NCERT Solutions for class 12 Chemistry Chapter 1: The Solid State

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Jasmine Grover

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NCERT Solutions for class 12 Chemistry Chapter 1 The Solid State are provided in this article. Some of the important concepts covered in this topic include:

  1. Amorphous and Crystalline Solids
  2. Crystal Lattices and Unit Cells
  3. Packing Efficiency
  4. Imperfections in Solids
  5. Magnetic Properties
  6. Impurity Defects
  7. Covalent Bond
  8. Schottky Defect
As this chapter has been omitted in the new CBSE Class 12 Syllabus, it does not have any weightage but is useful in preparing for competitive exams. 

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 1 pdf


NCERT Solutions for Class 12 Chemistry Chapter 1

NCERT Solutions for Class 12 Chemistry Chapter 1 Solid State is given below. 

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Class 12 Chemistry Chapter 1: Solid State – Important Topics

Some of the important topics in Class 12 Chemistry Chapter 1: Solid State is given below

  • Types of Solids – Crystalline and Amorphous Solids

Properties of Crystalline Solids:

  • They have fixed geometrical shapes.
  • Crystalline solids have their constituent particles arranged in long-range order.
  • They have a fixed melting point.
  • They have fixed heat of fusion.
  • They are anisotropic.
  • They are considered as true solids.

Properties of Amorphous Solids:

  • They have an irregular shape.
  • Amorphous solids have their constituent particles arranged in short-range order.
  • When heated, they soften and do not have a sharp melting point.
  • They do not have a sharp melting point.
  • They are isotropic.
  • They are considered as pseudo solids or super cooled liquids.

Solid State

Solid State

  • Types of Bonding – Ionic Bond, Covalent Bond

Ionic Bond: Ionic bond is formed by the exchange of electrons between two reacting molecules. It usually occurs between metals and non metals (eg: Sodium and Chlorine) where there is an interchange of oppositely charged particles.

Covalent Bond: Covalent Bond is the sharing of electrons between two molecules to form a new product. This types of bonding is not as strong as Ionic bonds.

Some of the factors which determine the type of Bonding are called as Bond parameters. They include:

  • Bond Length
  • Bond Angle
  • Bond Enthalpy
  • Bond Order
  • Resonance Structures
Lattice Enthalpy: It is the amount of energy required to separate one mole of crystalline ionic compounds from its constituent gaseous ions.

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CBSE CLASS XII Related Questions

  • 1.
    Following reaction takes place in one step:

    \(2A + B \rightarrow 2C\)

    How will the rate of above reaction change if the volume of the reaction vessel is decreased to one third of its original volume? Will there be any change in the order of reaction with the reduced volume?


      • 2.

        A reaction \( \mathrm{A \rightarrow B} \) follows second order kinetics. How will the rate of reaction be affected if the concentration of (i) A is increased by three times, and (ii) A is reduced to half ?


          • 3.

            (i) Why do Zr and Hf exhibit similar properties ?

            (ii) "\( E^\circ \) for \( \mathrm{Mn^{3+}/Mn^{2+}} \) couple is more positive than that for \( \mathrm{Fe^{3+}/Fe^{2+}} \)." Justify the statement.

            [Atomic number : Mn = 25, Fe = 26]


              • 4.

                (a) Define 'Denatured Protein' with an example.

                (b) What happens when glucose reacts with HCN ? Write the reaction involved.

                (c) Name the disease caused by the deficiency of Vitamin C.


                  • 5.
                    An organic compound (X) has the molecular formula \(C_5H_{10}O\). Draw structures for (X) if it:
                    (I) does not give Tollen's test but gives a positive iodoform test.
                    (II) does not give Tollen's test and iodoform test but undergoes Aldol condensation.
                    (III) undergoes Cannizzaro's reaction.


                      • 6.

                        Conductivity of \( 2.5 \times 10^{-4} \) M methanoic acid solution is \( 5.25 \times 10^{-5} \) S cm\(^{-1}\).

                        (a) Calculate its molar conductivity.

                        (b) Calculate its degree of dissociation.

                        [Given : \( \lambda^{\circ}_{(\mathrm{H^+})} = 349.5 \) S cm\(^2\) mol\(^{-1}\) and \( \lambda^{\circ}_{(\mathrm{HCOO^-})} = 50.5 \) S cm\(^2\) mol\(^{-1}\)]

                          CBSE CLASS XII Previous Year Papers

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