Ques 6. Calculate the current passing through an electrical device of resistance 10 ohms and voltage 100V. (3 marks)

Ans. R = 10 ohms

V = 100V

By Ohm’s law,

V = IR

I = V/R

= 100/10

= 10 Ampere

Ques 7. What is electric current? (2 marks)

Ans. The rate of flow of charges through a conductor with a defined potential difference is called electric current. If Q is the charge flowing through a conductor in a time interval of t, then current I is given by,

I = Q/t

Ques 8. If current flowing through a conductor for 6 minutes id 0.6A, find the charge. (3 marks)

Ans. We know that,

I = Q/t

Q = ?

I = 0.6A

t = 6 min = 360 sec

Q = Ixt

= 0.6 x 360

= 216 C

Ques 9. If 2A current flows for 5 minutes, the amount of charge flowing through the conductor is? (3 marks)

Ans. We know that,

I = Q/t

I = 2A

t = 5 min = 300 sec

Q = Ixt

= 2 x 300

= 600C

Ques 10. If 600C charge flows for 5 minutes, calculate the current flowing through the conductor.  (3 marks)

Ans. We know that,

I = Q/t

I = ?

Q = 600C

t = 5 min = 300 sec

I = Q/t

= 600/300

= 2A

Check Out:

CBSE CLASS XII Related Questions

  • 1.
    Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.


      • 2.
        A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of 60° in 0.2 s. The value of emf induced in the loop will be:

          • 5 V
          • 3.5 V
          • 2.5 V
          • Zero V

        • 3.
          Draw the number of scattered particles versus the scattering angle graph for scattering of alpha particles by a thin foil. Write two important conclusions that can be drawn from this plot.


            • 4.
              Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.


                • 5.
                  If both the number of protons and the neutrons are conserved in each nuclear reaction, in what way is mass converted into energy (or vice versa) in a nuclear reaction? Explain.


                    • 6.
                      The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

                        • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
                        • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
                        • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
                        • Zero
                      CBSE CLASS XII Previous Year Papers

                      Comments


                      No Comments To Show