NCERT Solutions For Class 12 Chemistry Chapter 5: Surface Chemistry

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NCERT Solutions for Class 12 Chemistry Chapter 5 Surface Chemistry deals with the concepts of catalysis, adsorption, and colloids that comprise gels and emulsions. Some of the important topics of Class 12 Surface Chemistry chapter include:

As this topic has been omitted from the new CBSE Class 12 syllabus, no questions can be expected from this chapter. But it proves to be useful for other competitive examinations.

Download PDF: NCERT Solutions for Class 12 Chemistry Chapter 5 Surface Chemistry

NCERT Solutions for Class 12 Chemistry Chapter 5

The NCERT Solutions for class 12 Chemistry chapter 5 are as given below.

NCERT Solutions

Class 12 Chemistry Chapter 5 Surface Chemistry – Important Topics

Surface Chemistry is the study of the various phenomenon that takes place over chemical surfaces.

Adsorption: The process of attraction and aggregation of the molecules of a substance on the surface of a solid is known as adsorption.
Corrosion: The process through which the refined unstable metals convert themselves into more stable compounds is known as corrosion.
Crystallization: The type of technique that is used in order to purify the substances to separate solids from liquids is known as crystallization

Emulsions are colloidal solutions where both the dispersion medium and dispersed phase are in liquid state. They can be either oil in water or water in oil emulsions.

Surface chemistry finds its application in the process of Catalysis, Chromatography and Colloidal formations.

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CBSE CLASS XII Related Questions

1.
Draw the structures of major monohalo products in each of the following :
(a)
(b)
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2.
(i) A first order reaction is 20% complete in 10 minutes. Calculate the time taken when 80% of the reaction will be completed.
[Given : log 5 = 0.7, log 4 = 0.6]
(ii) For a chemical reaction \( \mathrm{R \rightarrow P} \), variation in \( \ln[\mathrm{R}] \) vs. time (t) graph is given below :
(I) Predict the order of the reaction.
(II) Write the slope of the curve.
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3.
(i) Give a chemical test to distinguish between Propanal and Propanone.
(ii) Which of the given acids is stronger and why ? \( \mathrm{F_3C{-}C_6H_4{-}COOH} \) or \( \mathrm{H_3C{-}C_6H_4{-}COOH} \)
(iii) Complete the given reaction sequence :
\[ \mathrm{CH_3CH_2CH_2COOC_2H_5} \xrightarrow{\mathrm{NaOH}} \mathrm{A + C_2H_5OH} \]
\[ \mathrm{A} \xrightarrow{\mathrm{H_3O^+}} \mathrm{B} \]
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4.
Conductivity of \( 2.5 \times 10^{-4} \) M methanoic acid solution is \( 5.25 \times 10^{-5} \) S cm\(^{-1}\).
(a) Calculate its molar conductivity.
(b) Calculate its degree of dissociation.
[Given : \( \lambda^{\circ}_{(\mathrm{H^+})} = 349.5 \) S cm\(^2\) mol\(^{-1}\) and \( \lambda^{\circ}_{(\mathrm{HCOO^-})} = 50.5 \) S cm\(^2\) mol\(^{-1}\)]
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5.
The electrical resistance of a column of 0.05 M KOH solution of area 0.5 cm\(^2\) and length 50 cm is 2.5 \(\times\) 10\(^4\) ohm. Calculate its molar conductivity.
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6.
Explain the Finkelstein reaction.
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