Electric Current MCQs with Solutions

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Electric current is the flow of electric charges in a closed circuit. The SI unit of current is Ampere (A). 1 Ampere is the current produced due to the flow of 1 coulomb of charges in one second. Depending upon the direction of flow of current, it is divided into two types - Alternating current and Direct current. 

Electric current is measured with the help of a device called Ammeter. An ammeter is always connected in series in a circuit. It has negligible resistance, thus it draws no current from the circuit to which it is connected. 

Check Also: CBSE Class 12 Physics Notes


MCQs on Electric Current

Ques 1. While connecting 6 cells in a battery in series, in a tape recorder, by mistake one cell is connected with reverse polarity. If the effective resistance of load is 24 Ω and internal resistance of each cell is 1 Ω and emf is 1.5 V, the current delivered by the battery is:

  1. 0.1 A
  2. 0.2 A
  3. 0.3 A
  4. 0.4 A

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Ans. (b). 0.2 A

Explanation: Applying KVL to the loop, 

4E = I [R + 6r]

4 × 1.5 = I [30]

I = 6/30

I = 1/5 = 0.2 A

Ques 2. A 5°C rise in temperature is observed in a conductor by passing a current, when the current is doubled, the rise in temperature will be nearly

  1. 10°C
  2. 16°C
  3. 20°C
  4. 12°C

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Ans. P = I2R

If I is doubled, the power will be 4 times

and, ΔT ∝ P 

If power is increased 4 times, then ΔT will also increase by 4 times

so, 4 × 5°C = 20°C

Ques 3. Assertion: When current through a bulb decreases by 0.5%, the glow of the bulb decreases by 1%. 

Reason: Glow (Power) is directly proportional to square of current. 

  1. Both assertion and reason are true and reason is the correct explanation of the assertion
  2. Both assertion and reason are true but reason is not the correct explanation for assertion
  3. Assertion is correct but reason is incorrect
  4. Both assertion and reason are incorrect

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Ans. (a). Both assertion and reason are true and reason is the correct explanation of the assertion

Explanation: P = I2R

Pf / Pi = If2 / Ii2 (R = constant) ………(i)

If = Ii - Ii (0.5)/100 = 0.995 Ii 

If / Ii = 0.995

From (i)

Pf / Pi = (0.995)2 = 0.99

Power decreased = (Pi - Pf / Pi) × 100 = 1%

Ques 4. Three resistors each of 10Ω are connected in series to a battery of potential difference 150 V. The current flowing through it is:

  1. 45 A
  2. 15 A
  3. 20 A
  4. 5 A

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Ans. (d). 5 A

Explanation: V = IR

V = I × Req 

I = V / Req 

The three resistances are in series. So, the equivalent resistance will be; 

Req = R1 + R2 + R3 

Req = 10 + 10 + 10

Req = 30 Ω

I = 150/30 

I = 5 A

Ques 5. The resistance of an iron wire is 10 Ω and its temperature coefficient of resistance is 5 × 10-3/°C. A current of 30 mA is flowing in it at 20°C. Keeping potential difference across its ends constant, if its temperature is increased to 120°C then the current flowing in the wire will be (in mA)

  1. 20
  2. 10
  3. 15
  4. 40

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Ans. (a). 20

Explanation: Temperature coefficient of resistance, α = 5 × 10-3 /°C

Initial Temperature, To = 20°

Initial Resistance at To , Ro = 10 Ω

Initial Current at To , Io = 30 mA

Increased temperature, T1 = 120°

Increased resistance, 

R1 = Ro [1 + α (T1 - To)]

R1 = 10 [1 + 5 × 10-3 (120 - 20)]

R1 = 10 [1 + 5 × 10-1]

R1 = 10 [1 + 0.5]

R1 = 10 [1.5] 

R1 = 15 Ω

Now, potential difference across the wire is constant,

V = IoRo = I1R1 

I1 = IoRo / R1 

I1 = 30 × 10 / 15

I1 = 300/15 

I1 = 20 mA

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Ques 6. A steady current is passing through a linear conductor of non-uniform cross-section. The net quantity of charge crossing any cross-section per second is:

  1. Independent of area of cross-section
  2. Directly proportional to the length of the conductor
  3. Directly proportional to the area of the cross section
  4. Inversely proportional to the length of the conductor

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Ans. (a). Independent of area of cross-section

Explanation: The quantity of charge passing through the cross-section is the current flowing in it. It is given in the question that the current is steady. Therefore, it is independent of the area of cross-section. 

