NCERT Solutions for Class 12 Physics Chapter 13: Nuclei

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Jasmine Grover

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NCERT Solutions for class 12 physics chapter 13 Nuclei are given in this article. Atomic Nucleus is the small, dense and central part of the Atom consisting of Protons, which are positively charged and Neutrons, which are electrically neutral containing more than 99.9% of the mass of an atom and are ten thousand times smaller than an atom.

Unit 8 Atoms and Nuclei along with Unit 7 Dual Nature of Radiation and Matter has a weightage of 12 marks in the CBSE Board examinations. NCERT Solutions Class 12 Physics Chapter 13 covers concepts of Mass-Energy and Nuclear Binding EnergyRadioactive Decay, and Nuclear Energy.

Download PDF: NCERT Solutions for Class 12 Physics Chapter 13


NCERT Solutions for Class 12 Physics Chapter 13

The NCERT solutions for class 12 physics chapter 13: Nuclei are given below.

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Class 12 Physics Chapter 13 Nuclei – Topics Covered

  • Atomic Mass Unit (amu): The unit used to express atomic masses is known as the atomic mass unit. It is defined as 1/12th of the mass of a Carbon atom (C12).
1 u = 1.660539 x 10-27 kg
  • Atomic number of an element refers to the number of protons that are present inside the nucleus of an atom of an element.
Atomic number = Number of protons = Number of electrons
  • Mass number of an element refers to the total number of protons and neutrons inside the atomic nucleus of the element.
Mass number = Number of protons + Number of neutrons = Number of electrons + Number of neutrons i.e. A = Z + N
  • Size of Nucleus: If R is the radius of the nucleus that has mass number A, then the size of the nucleus can be represented by:
\({4 \over 3} \pi R^3 \propto A => R \propto A^{1/3} => R = R_0A^{1 \over 3}\)
  • Radioactivity Decay Law: According to the Radioactive Decay law, the rate of decay of radioactive atoms at any instant is directly proportional to the number of atoms present at that instant.
\({dN \over dt} \propto N, {dN \over dt}=\ - \lambda N\)

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CBSE CLASS XII Related Questions

  • 1.
    Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).


      • 2.
        Draw a circuit diagram of a full-wave rectifier using p-n junction diodes. Explain its working and show the input-output waveforms.


          • 3.
            Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.


              • 4.
                Assertion (A) : The mass of a nucleus is less than the sum of the masses of the constituent nucleons. Reason (R) : Energy is absorbed when the nucleons are bound together to form a nucleus.

                  • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
                  • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                  • Assertion (A) is true, but Reason (R) is false.
                  • Both Assertion (A) and Reason (R) are false.

                • 5.
                  The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

                    • \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
                    • \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
                    • \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
                    • Zero

                  • 6.
                    Four independent waves are expressed as \[ (i)\; y_1=A_1\sin\omega t, \] \[ (ii)\; y_2=A_2\sin 2\omega t, \] \[ (iii)\; y_3=A_3\cos\omega t, \] \[ (iv)\; y_4=A_4\sin\left(\omega t+\frac{\pi}{3}\right) \] The interference between two of these waves is possible in

                      • (i) and (iii) only
                      • (iii) and (iv) only
                      • (i), (iii) and (iv) only
                      • All of them
                    CBSE CLASS XII Previous Year Papers

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