Ques 7. For a chosen non-zero value of voltage, there can be more than one value of current in: 

  1. Copper wire
  2. Thermistor
  3. Nichrome wire
  4. Manganin wire

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Ans. (b). Thermistor

Explanation: Thermistor are made up of substance that have a high value of temperature coefficient of resistance (α), thus a slight change in temperature can vary its resistance to a high amount. This increases the possibility of more than one value of current. 

Ques 8. A 24 V potential difference is applied across a parallel combination of four 6Ω resistor. The current in each resistor is:

  1. 4 A
  2. 1 A
  3. 36 A
  4. 16 A

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Ans. (a). 4 A

Explanation: As the resistors are connected in parallel, the voltage across each resistor is the same i.e. 24 V.

So, current in each resistor is,

I = V/R 

I = 24/6 = 4 A

Ques 9. What steady current can be drawn from an accumulator of capacity 80 Ah?

  1. 4 A for 20 hours
  2. 40 A for 6 hours
  3. 20 A for 5 hours
  4. 2 A for 100 hours

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Ans. (a). 4 A for 20 hours

Explanation: The capacity of the accumulator is 80 Ah. So, either a current of 80 A can be drawn for 1 hour or less current can be drawn for a longer period. 

I = dQ/dt = Q/t

Q = 4 A × 20 hrs = 80 Ah

Ques 10. Name the instrument used to control the current in an electric circuit.

  1. Rheostat
  2. Voltmeter
  3. Ammeter
  4. Galvanometer

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Ans. (a). Rheostat

Explanation: A rheostat can be used to control current in an electric circuit. It is a variable resistor that can control electrical resistance of a circuit without influencing the flow of current. Rheostats are used in applications that require high voltage and current. 

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CBSE CLASS XII Related Questions

  • 1.
    The resistance of a metal wire at \(20^\circ\text{C}\) is \(1.05\,\Omega\) and at \(100^\circ\text{C}\) is \(1.38\,\Omega\). Determine the temperature coefficient of resistivity of this metal.


      • 2.

        A magnet held vertically, with its north pole down, is dropped along the axis of a closed solenoid placed vertically on a table. If the observer looks down from the top,

          • the induced current will flow in the anticlockwise direction.
          • the induced current will flow in the clockwise direction.
          • no induced current will flow in the solenoid.
          • the magnet will fall with a constant velocity.

        • 3.

          (I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.

          (II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.


            • 4.

              A rectangular loop of size 5 cm $\times$ 8 cm is lying in the $x$-$y$ plane in a uniform magnetic field $\vec{B} = (2.0\ \text{T})\hat{k}$. The total magnetic flux linked with the loop is:

                • 80 Wb
                • 16 Wb
                • \(8 \times 10^{-2}\) Wb
                • \(8 \times 10^{-3}\) Wb

              • 5.
                Consider the nuclear reaction \( X \to Y + Z \). Let \( M_x \), \( M_y \), and \( M_z \) be the masses of the three nuclei X, Y, and Z respectively. Then which of the following relations hold true?

                  • \( (M_x - M_z)<M_y \)
                  • \( (M_x - M_y)<M_z \)
                  • \( M_x>(M_y + M_z) \)
                  • \( M_x<(M_y + M_z) \)

                • 6.

                  A parallel beam of monochromatic light falls normally on a single slit of width $a$ and a diffraction pattern is observed on a screen placed at distance $D$ from the slit. Explain:

                  (I) the formation of maxima and minima in the diffraction pattern, and

                  (II) why the maxima go on becoming weaker and weaker with its increasing number $n$.

                    CBSE CLASS XII Previous Year Papers

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